将字符串相乘以使其重复

print "SO"*5 

给了

SOSOSOSOSO

threading.enumerate()提供了对系统中所有Thread对象的访问，sys._current_frames()返回系统中所有线程的当前堆栈帧，因此将这两者结合起来，你会得到Java风格的堆栈转储:

def dumpstacks(signal, frame):
    id2name = dict([(th.ident, th.name) for th in threading.enumerate()])
    code = []
    for threadId, stack in sys._current_frames().items():
        code.append("\n# Thread: %s(%d)" % (id2name[threadId], threadId))
        for filename, lineno, name, line in traceback.extract_stack(stack):
            code.append('File: "%s", line %d, in %s' % (filename, lineno, name))
            if line:
                code.append("  %s" % (line.strip()))
    print "\n".join(code)

import signal
signal.signal(signal.SIGQUIT, dumpstacks)

在多线程python程序开始时执行此操作，您可以通过发送SIGQUIT随时访问线程的当前状态。你也可以选择信号。SIGUSR1或signal。sigusr2。

See

三元运算符

>>> 'ham' if True else 'spam'
'ham'
>>> 'ham' if False else 'spam'
'spam'

这是在2.5中添加的，在此之前你可以使用:

>>> True and 'ham' or 'spam'
'ham'
>>> False and 'ham' or 'spam'
'spam'

然而，如果你想要处理的值被认为是假的，有一个区别:

>>> [] if True else 'spam'
[]
>>> True and [] or 'spam'
'spam'

内置base64, zlib和rot13编解码器

字符串有编码和解码方法。通常这用于将str转换为unicode，反之亦然，例如u = s.c encode('utf8')。但还有其他一些方便的内置编解码器。使用zlib(和bz2)进行压缩和解压，无需显式导入:

>>> s = 'a' * 100
>>> s.encode('zlib')
'x\x9cKL\xa4=\x00\x00zG%\xe5'

类似地，你可以编码和解码base64:

>>> 'Hello world'.encode('base64')
'SGVsbG8gd29ybGQ=\n'
>>> 'SGVsbG8gd29ybGQ=\n'.decode('base64')
'Hello world'

当然，你也可以:

>>> 'Secret message'.encode('rot13')
'Frperg zrffntr'

可读正则表达式

在Python中，您可以将正则表达式拆分为多行，命名匹配并插入注释。

示例详细语法(来自Python):

>>> pattern = """
... ^                   # beginning of string
... M{0,4}              # thousands - 0 to 4 M's
... (CM|CD|D?C{0,3})    # hundreds - 900 (CM), 400 (CD), 0-300 (0 to 3 C's),
...                     #            or 500-800 (D, followed by 0 to 3 C's)
... (XC|XL|L?X{0,3})    # tens - 90 (XC), 40 (XL), 0-30 (0 to 3 X's),
...                     #        or 50-80 (L, followed by 0 to 3 X's)
... (IX|IV|V?I{0,3})    # ones - 9 (IX), 4 (IV), 0-3 (0 to 3 I's),
...                     #        or 5-8 (V, followed by 0 to 3 I's)
... $                   # end of string
... """
>>> re.search(pattern, 'M', re.VERBOSE)

命名匹配示例(摘自正则表达式HOWTO)

>>> p = re.compile(r'(?P<word>\b\w+\b)')
>>> m = p.search( '(((( Lots of punctuation )))' )
>>> m.group('word')
'Lots'

由于字符串字面值的串联，你也可以在不使用re.VERBOSE的情况下详细地编写一个正则表达式。

>>> pattern = (
...     "^"                 # beginning of string
...     "M{0,4}"            # thousands - 0 to 4 M's
...     "(CM|CD|D?C{0,3})"  # hundreds - 900 (CM), 400 (CD), 0-300 (0 to 3 C's),
...                         #            or 500-800 (D, followed by 0 to 3 C's)
...     "(XC|XL|L?X{0,3})"  # tens - 90 (XC), 40 (XL), 0-30 (0 to 3 X's),
...                         #        or 50-80 (L, followed by 0 to 3 X's)
...     "(IX|IV|V?I{0,3})"  # ones - 9 (IX), 4 (IV), 0-3 (0 to 3 I's),
...                         #        or 5-8 (V, followed by 0 to 3 I's)
...     "$"                 # end of string
... )
>>> print pattern
"^M{0,4}(CM|CD|D?C{0,3})(XC|XL|L?X{0,3})(IX|IV|V?I{0,3})$"

小心可变默认参数

>>> def foo(x=[]):
...     x.append(1)
...     print x
... 
>>> foo()
[1]
>>> foo()
[1, 1]
>>> foo()
[1, 1, 1]

相反，你应该使用一个表示“not given”的哨兵值，并将其替换为你想要的默认值:

>>> def foo(x=None):
...     if x is None:
...         x = []
...     x.append(1)
...     print x
>>> foo()
[1]
>>> foo()
[1]