是否有一种更简单的方法来复制文件夹及其所有内容,而无需手动执行一系列的fs。readir, fs。readfile, fs。writefile递归?

我只是想知道我是否错过了一个函数,理想情况下是这样工作的:

fs.copy("/path/to/source/folder", "/path/to/destination/folder");

关于这个历史问题。注意fs。Cp和fs。cpSync可以递归复制文件夹,在Node v16+中可用


当前回答

我知道这里已经有很多答案了,但是没有一个答案是简单的。

关于fs-exra官方文档,您可以非常轻松地完成。

const fs = require('fs-extra')

// Copy file
fs.copySync('/tmp/myfile', '/tmp/mynewfile')

// Copy directory, even if it has subdirectories or files
fs.copySync('/tmp/mydir', '/tmp/mynewdir')

其他回答

我是这样做的:

let fs = require('fs');
let path = require('path');

然后:

let filePath = // Your file path

let fileList = []
    var walkSync = function(filePath, filelist)
    {
        let files = fs.readdirSync(filePath);
        filelist = filelist || [];
        files.forEach(function(file)
        {
            if (fs.statSync(path.join(filePath, file)).isDirectory())
            {
                filelist = walkSync(path.join(filePath, file), filelist);
            }
            else
            {
                filelist.push(path.join(filePath, file));
            }
        });

        // Ignore hidden files
        filelist = filelist.filter(item => !(/(^|\/)\.[^\/\.]/g).test(item));

        return filelist;
    };

然后调用该方法:

This.walkSync(filePath, fileList)

对于没有fs的旧节点版本。cp,我在紧要关头使用这个来避免需要第三方库:

const fs = require("fs").promises;
const path = require("path");

const cp = async (src, dest) => {
  const lstat = await fs.lstat(src).catch(err => false);

  if (!lstat) {
    return;
  }
  else if (await lstat.isFile()) {
    await fs.copyFile(src, dest);
  }
  else if (await lstat.isDirectory()) {
    await fs.mkdir(dest).catch(err => {});

    for (const f of await fs.readdir(src)) {
      await cp(path.join(src, f), path.join(dest, f));
    }
  }
};

// sample usage
(async () => {
  const src = "foo";
  const dst = "bar";

  for (const f of await fs.readdir(src)) {
    await cp(path.join(src, f), path.join(dst, f));
  }
})();

相对于现有答案的优势(或区别):

异步 忽略符号链接 如果目录已经存在,则不抛出(如果不需要,则不捕获mkdir抛出) 相当简洁的

解决这个问题最简单的方法是只使用'fs'和'Path'模块和一些逻辑…

如果你只是想设置版本号,根文件夹中的所有文件都复制新名称,即" var v = '您的目录名'"

在文件名的前缀中添加带有文件名的内容。

var fs = require('fs-extra');
var path = require('path');

var c = 0;
var i = 0;
var v = "1.0.2";
var copyCounter = 0;
var directoryCounter = 0;
var directoryMakerCounter = 0;
var recursionCounter = -1;
var Flag = false;
var directoryPath = [];
var directoryName = [];
var directoryFileName = [];
var fileName;
var directoryNameStorer;
var dc = 0;
var route;

if (!fs.existsSync(v)) {
    fs.mkdirSync(v);
}

var basePath = path.join(__dirname, v);


function walk(dir) {

    fs.readdir(dir, function(err, items) {

        items.forEach(function(file) {

            file = path.resolve(dir, file);

            fs.stat(file, function(err, stat) {

                if(stat && stat.isDirectory()) {
                    directoryNameStorer = path.basename(file);
                    route = file;
                    route = route.replace("gd", v);

                    directoryFileName[directoryCounter] = route;
                    directoryPath[directoryCounter] = file;
                    directoryName[directoryCounter] = directoryNameStorer;

                    directoryCounter++;
                    dc++;

                    if (!fs.existsSync(basePath + "/" + directoryName[directoryMakerCounter])) {
                        fs.mkdirSync(directoryFileName[directoryMakerCounter]);
                        directoryMakerCounter++;
                    }
                }
                else {
                    fileName = path.basename(file);
                    if(recursionCounter >= 0) {
                        fs.copyFileSync(file, directoryFileName[recursionCounter] + "/" + v + "_" + fileName, err => {
                            if(err) return console.error(err);
                        });
                        copyCounter++;
                    }
                    else {
                        fs.copyFileSync(file, v + "/" + v + "_" + fileName, err => {
                            if(err) return console.error(err);
                        });
                        copyCounter++;
                    }
                }
                if(copyCounter + dc == items.length && directoryCounter > 0 && recursionCounter < directoryMakerCounter-1) {
                    console.log("COPY COUNTER:             " + copyCounter);
                    console.log("DC COUNTER:               " + dc);
                    recursionCounter++;
                    dc = 0;
                    copyCounter = 0;
                    console.log("ITEM DOT LENGTH:          " + items.length);
                    console.log("RECURSION COUNTER:        " + recursionCounter);
                    console.log("DIRECOTRY MAKER COUNTER:  " + directoryMakerCounter);
                    console.log(": START RECURSION:        " + directoryPath[recursionCounter]);
                    walk(directoryPath[recursionCounter]); //recursive call to copy sub-folder
                }
            })
        })
    });
}

walk('./gd', function(err, data) { // Just pass the root directory which you want to copy
    if(err)
        throw err;
    console.log("done");
})

由于我只是构建一个简单的Node.js脚本,我不希望脚本的用户需要导入一堆外部模块和依赖项,所以我开始思考,并从Bash shell中搜索运行命令。

这个Node.js代码片段递归地复制了一个名为node-webkit的文件夹。应用程序到一个名为build的文件夹:

child = exec("cp -r node-webkit.app build", function(error, stdout, stderr) {
    sys.print("stdout: " + stdout);
    sys.print("stderr: " + stderr);
    if(error !== null) {
        console.log("exec error: " + error);
    } else {

    }
});

感谢dzone的兰斯·波拉德让我开始。

上面的代码片段仅限于基于unix的平台,如macOS和Linux,但类似的技术也适用于Windows。

使用 shelljs

npm i -D shelljs

const bash = require('shelljs');
bash.cp("-rf", "/path/to/source/folder", "/path/to/destination/folder");