是否有一种更简单的方法来复制文件夹及其所有内容,而无需手动执行一系列的fs。readir, fs。readfile, fs。writefile递归?

我只是想知道我是否错过了一个函数,理想情况下是这样工作的:

fs.copy("/path/to/source/folder", "/path/to/destination/folder");

关于这个历史问题。注意fs。Cp和fs。cpSync可以递归复制文件夹,在Node v16+中可用


当前回答

对于没有fs的旧节点版本。cp,我在紧要关头使用这个来避免需要第三方库:

const fs = require("fs").promises;
const path = require("path");

const cp = async (src, dest) => {
  const lstat = await fs.lstat(src).catch(err => false);

  if (!lstat) {
    return;
  }
  else if (await lstat.isFile()) {
    await fs.copyFile(src, dest);
  }
  else if (await lstat.isDirectory()) {
    await fs.mkdir(dest).catch(err => {});

    for (const f of await fs.readdir(src)) {
      await cp(path.join(src, f), path.join(dest, f));
    }
  }
};

// sample usage
(async () => {
  const src = "foo";
  const dst = "bar";

  for (const f of await fs.readdir(src)) {
    await cp(path.join(src, f), path.join(dst, f));
  }
})();

相对于现有答案的优势(或区别):

异步 忽略符号链接 如果目录已经存在,则不抛出(如果不需要,则不捕获mkdir抛出) 相当简洁的

其他回答

有一些模块支持复制文件夹及其内容。最流行的是wrench.js:

// Deep-copy an existing directory
wrench.copyDirSyncRecursive('directory_to_copy', 'location_where_copy_should_end_up');

一个替代方案是node-fs-extra:

fs.copy('/tmp/mydir', '/tmp/mynewdir', function (err) {
  if (err) {
    console.error(err);
  } else {
    console.log("success!");
  }
}); // Copies directory, even if it has subdirectories or files

使用 shelljs

npm i -D shelljs

const bash = require('shelljs');
bash.cp("-rf", "/path/to/source/folder", "/path/to/destination/folder");

这段代码可以很好地工作,递归地将任何文件夹复制到任何位置。但它只适用于Windows。

var child = require("child_process");
function copySync(from, to){
    from = from.replace(/\//gim, "\\");
    to = to.replace(/\//gim, "\\");
    child.exec("xcopy /y /q \"" + from + "\\*\" \"" + to + "\\\"");
}

它非常适合我的基于文本的游戏去创造新玩家。

内联版本

node -e "const fs=require('fs');const p=require('path');function copy(src, dest) {if (!fs.existsSync(src)) {return;} if (fs.statSync(src).isFile()) {fs.copyFileSync(src, dest);}else{fs.mkdirSync(dest, {recursive: true});fs.readdirSync(src).forEach(f=>copy(p.join(src, f), p.join(dest, f)));}}const args=Array.from(process.argv); copy(args[args.length-2], args[args.length-1]);" dist temp\dest

或者节点16.x+

node -e "const fs=require('fs');const args=Array.from(process.argv); fs.cpSync(args[args.length-2], args[args.length-1], {recursive: true});" 

在“节点14.20.0”上测试,但假设它在节点10.x上工作?

来自user8894303和pen的回答:https://stackoverflow.com/a/52338335/458321

如果在包中使用,请务必转义引号。json脚本

package.json:

  "scripts": {
    "rmrf": "node -e \"const fs=require('fs/promises');const args=Array.from(process.argv); Promise.allSettled(args.map(a => fs.rm(a, { recursive: true, force: true })));\"",
    "cp": "node -e \"const fs=require('fs');const args=Array.from(process.argv);if (args.length>2){ fs.cpSync(args[args.length-2], args[args.length-1], {recursive: true});}else{console.log('args missing', args);}\""
    "copy": "node -e \"const fs=require('fs');const p=require('path');function copy(src, dest) {if (!fs.existsSync(src)) {return;} if (fs.statSync(src).isFile()) {fs.copyFileSync(src, dest);}else{fs.mkdirSync(dest, {recursive: true});fs.readdirSync(src).forEach(f=>copy(p.join(src, f), p.join(dest, f)));}}const args=Array.from(process.argv);if (args.length>2){copy(args[args.length-2], args[args.length-1]);}else{console.log('args missing', args);}\"",
    "mkdir": "node -e \"const fs=require('fs');const args=Array.from(process.argv);fs.mkdirSync(args[args.length-1],{recursive:true});\"",
    "clean": "npm run rmrf -- temp && npm run mkdir -- temp && npm run copy -- dist temp"
  }

注:RMRF脚本需要14.20节点。X还是12.20.x?

奖金:

deno eval "import { existsSync, mkdirSync, copyFileSync, readdirSync, statSync } from 'node:fs';import { join } from 'node:path';function copy(src, dest) {if (!existsSync(src)) {return;} if (statSync(src).isFile()) {copyFileSync(src, dest);}else{mkdirSync(dest, {recursive: true});readdirSync(src).forEach(f=>copy(join(src, f), join(dest, f)));}}const args=Array.from(Deno.args);copy(args[0], args[1]);" dist temp\dest -- --allow-read --allow-write

Deno支持-> NPM I Deno -bin支持节点中的Deno -bin

是的,ncp很酷…

你可能想要/应该承诺它的功能,让它超级酷。当你这样做的时候,把它添加到一个工具文件中以重复使用它。

下面是一个工作版本,它是异步的,并使用承诺。


文件index.js

const {copyFolder} = require('./tools/');

return copyFolder(
    yourSourcePath,
    yourDestinationPath
)
.then(() => {
    console.log('-> Backup completed.')
}) .catch((err) => {
    console.log("-> [ERR] Could not copy the folder: ", err);
})

文件tools.js

const ncp = require("ncp");

/**
 * Promise Version of ncp.ncp()
 *
 * This function promisifies ncp.ncp().
 * We take the asynchronous function ncp.ncp() with
 * callback semantics and derive from it a new function with
 * promise semantics.
 */
ncp.ncpAsync = function (sourcePath, destinationPath) {
  return new Promise(function (resolve, reject) {
      try {
          ncp.ncp(sourcePath, destinationPath, function(err){
              if (err) reject(err); else resolve();
          });
      } catch (err) {
          reject(err);
      }
  });
};

/**
 * Utility function to copy folders asynchronously using
 * the Promise returned by ncp.ncp().
 */
const copyFolder = (sourcePath, destinationPath) => {
    return ncp.ncpAsync(sourcePath, destinationPath, function (err) {
        if (err) {
            return console.error(err);
        }
    });
}
module.exports.copyFolder = copyFolder;