是否有一种内置的方法来测量Windows命令行上命令的执行时间?
当前回答
在Perl安装了可用的雇佣解决方案后,运行:
C:\BATCH>time.pl "echo Fine result"
0.01063
Fine result
STDERR出现在被测量的秒之前
#!/usr/bin/perl -w
use Time::HiRes qw();
my $T0 = [ Time::HiRes::gettimeofday ];
my $stdout = `@ARGV`;
my $time_elapsed = Time::HiRes::tv_interval( $T0 );
print $time_elapsed, "\n";
print $stdout;
其他回答
The following script uses only "cmd.exe" and outputs the number of milliseconds from the time a pipeline is created to the time that the process preceding the script exits. i.e., Type your command, and pipe the to the script. Example: "timeout 3 | runtime.cmd" should yield something like "2990." If you need both the runtime output and the stdin output, redirect stdin before the pipe - ex: "dir /s 1>temp.txt | runtime.cmd" would dump the output of the "dir" command to "temp.txt" and would print the runtime to the console.
:: --- runtime.cmd ----
@echo off
setlocal enabledelayedexpansion
:: find target for recursive calls
if not "%1"=="" (
shift /1
goto :%1
exit /b
)
:: set pipeline initialization time
set t1=%time%
:: wait for stdin
more > nul
:: set time at which stdin was ready
set t2=!time!
::parse t1
set t1=!t1::= !
set t1=!t1:.= !
set t1=!t1: 0= !
:: parse t2
set t2=!t2::= !
set t2=!t2:.= !
set t2=!t2: 0= !
:: calc difference
pushd %~dp0
for /f %%i in ('%0 calc !t1!') do for /f %%j in ('%0 calc !t2!') do (
set /a t=%%j-%%i
echo !t!
)
popd
exit /b
goto :eof
:calc
set /a t=(%1*(3600*1000))+(%2*(60*1000))+(%3*1000)+(%4)
echo !t!
goto :eof
endlocal
@echo off & setlocal
set start=%time%
REM Do stuff to be timed here.
REM Alternatively, uncomment the line below to be able to
REM pass in the command to be timed when running this script.
REM cmd /c %*
set end=%time%
REM Calculate time taken in seconds, to the hundredth of a second.
REM Assumes start time and end time will be on the same day.
set options="tokens=1-4 delims=:."
for /f %options% %%a in ("%start%") do (
set /a start_s="(100%%a %% 100)*3600 + (100%%b %% 100)*60 + (100%%c %% 100)"
set /a start_hs=100%%d %% 100
)
for /f %options% %%a in ("%end%") do (
set /a end_s="(100%%a %% 100)*3600 + (100%%b %% 100)*60 + (100%%c %% 100)"
set /a end_hs=100%%d %% 100
)
set /a s=%end_s%-%start_s%
set /a hs=%end_hs%-%start_hs%
if %hs% lss 0 (
set /a s=%s%-1
set /a hs=100%hs%
)
if 1%hs% lss 100 set hs=0%hs%
echo.
echo Time taken: %s%.%hs% secs
echo.
不像Unix上的一些功能那样优雅,但是创建一个cmd文件,看起来像这样:
@echo off
time < nul
yourexecutable.exe > c:\temp\output.txt
time < nul
rem on newer windows system you can try time /T
将显示开始和停止时间,如下所示:
The current time is: 10:31:57.92
Enter the new time:
The current time is: 10:32:05.94
Enter the new time:
这是对Luke Sampson的nice timecmd.bat的评论/编辑并回复
出于某种原因,这只给我整秒的输出…这对我来说毫无用处。我的意思是,我运行timecmd pause,结果总是1秒,2秒,4秒……甚至是0.00秒!Windows 7。- Camilo Martin 13年9月25日16:00
在某些配置上,分隔符可能不同。以下变化至少应该涵盖大多数西方国家。
set options="tokens=1-4 delims=:,." (added comma)
在添加','后,%time%毫秒在我的系统上工作
(*因为网站不允许匿名评论,没有很好地跟踪身份,即使我总是使用相同的客人电子邮件,结合ipv6 ip和浏览器指纹应该足以唯一识别没有密码)
呵呵,最简单的解决办法可能是:
echo %time%
YourApp.exe
echo %time%
这适用于所有开箱即用的Windows。
在应用程序使用控制台输出的情况下,将开始时间存储在临时变量中可能会很方便:
set startTime=%time%
YourApp.exe
echo Start Time: %startTime%
echo Finish Time: %time%
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