是否有一种内置的方法来测量Windows命令行上命令的执行时间?
当前回答
@echo off & setlocal
set start=%time%
REM Do stuff to be timed here.
REM Alternatively, uncomment the line below to be able to
REM pass in the command to be timed when running this script.
REM cmd /c %*
set end=%time%
REM Calculate time taken in seconds, to the hundredth of a second.
REM Assumes start time and end time will be on the same day.
set options="tokens=1-4 delims=:."
for /f %options% %%a in ("%start%") do (
set /a start_s="(100%%a %% 100)*3600 + (100%%b %% 100)*60 + (100%%c %% 100)"
set /a start_hs=100%%d %% 100
)
for /f %options% %%a in ("%end%") do (
set /a end_s="(100%%a %% 100)*3600 + (100%%b %% 100)*60 + (100%%c %% 100)"
set /a end_hs=100%%d %% 100
)
set /a s=%end_s%-%start_s%
set /a hs=%end_hs%-%start_hs%
if %hs% lss 0 (
set /a s=%s%-1
set /a hs=100%hs%
)
if 1%hs% lss 100 set hs=0%hs%
echo.
echo Time taken: %s%.%hs% secs
echo.
其他回答
在Perl安装了可用的雇佣解决方案后,运行:
C:\BATCH>time.pl "echo Fine result"
0.01063
Fine result
STDERR出现在被测量的秒之前
#!/usr/bin/perl -w
use Time::HiRes qw();
my $T0 = [ Time::HiRes::gettimeofday ];
my $stdout = `@ARGV`;
my $time_elapsed = Time::HiRes::tv_interval( $T0 );
print $time_elapsed, "\n";
print $stdout;
不像Unix上的一些功能那样优雅,但是创建一个cmd文件,看起来像这样:
@echo off
time < nul
yourexecutable.exe > c:\temp\output.txt
time < nul
rem on newer windows system you can try time /T
将显示开始和停止时间,如下所示:
The current time is: 10:31:57.92
Enter the new time:
The current time is: 10:32:05.94
Enter the new time:
driblio的答案可以短一点(虽然可读性不高)
@echo off
:: Calculate the start timestamp
set _time=%time%
set /a _hours=100%_time:~0,2%%%100,_min=100%_time:~3,2%%%100,_sec=100%_time:~6,2%%%100,_cs=%_time:~9,2%
set /a _started=_hours*60*60*100+_min*60*100+_sec*100+_cs
:: yourCommandHere
:: Calculate the difference in cSeconds
set _time=%time%
set /a _hours=100%_time:~0,2%%%100,_min=100%_time:~3,2%%%100,_sec=100%_time:~6,2%%%100,_cs=%_time:~9,2%
set /a _duration=_hours*60*60*100+_min*60*100+_sec*100+_cs-_started
:: Populate variables for rendering (100+ needed for padding)
set /a _hours=_duration/60/60/100,_min=100+_duration/60/100%%60,_sec=100+(_duration/100%%60%%60),_cs=100+_duration%%100
echo Done at: %_time% took : %_hours%:%_min:~-2%:%_sec:~-2%.%_cs:~-2%
::prints something like:
::Done at: 12:37:53,70 took: 0:02:03.55
根据Luke Sampson的评论,这个版本是八进制安全的,尽管任务应该在24小时内完成。
下面是我的方法,没有转换和没有ms。它有助于确定编码持续时间(限制在24小时内):
@echo off
:start
REM Start time storage
set ST=%time%
echo Process started at %ST%
echo.
echo.
REM Your commands
REM Your commands
REM Your commands
:end
REM Start Time Definition
for /f "tokens=1-3 delims=:" %%a in ("%ST%") do set /a h1=%%a & set /a m1=%%b & set /a s1=%%c
REM End Time Definition
for /f "tokens=1-3 delims=:" %%a in ("%TIME%") do set /a h2=%%a & set /a m2=%%b & set /a s2=%%c
REM Difference
set /a h3=%h2%-%h1% & set /a m3=%m2%-%m1% & set /a s3=%s2%-%s1%
REM Time Adjustment
if %h3% LSS 0 set /a h3=%h3%+24
if %m3% LSS 0 set /a m3=%m3%+60 & set /a h3=%h3%-1
if %s3% LSS 0 set /a s3=%s3%+60 & set /a m3=%m3%-1
echo Start : %ST%
echo End : %time%
echo.
echo Total : %h3%:%m3%:%s3%
echo.
pause
如果你打开了一个命令窗口并手动调用命令,你可以在每个提示符上显示时间戳,例如:
prompt $d $t $_$P$G
它会给你这样的东西:
23.03.2009 15:45:50 77 C: \ >
如果你有一个小的批处理脚本来执行你的命令,在每个命令之前有一个空行,例如。
(空行) myCommand.exe (下一行空) myCommand2.exe
根据提示符中的时间信息,可以计算出每条命令的执行时间。最好的可能是管道输出到一个文本文件进行进一步分析:
MyBatchFile.bat > output.txt
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