是否有一种内置的方法来测量Windows命令行上命令的执行时间?
当前回答
PowerShell为此提供了一个cmdlet,称为Measure-Command。您必须确保在运行PowerShell的机器上是可用的。
PS> Measure-Command { echo hi }
Days : 0
Hours : 0
Minutes : 0
Seconds : 0
Milliseconds : 0
Ticks : 1318
TotalDays : 1.52546296296296E-09
TotalHours : 3.66111111111111E-08
TotalMinutes : 2.19666666666667E-06
TotalSeconds : 0.0001318
TotalMilliseconds : 0.1318
Measure-Command捕获命令的输出。你可以使用Out-Default将输出重定向回控制台:
PS> Measure-Command { echo hi | Out-Default }
hi
Days : 0
...
正如Makotoe所评论的那样,Measure-Command返回一个TimeSpan对象,因此测量的时间被打印为一堆字段。你可以使用ToString()将对象格式化为时间戳字符串:
PS> (Measure-Command { echo hi | Out-Default }).ToString()
hi
00:00:00.0001318
如果Measure-Command中的命令改变了控制台文本的颜色,使用[console]::ResetColor()将其重置为正常。
其他回答
The following script uses only "cmd.exe" and outputs the number of milliseconds from the time a pipeline is created to the time that the process preceding the script exits. i.e., Type your command, and pipe the to the script. Example: "timeout 3 | runtime.cmd" should yield something like "2990." If you need both the runtime output and the stdin output, redirect stdin before the pipe - ex: "dir /s 1>temp.txt | runtime.cmd" would dump the output of the "dir" command to "temp.txt" and would print the runtime to the console.
:: --- runtime.cmd ----
@echo off
setlocal enabledelayedexpansion
:: find target for recursive calls
if not "%1"=="" (
shift /1
goto :%1
exit /b
)
:: set pipeline initialization time
set t1=%time%
:: wait for stdin
more > nul
:: set time at which stdin was ready
set t2=!time!
::parse t1
set t1=!t1::= !
set t1=!t1:.= !
set t1=!t1: 0= !
:: parse t2
set t2=!t2::= !
set t2=!t2:.= !
set t2=!t2: 0= !
:: calc difference
pushd %~dp0
for /f %%i in ('%0 calc !t1!') do for /f %%j in ('%0 calc !t2!') do (
set /a t=%%j-%%i
echo !t!
)
popd
exit /b
goto :eof
:calc
set /a t=(%1*(3600*1000))+(%2*(60*1000))+(%3*1000)+(%4)
echo !t!
goto :eof
endlocal
driblio的答案可以短一点(虽然可读性不高)
@echo off
:: Calculate the start timestamp
set _time=%time%
set /a _hours=100%_time:~0,2%%%100,_min=100%_time:~3,2%%%100,_sec=100%_time:~6,2%%%100,_cs=%_time:~9,2%
set /a _started=_hours*60*60*100+_min*60*100+_sec*100+_cs
:: yourCommandHere
:: Calculate the difference in cSeconds
set _time=%time%
set /a _hours=100%_time:~0,2%%%100,_min=100%_time:~3,2%%%100,_sec=100%_time:~6,2%%%100,_cs=%_time:~9,2%
set /a _duration=_hours*60*60*100+_min*60*100+_sec*100+_cs-_started
:: Populate variables for rendering (100+ needed for padding)
set /a _hours=_duration/60/60/100,_min=100+_duration/60/100%%60,_sec=100+(_duration/100%%60%%60),_cs=100+_duration%%100
echo Done at: %_time% took : %_hours%:%_min:~-2%:%_sec:~-2%.%_cs:~-2%
::prints something like:
::Done at: 12:37:53,70 took: 0:02:03.55
根据Luke Sampson的评论,这个版本是八进制安全的,尽管任务应该在24小时内完成。
不像Unix上的一些功能那样优雅,但是创建一个cmd文件,看起来像这样:
@echo off
time < nul
yourexecutable.exe > c:\temp\output.txt
time < nul
rem on newer windows system you can try time /T
将显示开始和停止时间,如下所示:
The current time is: 10:31:57.92
Enter the new time:
The current time is: 10:32:05.94
Enter the new time:
还有TimeMem(2012年3月):
这是一个Windows实用程序,执行一个程序并显示它 执行时间、内存使用和IO统计信息。这与 Unix time实用程序的功能。
@echo off & setlocal
set start=%time%
REM Do stuff to be timed here.
REM Alternatively, uncomment the line below to be able to
REM pass in the command to be timed when running this script.
REM cmd /c %*
set end=%time%
REM Calculate time taken in seconds, to the hundredth of a second.
REM Assumes start time and end time will be on the same day.
set options="tokens=1-4 delims=:."
for /f %options% %%a in ("%start%") do (
set /a start_s="(100%%a %% 100)*3600 + (100%%b %% 100)*60 + (100%%c %% 100)"
set /a start_hs=100%%d %% 100
)
for /f %options% %%a in ("%end%") do (
set /a end_s="(100%%a %% 100)*3600 + (100%%b %% 100)*60 + (100%%c %% 100)"
set /a end_hs=100%%d %% 100
)
set /a s=%end_s%-%start_s%
set /a hs=%end_hs%-%start_hs%
if %hs% lss 0 (
set /a s=%s%-1
set /a hs=100%hs%
)
if 1%hs% lss 100 set hs=0%hs%
echo.
echo Time taken: %s%.%hs% secs
echo.
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