因为其他人建议安装像免费软件和PowerShell这样的东西，你也可以安装Cygwin，它可以让你访问许多基本的Unix命令，比如time:

abe@abe-PC:~$ time sleep 5

real    0m5.012s
user    0m0.000s
sys 0m0.000s

不知道Cygwin增加了多少开销。

如果您使用的是Windows 2003(注意不支持Windows server 2008及更高版本)，您可以使用Windows server 2003资源工具包，其中包含显示详细执行统计信息的time .exe。这里有一个例子，计时命令“timeit -?”：

C:\>timeit timeit -?
Invalid switch -?
Usage: TIMEIT [-f filename] [-a] [-c] [-i] [-d] [-s] [-t] [-k keyname | -r keyname] [-m mask] [commandline...]
where:        -f specifies the name of the database file where TIMEIT
                 keeps a history of previous timings.  Default is .\timeit.dat
              -k specifies the keyname to use for this timing run
              -r specifies the keyname to remove from the database.  If
                 keyname is followed by a comma and a number then it will
                 remove the slowest (positive number) or fastest (negative)
                 times for that keyname.
              -a specifies that timeit should display average of all timings
                 for the specified key.
              -i specifies to ignore non-zero return codes from program
              -d specifies to show detail for average
              -s specifies to suppress system wide counters
              -t specifies to tabular output
              -c specifies to force a resort of the data base
              -m specifies the processor affinity mask

Version Number:   Windows NT 5.2 (Build 3790)
Exit Time:        7:38 am, Wednesday, April 15 2009
Elapsed Time:     0:00:00.000
Process Time:     0:00:00.015
System Calls:     731
Context Switches: 299
Page Faults:      515
Bytes Read:       0
Bytes Written:    0
Bytes Other:      298

您可以在Windows 2003资源工具包中获得TimeIt。它不能从微软下载中心直接下载，但仍然可以从archive.org - Windows Server 2003资源工具包工具中获得。

在程序所在的目录中，键入记事本mytimer.bat，单击“是”创建一个新文件。 粘贴下面的代码，用你的程序替换YourApp.exe，然后保存。 @echo掉 日期/ t 时间/ t YourApp.exe 日期/ t 时间/ t 在命令行中输入mytimer.bat，然后按Enter。

这是凯西对答案的扩展。关于使用PowerShell中的Measure-Command:

您可以从标准的命令提示符调用PowerShell，如下所示: powershell -Command "Measure-Command {echo hi}" 这将消耗标准输出，但你可以通过从PowerShell添加| Out-Default来防止这种情况: 测量命令{echo hi | Out-Default} 或者从命令提示符: powershell -Command "Measure-Command {echo hi | Out-Default}"

当然，您可以自由地将其包装在脚本文件*中。Ps1或*.bat。

@echo off & setlocal

set start=%time%

REM Do stuff to be timed here.
REM Alternatively, uncomment the line below to be able to
REM pass in the command to be timed when running this script.
REM cmd /c %*

set end=%time%

REM Calculate time taken in seconds, to the hundredth of a second.
REM Assumes start time and end time will be on the same day.

set options="tokens=1-4 delims=:."

for /f %options% %%a in ("%start%") do (
    set /a start_s="(100%%a %% 100)*3600 + (100%%b %% 100)*60 + (100%%c %% 100)"
    set /a start_hs=100%%d %% 100
)

for /f %options% %%a in ("%end%") do (
    set /a end_s="(100%%a %% 100)*3600 + (100%%b %% 100)*60 + (100%%c %% 100)"
    set /a end_hs=100%%d %% 100
)

set /a s=%end_s%-%start_s%
set /a hs=%end_hs%-%start_hs%

if %hs% lss 0 (
    set /a s=%s%-1
    set /a hs=100%hs%
)
if 1%hs% lss 100 set hs=0%hs%

echo.
echo  Time taken: %s%.%hs% secs
echo.

下面的脚本模拟*nix纪元时间，但它是本地和区域性的。它应该处理日历边缘情况，包括闰年。如果Cygwin可用，则可以通过指定Cygwin选项来比较epoch值。

我在EST，报告的差异是4小时，这是相对正确的。有一些有趣的解决方案可以删除TZ和区域依赖，但我注意到没有什么微不足道的。

@ECHO off
SETLOCAL EnableDelayedExpansion

::
::  Emulates local epoch seconds
::

:: Call passing local date and time
CALL :SECONDS "%DATE%" "%TIME%"
IF !SECONDS! LEQ 0 GOTO END

:: Not testing - print and exit
IF NOT "%~1"=="cygwin" (
    ECHO !SECONDS!
    GOTO END
)

:: Call on Cygwin to get epoch time
FOR /F %%c IN ('C:\cygwin\bin\date +%%s') DO SET EPOCH=%%c

:: Show the results
ECHO Local Seconds: !SECONDS!
ECHO Epoch Seconds: !EPOCH!

:: Calculate difference between script and Cygwin
SET /A HOURS=(!EPOCH!-!SECONDS!)/3600
SET /A FRAC=(!EPOCH!-!SECONDS!)%%3600

:: Delta hours shown reflect TZ
ECHO Delta Hours: !HOURS! Remainder: !FRAC!

GOTO END

:SECONDS
SETLOCAL  EnableDelayedExpansion

    :: Expecting values from caller
    SET DATE=%~1
    SET TIME=%~2

    :: Emulate Unix epoch time without considering TZ
    SET "SINCE_YEAR=1970"

    :: Regional constraint! Expecting date and time in the following formats:
    ::   Sun 03/08/2015   Day MM/DD/YYYY
    ::   20:04:53.64         HH:MM:SS
    SET VALID_DATE=0
    ECHO !DATE! | FINDSTR /R /C:"^... [0-9 ][0-9]/[0-9 ][0-9]/[0-9][0-9][0-9][0-9]" > nul && SET VALID_DATE=1
    SET VALID_TIME=0
    ECHO !TIME! | FINDSTR /R /C:"^[0-9 ][0-9]:[0-9 ][0-9]:[0-9 ][0-9]" > nul && SET VALID_TIME=1
    IF NOT "!VALID_DATE!!VALID_TIME!"=="11" (
        IF !VALID_DATE! EQU 0  ECHO Unsupported Date value: !DATE! 1>&2
        IF !VALID_TIME! EQU 0  ECHO Unsupported Time value: !TIME! 1>&2
        SET SECONDS=0
        GOTO SECONDS_END
    )

    :: Parse values
    SET "YYYY=!DATE:~10,4!"
    SET "MM=!DATE:~4,2!"
    SET "DD=!DATE:~7,2!"
    SET "HH=!TIME:~0,2!"
    SET "NN=!TIME:~3,2!"
    SET "SS=!TIME:~6,2!"
    SET /A YEARS=!YYYY!-!SINCE_YEAR!
    SET /A DAYS=!YEARS!*365

    :: Bump year if after February  - want leading zeroes for this test
    IF "!MM!!DD!" GEQ "0301" SET /A YEARS+=1

    :: Remove leading zeros that can cause octet probs for SET /A
    FOR %%r IN (MM,DD,HH,NN,SS) DO (
        SET "v=%%r"
        SET "t=!%%r!"
        SET /A N=!t:~0,1!0
        IF 0 EQU !N! SET "!v!=!t:~1!"
    )

    :: Increase days according to number of leap years
    SET /A DAYS+=(!YEARS!+3)/4-(!SINCE_YEAR!%%4+3)/4

    :: Increase days by preceding months of current year
    FOR %%n IN (31:1,28:2,31:3,30:4,31:5,30:6,31:7,31:8,30:9,31:10,30:11) DO (
        SET "n=%%n"
        IF !MM! GTR !n:~3! SET /A DAYS+=!n:~0,2!
    )

    :: Multiply and add it all together
    SET /A SECONDS=(!DAYS!+!DD!-1)*86400+!HH!*3600+!NN!*60+!SS!

:SECONDS_END
ENDLOCAL & SET "SECONDS=%SECONDS%"
GOTO :EOF

:END
ENDLOCAL