是否有一种内置的方法来测量Windows命令行上命令的执行时间?
当前回答
我的代码为您提供以毫秒为单位的运行时间,最高可达24小时,它是地区不敏感的,如果代码运行到午夜,则为负值。它使用延迟扩展,应该保存在cmd/bat文件中。
代码之前:
SETLOCAL EnableDelayedExpansion
for /f "tokens=2 delims==" %%I in ('wmic os get localdatetime /format:list') do set t=%%I
set /a t1 = %t:~8,1%*36000 + %t:~9,1%*3600 + %t:~10,1%*600 + %t:~11,1%*60 + %t:~12,1%*10 + %t:~13,1% && set t1=!t1!%t:~15,3%
代码之后:
for /f "tokens=2 delims==" %%I in ('wmic os get localdatetime /format:list') do set t=%%I
set /a t2 = %t:~8,1%*36000 + %t:~9,1%*3600 + %t:~10,1%*600 + %t:~11,1%*60 + %t:~12,1%*10 + %t:~13,1% && set t2=!t2!%t:~15,3%
set /a t2-=t1 && if !t2! lss 0 set /a t2+=24*3600000
如果你想让运行时间以HH:mm:ss为单位。000格式,添加:
set /a "h=t2/3600000,t2%%=3600000,m=t2/60000,t2%%=60000" && set t2=00000!t2!&& set t2=!t2:~-5!
if %h% leq 9 (set h=0%h%) && if %m% leq 9 (set m=0%m%)
set t2=%h%:%m%:%t2:~0,2%.%t2:~2,3%
ENDLOCAL
变量t2保存您的运行时间,您可以返回%t2%来显示它。
其他回答
“精益和平均”计时器与区域格式,24小时和混合输入支持 调整Aacini的替换方法体,没有IF,只有一个FOR(我的区域修复)
1:文件timer.bat放置在%PATH%或当前目录的某处
@echo off & rem :AveYo: compact timer function with Regional format, 24-hours and mixed input support
if not defined timer_set (if not "%~1"=="" (call set "timer_set=%~1") else set "timer_set=%TIME: =0%") & goto :eof
(if not "%~1"=="" (call set "timer_end=%~1") else set "timer_end=%TIME: =0%") & setlocal EnableDelayedExpansion
for /f "tokens=1-6 delims=0123456789" %%i in ("%timer_end%%timer_set%") do (set CE=%%i&set DE=%%k&set CS=%%l&set DS=%%n)
set "TE=!timer_end:%DE%=%%100)*100+1!" & set "TS=!timer_set:%DS%=%%100)*100+1!"
set/A "T=((((10!TE:%CE%=%%100)*60+1!%%100)-((((10!TS:%CS%=%%100)*60+1!%%100)" & set/A "T=!T:-=8640000-!"
set/A "cc=T%%100+100,T/=100,ss=T%%60+100,T/=60,mm=T%%60+100,hh=T/60+100"
set "value=!hh:~1!%CE%!mm:~1!%CE%!ss:~1!%DE%!cc:~1!" & if "%~2"=="" echo/!value!
endlocal & set "timer_end=%value%" & set "timer_set=" & goto :eof
用法: Timer & echo start_cmds & timeout /t 3 & echo end_cmds & Timer 计时器&计时器“23:23:23,00” 计时器“23:23:23,00”&计时器 计时器“13.23.23,00”&计时器“03:03:03.00” 定时器&定时器“0:00:00.00”no & CMD /v:on /c echo until midnight=!timer_end! 对于执行过程中不太可能但可能发生的时间格式更改,现在可以混合输入
2:函数:与批处理脚本绑定的定时器(示例用法如下):
@echo off
set "TIMER=call :timer" & rem short macro
echo.
echo EXAMPLE:
call :timer
timeout /t 3 >nul & rem Any process here..
call :timer
echo.
echo SHORT MACRO:
%TIMER% & timeout /t 1 & %TIMER%
echo.
echo TEST INPUT:
set "start=22:04:04.58"
set "end=04.22.44,22"
echo %start% ~ start & echo %end% ~ end
call :timer "%start%"
call :timer "%end%"
echo.
%TIMER% & %TIMER% "00:00:00.00" no
echo UNTIL MIDNIGHT: %timer_end%
echo.
pause
exit /b
::要测试它,复制粘贴上面和下面的代码段
rem :AveYo: compact timer function with Regional format, 24-hours and mixed input support
:timer Usage " call :timer [input - optional] [no - optional]" :i Result printed on second call, saved to timer_end
if not defined timer_set (if not "%~1"=="" (call set "timer_set=%~1") else set "timer_set=%TIME: =0%") & goto :eof
(if not "%~1"=="" (call set "timer_end=%~1") else set "timer_end=%TIME: =0%") & setlocal EnableDelayedExpansion
for /f "tokens=1-6 delims=0123456789" %%i in ("%timer_end%%timer_set%") do (set CE=%%i&set DE=%%k&set CS=%%l&set DS=%%n)
set "TE=!timer_end:%DE%=%%100)*100+1!" & set "TS=!timer_set:%DS%=%%100)*100+1!"
set/A "T=((((10!TE:%CE%=%%100)*60+1!%%100)-((((10!TS:%CS%=%%100)*60+1!%%100)" & set/A "T=!T:-=8640000-!"
set/A "cc=T%%100+100,T/=100,ss=T%%60+100,T/=60,mm=T%%60+100,hh=T/60+100"
set "value=!hh:~1!%CE%!mm:~1!%CE%!ss:~1!%DE%!cc:~1!" & if "%~2"=="" echo/!value!
endlocal & set "timer_end=%value%" & set "timer_set=" & goto :eof
CE,DE和CS,DS代表冒号结束,点结束和冒号集合,点集合-用于混合格式支持
这是凯西对答案的扩展。关于使用PowerShell中的Measure-Command:
您可以从标准的命令提示符调用PowerShell,如下所示: powershell -Command "Measure-Command {echo hi}" 这将消耗标准输出,但你可以通过从PowerShell添加| Out-Default来防止这种情况: 测量命令{echo hi | Out-Default} 或者从命令提示符: powershell -Command "Measure-Command {echo hi | Out-Default}"
当然,您可以自由地将其包装在脚本文件*中。Ps1或*.bat。
因为其他人建议安装像免费软件和PowerShell这样的东西,你也可以安装Cygwin,它可以让你访问许多基本的Unix命令,比如time:
abe@abe-PC:~$ time sleep 5
real 0m5.012s
user 0m0.000s
sys 0m0.000s
不知道Cygwin增加了多少开销。
@echo off & setlocal
set start=%time%
REM Do stuff to be timed here.
REM Alternatively, uncomment the line below to be able to
REM pass in the command to be timed when running this script.
REM cmd /c %*
set end=%time%
REM Calculate time taken in seconds, to the hundredth of a second.
REM Assumes start time and end time will be on the same day.
set options="tokens=1-4 delims=:."
for /f %options% %%a in ("%start%") do (
set /a start_s="(100%%a %% 100)*3600 + (100%%b %% 100)*60 + (100%%c %% 100)"
set /a start_hs=100%%d %% 100
)
for /f %options% %%a in ("%end%") do (
set /a end_s="(100%%a %% 100)*3600 + (100%%b %% 100)*60 + (100%%c %% 100)"
set /a end_hs=100%%d %% 100
)
set /a s=%end_s%-%start_s%
set /a hs=%end_hs%-%start_hs%
if %hs% lss 0 (
set /a s=%s%-1
set /a hs=100%hs%
)
if 1%hs% lss 100 set hs=0%hs%
echo.
echo Time taken: %s%.%hs% secs
echo.
下面的脚本模拟*nix纪元时间,但它是本地和区域性的。它应该处理日历边缘情况,包括闰年。如果Cygwin可用,则可以通过指定Cygwin选项来比较epoch值。
我在EST,报告的差异是4小时,这是相对正确的。有一些有趣的解决方案可以删除TZ和区域依赖,但我注意到没有什么微不足道的。
@ECHO off
SETLOCAL EnableDelayedExpansion
::
:: Emulates local epoch seconds
::
:: Call passing local date and time
CALL :SECONDS "%DATE%" "%TIME%"
IF !SECONDS! LEQ 0 GOTO END
:: Not testing - print and exit
IF NOT "%~1"=="cygwin" (
ECHO !SECONDS!
GOTO END
)
:: Call on Cygwin to get epoch time
FOR /F %%c IN ('C:\cygwin\bin\date +%%s') DO SET EPOCH=%%c
:: Show the results
ECHO Local Seconds: !SECONDS!
ECHO Epoch Seconds: !EPOCH!
:: Calculate difference between script and Cygwin
SET /A HOURS=(!EPOCH!-!SECONDS!)/3600
SET /A FRAC=(!EPOCH!-!SECONDS!)%%3600
:: Delta hours shown reflect TZ
ECHO Delta Hours: !HOURS! Remainder: !FRAC!
GOTO END
:SECONDS
SETLOCAL EnableDelayedExpansion
:: Expecting values from caller
SET DATE=%~1
SET TIME=%~2
:: Emulate Unix epoch time without considering TZ
SET "SINCE_YEAR=1970"
:: Regional constraint! Expecting date and time in the following formats:
:: Sun 03/08/2015 Day MM/DD/YYYY
:: 20:04:53.64 HH:MM:SS
SET VALID_DATE=0
ECHO !DATE! | FINDSTR /R /C:"^... [0-9 ][0-9]/[0-9 ][0-9]/[0-9][0-9][0-9][0-9]" > nul && SET VALID_DATE=1
SET VALID_TIME=0
ECHO !TIME! | FINDSTR /R /C:"^[0-9 ][0-9]:[0-9 ][0-9]:[0-9 ][0-9]" > nul && SET VALID_TIME=1
IF NOT "!VALID_DATE!!VALID_TIME!"=="11" (
IF !VALID_DATE! EQU 0 ECHO Unsupported Date value: !DATE! 1>&2
IF !VALID_TIME! EQU 0 ECHO Unsupported Time value: !TIME! 1>&2
SET SECONDS=0
GOTO SECONDS_END
)
:: Parse values
SET "YYYY=!DATE:~10,4!"
SET "MM=!DATE:~4,2!"
SET "DD=!DATE:~7,2!"
SET "HH=!TIME:~0,2!"
SET "NN=!TIME:~3,2!"
SET "SS=!TIME:~6,2!"
SET /A YEARS=!YYYY!-!SINCE_YEAR!
SET /A DAYS=!YEARS!*365
:: Bump year if after February - want leading zeroes for this test
IF "!MM!!DD!" GEQ "0301" SET /A YEARS+=1
:: Remove leading zeros that can cause octet probs for SET /A
FOR %%r IN (MM,DD,HH,NN,SS) DO (
SET "v=%%r"
SET "t=!%%r!"
SET /A N=!t:~0,1!0
IF 0 EQU !N! SET "!v!=!t:~1!"
)
:: Increase days according to number of leap years
SET /A DAYS+=(!YEARS!+3)/4-(!SINCE_YEAR!%%4+3)/4
:: Increase days by preceding months of current year
FOR %%n IN (31:1,28:2,31:3,30:4,31:5,30:6,31:7,31:8,30:9,31:10,30:11) DO (
SET "n=%%n"
IF !MM! GTR !n:~3! SET /A DAYS+=!n:~0,2!
)
:: Multiply and add it all together
SET /A SECONDS=(!DAYS!+!DD!-1)*86400+!HH!*3600+!NN!*60+!SS!
:SECONDS_END
ENDLOCAL & SET "SECONDS=%SECONDS%"
GOTO :EOF
:END
ENDLOCAL
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