我有一个由装饰器转移变量insurance_mode的问题。我将通过以下装饰器语句来实现:
@execute_complete_reservation(True)
def test_booking_gta_object(self):
self.test_select_gta_object()
但不幸的是，这种说法并不管用。也许也许有更好的办法来解决这个问题。
def execute_complete_reservation(test_case,insurance_mode):
def inner_function(self,*args,**kwargs):
self.test_create_qsf_query()
test_case(self,*args,**kwargs)
self.test_select_room_option()
if insurance_mode:
self.test_accept_insurance_crosseling()
else:
self.test_decline_insurance_crosseling()
self.test_configure_pax_details()
self.test_configure_payer_details
return inner_function
在我的实例中，我决定通过一行lambda来解决这个问题，以创建一个新的decorator函数:
def finished_message(function, message="Finished!"):
def wrapper(*args, **kwargs):
output = function(*args,**kwargs)
print(message)
return output
return wrapper
@finished_message
def func():
pass
my_finished_message = lambda f: finished_message(f, "All Done!")
@my_finished_message
def my_func():
pass
if __name__ == '__main__':
func()
my_func()
执行时，输出:
Finished!
All Done!
也许不像其他解决方案那样可扩展，但对我来说是可行的。
我猜你的问题是把参数传递给你的装饰师。这有点棘手，不简单。
下面是一个如何做到这一点的例子:
class MyDec(object):
def __init__(self,flag):
self.flag = flag
def __call__(self, original_func):
decorator_self = self
def wrappee( *args, **kwargs):
print 'in decorator before wrapee with flag ',decorator_self.flag
original_func(*args,**kwargs)
print 'in decorator after wrapee with flag ',decorator_self.flag
return wrappee
@MyDec('foo de fa fa')
def bar(a,b,c):
print 'in bar',a,b,c
bar('x','y','z')
打印:
in decorator before wrapee with flag foo de fa fa
in bar x y z
in decorator after wrapee with flag foo de fa fa
详见Bruce Eckel的文章。
定义这个decoratorize函数来生成定制的decorator函数:
def decoratorize(FUN, **kw):
def foo(*args, **kws):
return FUN(*args, **kws, **kw)
return foo
可以这样用:
@decoratorize(FUN, arg1 = , arg2 = , ...)
def bar(...):
...
如果函数和装饰器都必须接受参数，可以采用下面的方法。
例如，有一个名为decorator1的装饰器，它接受一个参数
@decorator1(5)
def func1(arg1, arg2):
print (arg1, arg2)
func1(1, 2)
现在，如果decorator1参数必须是动态的，或者在调用函数时传递，
def func1(arg1, arg2):
print (arg1, arg2)
a = 1
b = 2
seconds = 10
decorator1(seconds)(func1)(a, b)
在上面的代码中
Seconds是decorator1的参数
A b是func1的参数
下面是一个使用带有参数的装饰器的Flask示例。假设我们有一个路由'/user/name'，我们想要映射到他的主页。
def matchR(dirPath):
def decorator(func):
def wrapper(msg):
if dirPath[0:6] == '/user/':
print(f"User route '{dirPath}' match, calling func {func}")
name = dirPath[6:]
return func(msg2=name, msg3=msg)
else:
print(f"Input dirPath '{dirPath}' does not match route '/user/'")
return
return wrapper
return decorator
#@matchR('/Morgan_Hills')
@matchR('/user/Morgan_Hills')
def home(**kwMsgs):
for arg in kwMsgs:
if arg == 'msg2':
print(f"In home({arg}): Hello {kwMsgs[arg]}, welcome home!")
if arg == 'msg3':
print(f"In home({arg}): {kwMsgs[arg]}")
home('This is your profile rendered as in index.html.')
输出:
User route '/user/Morgan_Hills' match, calling func <function home at 0x000001DD5FDCD310>
In home(msg2): Hello Morgan_Hills, welcome home!
In home(msg3): This is your profile rendered as in index.html.
上面的回答很棒。这个例子还演示了@wraps，它从原始函数中获取文档字符串和函数名，并将其应用于新的包装版本:
from functools import wraps
def decorator_func_with_args(arg1, arg2):
def decorator(f):
@wraps(f)
def wrapper(*args, **kwargs):
print("Before orginal function with decorator args:", arg1, arg2)
result = f(*args, **kwargs)
print("Ran after the orginal function")
return result
return wrapper
return decorator
@decorator_func_with_args("foo", "bar")
def hello(name):
"""A function which prints a greeting to the name provided.
"""
print('hello ', name)
return 42
print("Starting script..")
x = hello('Bob')
print("The value of x is:", x)
print("The wrapped functions docstring is:", hello.__doc__)
print("The wrapped functions name is:", hello.__name__)
打印:
Starting script..
Before orginal function with decorator args: foo bar
hello Bob
Ran after the orginal function
The value of x is: 42
The wrapped functions docstring is: A function which prints a greeting to the name provided.
The wrapped functions name is: hello
