在Oracle数据库表中返回给定列的重复值及其出现次数的最简单SQL语句是什么?
例如:我有一个列为JOB_NUMBER的JOBS表。如何才能知道我是否有任何重复的JOB_NUMBERs,以及它们重复了多少次?
在Oracle数据库表中返回给定列的重复值及其出现次数的最简单SQL语句是什么?
例如:我有一个列为JOB_NUMBER的JOBS表。如何才能知道我是否有任何重复的JOB_NUMBERs,以及它们重复了多少次?
当前回答
如果您不需要知道重复的实际数量,则甚至不需要在返回列中显示计数。如。
SELECT column_name
FROM table
GROUP BY column_name
HAVING COUNT(*) > 1
其他回答
按COUNT聚合列,然后使用HAVING子句查找出现多次的值。
SELECT column_name, COUNT(column_name)
FROM table_name
GROUP BY column_name
HAVING COUNT(column_name) > 1;
我能想到的最简单的:
select job_number, count(*)
from jobs
group by job_number
having count(*) > 1;
下面是一个SQL请求:
select column_name, count(1)
from table
group by column_name
having count (column_name) > 1;
做
select count(j1.job_number), j1.job_number, j1.id, j2.id
from jobs j1 join jobs j2 on (j1.job_numer = j2.job_number)
where j1.id != j2.id
group by j1.job_number
将给出复制行的id。
如何:
SELECT <column>, count(*)
FROM <table>
GROUP BY <column> HAVING COUNT(*) > 1;
要回答上面的例子,它看起来像:
SELECT job_number, count(*)
FROM jobs
GROUP BY job_number HAVING COUNT(*) > 1;