在Oracle数据库表中返回给定列的重复值及其出现次数的最简单SQL语句是什么?
例如:我有一个列为JOB_NUMBER的JOBS表。如何才能知道我是否有任何重复的JOB_NUMBERs,以及它们重复了多少次?
在Oracle数据库表中返回给定列的重复值及其出现次数的最简单SQL语句是什么?
例如:我有一个列为JOB_NUMBER的JOBS表。如何才能知道我是否有任何重复的JOB_NUMBERs,以及它们重复了多少次?
当前回答
你也可以尝试这样的方法在一个表中列出所有重复的值,比如reqitem
SELECT count(poid)
FROM poitem
WHERE poid = 50
AND rownum < any (SELECT count(*) FROM poitem WHERE poid = 50)
GROUP BY poid
MINUS
SELECT count(poid)
FROM poitem
WHERE poid in (50)
GROUP BY poid
HAVING count(poid) > 1;
其他回答
下面是一个SQL请求:
select column_name, count(1)
from table
group by column_name
having count (column_name) > 1;
按COUNT聚合列,然后使用HAVING子句查找出现多次的值。
SELECT column_name, COUNT(column_name)
FROM table_name
GROUP BY column_name
HAVING COUNT(column_name) > 1;
另一种方法:
SELECT *
FROM TABLE A
WHERE EXISTS (
SELECT 1 FROM TABLE
WHERE COLUMN_NAME = A.COLUMN_NAME
AND ROWID < A.ROWID
)
当column_name上有索引时,工作正常(足够快)。它是删除或更新重复行的更好方法。
如果您不需要知道重复的实际数量,则甚至不需要在返回列中显示计数。如。
SELECT column_name
FROM table
GROUP BY column_name
HAVING COUNT(*) > 1
如何:
SELECT <column>, count(*)
FROM <table>
GROUP BY <column> HAVING COUNT(*) > 1;
要回答上面的例子,它看起来像:
SELECT job_number, count(*)
FROM jobs
GROUP BY job_number HAVING COUNT(*) > 1;