我有两个闹钟。我使用带有额外内容的意图而不是行动来识别事件:

Intent i = new Intent(context, AppReciever.class);
i.putExtra("timer", "timer1");

问题是，不同的额外的意图(和警报)不会是唯一的。因此，为了能够识别哪个警报是活跃的或不活跃的，我必须定义diff requestCode-s:

boolean alarmUp = (PendingIntent.getBroadcast(context, MyApp.TIMER_1, i, 
                    PendingIntent.FLAG_NO_CREATE) != null);

下面是如何创建警报的:

public static final int TIMER_1 = 1;
public static final int TIMER_2 = 2;

PendingIntent pending = PendingIntent.getBroadcast(context, TIMER_1, i,
            PendingIntent.FLAG_CANCEL_CURRENT);
setInexactRepeating(AlarmManager.RTC_WAKEUP,
            cal.getTimeInMillis(), AlarmManager.INTERVAL_DAY, pending);
pending = PendingIntent.getBroadcast(context, TIMER_2, i,
            PendingIntent.FLAG_CANCEL_CURRENT);
setInexactRepeating(AlarmManager.RTC_WAKEUP,
            cal.getTimeInMillis(), AlarmManager.INTERVAL_DAY, pending);

接收器的工作示例(上面的答案只是与动作有关)。

//starting
AlarmManager alarmManager = (AlarmManager) getActivity().getSystemService(Context.ALARM_SERVICE);
Intent intent = new Intent(getActivity(), MyReceiver.class);
intent.setAction(MyReceiver.ACTION_ALARM_RECEIVER);//my custom string action name
PendingIntent pendingIntent = PendingIntent.getBroadcast(getActivity(), 1001, intent, PendingIntent.FLAG_CANCEL_CURRENT);//used unique ID as 1001
alarmManager.setRepeating(AlarmManager.RTC_WAKEUP, System.currentTimeMillis(), aroundInterval, pendingIntent);//first start will start asap

//and stopping
Intent intent = new Intent(getActivity(), MyReceiver.class);//the same as up
intent.setAction(MyReceiver.ACTION_ALARM_RECEIVER);//the same as up
PendingIntent pendingIntent = PendingIntent.getBroadcast(getActivity(), 1001, intent, PendingIntent.FLAG_CANCEL_CURRENT);//the same as up
alarmManager.cancel(pendingIntent);//important
pendingIntent.cancel();//important

//checking if alarm is working with pendingIntent
Intent intent = new Intent(getActivity(), MyReceiver.class);//the same as up
intent.setAction(MyReceiver.ACTION_ALARM_RECEIVER);//the same as up
boolean isWorking = (PendingIntent.getBroadcast(getActivity(), 1001, intent, PendingIntent.FLAG_NO_CREATE) != null);//just changed the flag
Log.d(TAG, "alarm is " + (isWorking ? "" : "not") + " working...");

值得一提的是:

如果稍后创建应用程序(进程)重新检索相同类型的 PendingIntent(相同的操作，相同的Intent的动作，数据，类别， 组件，标志)，它将收到一个PendingIntent 表示相同的令牌，如果该令牌仍然有效，则可以调用 取消()来删除它。

简而言之，你的PendingIntent应该有相同的特性(操作和意图的结构)来控制它。

我有两个闹钟。我使用带有额外内容的意图而不是行动来识别事件:

Intent i = new Intent(context, AppReciever.class);
i.putExtra("timer", "timer1");

问题是，不同的额外的意图(和警报)不会是唯一的。因此，为了能够识别哪个警报是活跃的或不活跃的，我必须定义diff requestCode-s:

boolean alarmUp = (PendingIntent.getBroadcast(context, MyApp.TIMER_1, i, 
                    PendingIntent.FLAG_NO_CREATE) != null);

下面是如何创建警报的:

public static final int TIMER_1 = 1;
public static final int TIMER_2 = 2;

PendingIntent pending = PendingIntent.getBroadcast(context, TIMER_1, i,
            PendingIntent.FLAG_CANCEL_CURRENT);
setInexactRepeating(AlarmManager.RTC_WAKEUP,
            cal.getTimeInMillis(), AlarmManager.INTERVAL_DAY, pending);
pending = PendingIntent.getBroadcast(context, TIMER_2, i,
            PendingIntent.FLAG_CANCEL_CURRENT);
setInexactRepeating(AlarmManager.RTC_WAKEUP,
            cal.getTimeInMillis(), AlarmManager.INTERVAL_DAY, pending);

    Intent intent = new Intent("com.my.package.MY_UNIQUE_ACTION");
            PendingIntent pendingIntent = PendingIntent.getBroadcast(
                    sqlitewraper.context, 0, intent,
                    PendingIntent.FLAG_NO_CREATE);

FLAG_NO_CREATE不是创建挂起意图，因此它给出布尔值false。

            boolean alarmUp = (PendingIntent.getBroadcast(sqlitewraper.context, 0,
                    new Intent("com.my.package.MY_UNIQUE_ACTION"),
                    PendingIntent.FLAG_NO_CREATE) != null);

            if (alarmUp) {
                System.out.print("k");

            }

            AlarmManager alarmManager = (AlarmManager) sqlitewraper.context
                    .getSystemService(Context.ALARM_SERVICE);
            alarmManager.setRepeating(AlarmManager.RTC_WAKEUP,
                    System.currentTimeMillis(), 1000 * 60, pendingIntent);

在AlarmManager检查Pending Intent的值后，它给出true，因为AlarmManager更新了Pending Intent的标志。

            boolean alarmUp1 = (PendingIntent.getBroadcast(sqlitewraper.context, 0,
                    new Intent("com.my.package.MY_UNIQUE_ACTION"),
                    PendingIntent.FLAG_UPDATE_CURRENT) != null);
            if (alarmUp1) {
                System.out.print("k");

            }

刚找到另一个解决办法，似乎对我有用

Intent myIntent = new Intent(MainActivity.this, MyReceiver.class);

boolean isWorking = (PendingIntent.getBroadcast(MainActivity.this, 0, myIntent, PendingIntent.FLAG_NO_CREATE) != null);
if (isWorking) {Log.d("alarm", "is working");} else {Log.d("alarm", "is not working");}

if(!isWorking) {
    pendingIntent = PendingIntent.getBroadcast(MainActivity.this, 0, myIntent,    PendingIntent.FLAG_UPDATE_CURRENT);
    alarmManager = (AlarmManager) getSystemService(ALARM_SERVICE);
    int timeNotif = 5 * 60 * 1000;//time in ms, 7*24*60*60*1000 for 1 week
    Log.d("Notif", "Notification every (ms): " + timeNotif);
    alarmManager.setRepeating(AlarmManager.RTC_WAKEUP, calendar.getTimeInMillis(), timeNotif, pendingIntent);
    }

根据ron发表的评论，下面是详细的解决方案。让我们假设你已经注册了一个重复的警报，它的意图是这样的:

Intent intent = new Intent("com.my.package.MY_UNIQUE_ACTION");
PendingIntent pendingIntent = PendingIntent.getBroadcast(context, 0, 
                                      intent, PendingIntent.FLAG_UPDATE_CURRENT);
Calendar calendar = Calendar.getInstance();
calendar.setTimeInMillis(System.currentTimeMillis());
calendar.add(Calendar.MINUTE, 1);

AlarmManager alarmManager = (AlarmManager) context.getSystemService(Context.ALARM_SERVICE);
alarmManager.setRepeating(AlarmManager.RTC_WAKEUP, calendar.getTimeInMillis(), 1000 * 60, pendingIntent);

检查它是否处于活动状态的方法是:

boolean alarmUp = (PendingIntent.getBroadcast(context, 0, 
        new Intent("com.my.package.MY_UNIQUE_ACTION"), 
        PendingIntent.FLAG_NO_CREATE) != null);

if (alarmUp)
{
    Log.d("myTag", "Alarm is already active");
}

关键是在javadoc中描述的FLAG_NO_CREATE:如果所描述的PendingIntent **不**已经存在，那么简单地返回null(而不是创建一个新的)