我有一个基本的Node.js应用程序,我试图使用Express框架启动。我有一个views文件夹,其中有一个index.html文件。但是我在加载网页时收到以下错误:

Error: Cannot find module 'html'

下面是我的代码。

var express = require('express');
var app = express.createServer();

app.use(express.staticProvider(__dirname + '/public'));

app.get('/', function(req, res) {
    res.render('index.html');
});

app.listen(8080, '127.0.0.1')

我错过了什么?


当前回答

这里是一个完整的文件演示的express服务器!

https://gist.github.com/xgqfrms-GitHub/7697d5975bdffe8d474ac19ef906e906

希望对你有所帮助!

// simple express server for HTML pages! // ES6 style const express = require('express'); const fs = require('fs'); const hostname = '127.0.0.1'; const port = 3000; const app = express(); let cache = [];// Array is OK! cache[0] = fs.readFileSync( __dirname + '/index.html'); cache[1] = fs.readFileSync( __dirname + '/views/testview.html'); app.get('/', (req, res) => { res.setHeader('Content-Type', 'text/html'); res.send( cache[0] ); }); app.get('/test', (req, res) => { res.setHeader('Content-Type', 'text/html'); res.send( cache[1] ); }); app.listen(port, () => { console.log(` Server is running at http://${hostname}:${port}/ Server hostname ${hostname} is listening on port ${port}! `); });

其他回答

如果你使用express@~3.0.0修改下面的代码行:

app.use(express.staticProvider(__dirname + '/public'));

就像这样:

app.set("view options", {layout: false});
app.use(express.static(__dirname + '/public'));

我做了它的描述在express api页面,它的工作就像魅力。有了这样的设置,你就不需要编写额外的代码,所以它很容易用于你的微产品或测试。

完整代码如下所示:

var express = require('express');
var app = express.createServer();

app.set("view options", {layout: false});
app.use(express.static(__dirname + '/public'));

app.get('/', function(req, res) {
    res.render('index.html');
});

app.listen(8080, '127.0.0.1')

要在节点中呈现Html页面,请尝试以下操作,

app.set('views', __dirname + '/views');

app.engine('html', require('ejs').renderFile);

你需要像这样通过npm安装ejs模块: NPM安装ejs—保存

It is very sad that it is about 2020 still express hasn't added a way to render an HTML page without using sendFile method of the response object. Using sendFile is not a problem but passing argument to it in the form of path.join(__dirname, 'relative/path/to/file') doesn't feel right. Why should a user join __dirname to the file path? It should be done by default. Why can't the root of the server be by defalut the project directory? Also, installing a templating dependency just to render a static HTML file is again not correct. I don't know the correct way to tackle the issue, but if I had to serve a static HTML, then I would do something like:

const PORT = 8154;

const express = require('express');
const app = express();

app.use(express.static('views'));

app.listen(PORT, () => {
    console.log(`Server is listening at port http://localhost:${PORT}`);
});

The above example assumes that the project structure has a views directory and the static HTML files are inside it. For example, let's say, the views directory has two HTML files named index.html and about.html, then to access them, we can visit: localhost:8153/index.html or just localhost:8153/ to load the index.html page and localhost:8153/about.html to load the about.html. We can use a similar approach to serve a react/angular app by storing the artifacts in the views directory or just using the default dist/<project-name> directory and configure it in the server js as follows:

app.use(express.static('dist/<project-name>'));

在server.js中,请包含

var express = require("express");
var app     = express();
var path    = require("path");


app.get('/',function(req,res){
  res.sendFile(path.join(__dirname+'/index.html'));
  //__dirname : It will resolve to your project folder.
});

这些答案很多都已经过时了。

使用快捷3.0.0和3.1.0,以下工作:

app.set('views', __dirname + '/views');
app.engine('html', require('ejs').renderFile);

请参阅下面的注释,了解表达式3.4+的替代语法和注意事项:

app.set('view engine', 'ejs');

然后你可以这样做:

app.get('/about', function (req, res)
{
    res.render('about.html');
});

这里假设views子文件夹中有视图,并且已经安装了ejs节点模块。如果不是,在Node控制台中执行以下命令:

npm install ejs --save