我有一个基本的Node.js应用程序，我试图使用Express框架启动。我有一个views文件夹，其中有一个index.html文件。但是我在加载网页时收到以下错误:
Error: Cannot find module 'html'
下面是我的代码。
var express = require('express');
var app = express.createServer();
app.use(express.staticProvider(__dirname + '/public'));
app.get('/', function(req, res) {
res.render('index.html');
});
app.listen(8080, '127.0.0.1')
我错过了什么?
当前回答
文件夹结构:
.
├── index.html
├── node_modules
│ ├──{...}
└── server.js
server.js
var express = require('express');
var app = express();
app.use(express.static('./'));
app.get('/', function(req, res) {
res.render('index.html');
});
app.listen(8882, '127.0.0.1')
index . html
<!DOCTYPE html>
<html>
<body>
<div> hello world </div>
</body>
</html>
输出:
你好世界
其他回答
It is very sad that it is about 2020 still express hasn't added a way to render an HTML page without using sendFile method of the response object. Using sendFile is not a problem but passing argument to it in the form of path.join(__dirname, 'relative/path/to/file') doesn't feel right. Why should a user join __dirname to the file path? It should be done by default. Why can't the root of the server be by defalut the project directory? Also, installing a templating dependency just to render a static HTML file is again not correct. I don't know the correct way to tackle the issue, but if I had to serve a static HTML, then I would do something like:
const PORT = 8154;
const express = require('express');
const app = express();
app.use(express.static('views'));
app.listen(PORT, () => {
console.log(`Server is listening at port http://localhost:${PORT}`);
});
The above example assumes that the project structure has a views directory and the static HTML files are inside it. For example, let's say, the views directory has two HTML files named index.html and about.html, then to access them, we can visit: localhost:8153/index.html or just localhost:8153/ to load the index.html page and localhost:8153/about.html to load the about.html. We can use a similar approach to serve a react/angular app by storing the artifacts in the views directory or just using the default dist/<project-name> directory and configure it in the server js as follows:
app.use(express.static('dist/<project-name>'));
你也可以读取HTML文件并发送它:
app.get('/', (req, res) => {
fs.readFile(__dirname + '/public/index.html', 'utf8', (err, text) => {
res.send(text);
});
});
1） 最好的办法是设置静态文件夹。在你的主文件(app.js | server.js | ??):
app.use(express.static(path.join(__dirname, 'public')));
公共/ css / form . html public / css / style . css
然后你从“public”文件夹中获得静态文件:
http://YOUR_DOMAIN/form.html
http://YOUR_DOMAIN/css/style.css
2)
您可以创建您的文件缓存。 使用方法fs.readFileSync
var cache = {};
cache["index.html"] = fs.readFileSync( __dirname + '/public/form.html');
app.get('/', function(req, res){
res.setHeader('Content-Type', 'text/html');
res.send( cache["index.html"] );
};);
如果你试图提供一个HTML文件，其中已经有它所有的内容在里面，那么它不需要被“渲染”，它只需要被“服务”。呈现是指在页面发送到浏览器之前让服务器更新或注入内容，并且它需要额外的依赖项，如ejs，如其他答案所示。
如果你只是想让浏览器根据他们的请求指向一个文件，你应该像这样使用res.sendFile():
const express = require('express');
const app = express();
var port = process.env.PORT || 3000; //Whichever port you want to run on
app.use(express.static('./folder_with_html')); //This ensures local references to cs and js files work
app.get('/', (req, res) => {
res.sendFile(__dirname + '/folder_with_html/index.html');
});
app.listen(port, () => console.log("lifted app; listening on port " + port));
这样，除了express，您就不需要其他依赖项了。如果你只是想让服务器发送你已经创建的html文件，上面是一种非常轻量级的方式。
试试这个。这对我很管用。
app.configure(function(){
.....
// disable layout
app.set("view options", {layout: false});
// make a custom html template
app.register('.html', {
compile: function(str, options){
return function(locals){
return str;
};
}
});
});
....
app.get('/', function(req, res){
res.render("index.html");
});
