使用lodash:

生物多样性功能(length) var chars =“不可能” 瓦尔pwd = _sampleSize (chars,长度正好| | 12)/ lodash v4:用_ sampleSize。 pwd归来加入(“”)。 的 文件写(createRandomString(8)。 <剧本剧本src = " https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js " > < / >

一个取长度的简单函数

getRandomToken(len: number): string {
  return Math.random().toString(36).substr(2, len);
}

如果你传递6，它会生成6位字母数字

在看了这个问题的答案和其他来源的答案后，这是最简单的解决方案，同时允许修改所包含的字符和选择返回结果的长度。

// generate random string of n characters
function randomString(length) {
    const characters = '0123456789abcdefghijklmnopqrstuvwxyz'; // characters used in string
    let result = ''; // initialize the result variable passed out of the function
    for (let i = length; i > 0; i--) {
        result += characters[Math.floor(Math.random() * characters.length)];
    }
    return result;
}

console.log(randomString(6));

随机字符:

String.fromCharCode(i); //where is an int

随机整数:

Math.floor(Math.random()*100);

把它们放在一起:

function randomNum(hi){
    return Math.floor(Math.random()*hi);
} 
function randomChar(){
    return String.fromCharCode(randomNum(100));
}
function randomString(length){
   var str = "";
   for(var i = 0; i < length; ++i){
        str += randomChar();
   }
   return str;
}
var RandomString = randomString(32); //32 length string

小提琴:http://jsfiddle.net/maniator/QZ9J2/

如果你只想允许特定的字符，你也可以这样做:

function randomString(length, chars) {
    var result = '';
    for (var i = length; i > 0; --i) result += chars[Math.floor(Math.random() * chars.length)];
    return result;
}
var rString = randomString(32, '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ');

下面是一个演示的jsfiddle: http://jsfiddle.net/wSQBx/

另一种方法是使用一个特殊的字符串，告诉函数使用什么类型的字符。你可以这样做:

function randomString(length, chars) {
    var mask = '';
    if (chars.indexOf('a') > -1) mask += 'abcdefghijklmnopqrstuvwxyz';
    if (chars.indexOf('A') > -1) mask += 'ABCDEFGHIJKLMNOPQRSTUVWXYZ';
    if (chars.indexOf('#') > -1) mask += '0123456789';
    if (chars.indexOf('!') > -1) mask += '~`!@#$%^&*()_+-={}[]:";\'<>?,./|\\';
    var result = '';
    for (var i = length; i > 0; --i) result += mask[Math.floor(Math.random() * mask.length)];
    return result;
}

console.log(randomString(16, 'aA'));
console.log(randomString(32, '#aA'));
console.log(randomString(64, '#A!'));

小提琴:http://jsfiddle.net/wSQBx/2/

或者，像下面描述的那样使用base36方法，你可以这样做:

function randomString(length) {
    return Math.round((Math.pow(36, length + 1) - Math.random() * Math.pow(36, length))).toString(36).slice(1);
}

我只是发现了一个非常好的优雅的解决方案:

Math.random().toString(36).slice(2)

这个实现的注意事项:

This will produce a string anywhere between zero and 12 characters long, usually 11 characters, due to the fact that floating point stringification removes trailing zeros. It won't generate capital letters, only lower-case and numbers. Because the randomness comes from Math.random(), the output may be predictable and therefore not necessarily unique. Even assuming an ideal implementation, the output has at most 52 bits of entropy, which means you can expect a duplicate after around 70M strings generated.