在JavaScript中生成一个随机的字母数字(大写,小写和数字)字符串来用作可能唯一的标识符的最短方法是什么?
当前回答
这样更干净
Math.random().toString(36).substr(2, length)
例子
Math.random().toString(36).substr(2, 5)
其他回答
32个字符:
for(var c = ''; c.length < 32;) c += Math.random().toString(36).substr(2, 1)
或者根据Jar Jar的建议,这是我在最近的一个项目中使用的方法(以克服长度限制):
var randomString = function (len, bits)
{
bits = bits || 36;
var outStr = "", newStr;
while (outStr.length < len)
{
newStr = Math.random().toString(bits).slice(2);
outStr += newStr.slice(0, Math.min(newStr.length, (len - outStr.length)));
}
return outStr.toUpperCase();
};
Use:
randomString(12, 16); // 12 hexadecimal characters
randomString(200); // 200 alphanumeric characters
一个取长度的简单函数
getRandomToken(len: number): string {
return Math.random().toString(36).substr(2, len);
}
如果你传递6,它会生成6位字母数字
这是一个简单的代码来生成随机字符串字母。 看看这段代码是如何工作的。 去(lenthOfStringToPrint);-使用此函数生成最终字符串。
var letters = {
1: ["q","w","e","r","t","y","u","i","o","p","a","s","d","f","g","h","j","k","l","z","x","c","v","b","n","m"],
2: ["Q","W","E","R","T","Y","U","I","O","P","A","S","D","F","G","H","J","K","L","Z","X","C","V","B","N","M"]
},i,letter,final="";
random = (max,min) => {
return Math.floor(Math.random()*(max-min+1)+min);
}
function go(length) {
final="",letter="";
for (i=1; i<=length; i++){
letter = letters[random(0,3)][random(0,25)];
final+=letter;
}
return final;
}
我认为以下是允许给定长度的最简单的解决方案:
Array(myLength).fill(0).map(x => Math.random().toString(36).charAt(2)).join('')
这取决于箭头函数的语法。