在尝试了合成操作和在画布上绘制图像后,我现在试图删除图像和合成。我怎么做呢?
我需要清除画布重绘其他图像;这可能会持续一段时间,所以我不认为每次都画一个新的矩形是最有效的选择。
在尝试了合成操作和在画布上绘制图像后,我现在试图删除图像和合成。我怎么做呢?
我需要清除画布重绘其他图像;这可能会持续一段时间,所以我不认为每次都画一个新的矩形是最有效的选择。
当前回答
这适用于我的pieChart in chart.js
<div class="pie_nut" id="pieChartContainer">
<canvas id="pieChart" height="5" width="6"></canvas>
</div>
$('#pieChartContainer').html(''); //remove canvas from container
$('#pieChartContainer').html('<canvas id="pieChart" height="5" width="6"></canvas>'); //add it back to the container
其他回答
这是2018年,仍然没有本地的方法来完全清除画布重新绘制。clearRect()不会完全清除画布。非填充型图纸不清除(例如。矩形())
1.要完全清除画布,无论你如何绘制:
context.clearRect(0, 0, context.canvas.width, context.canvas.height);
context.beginPath();
优点:保留strokeStyle, fillStyle等;没有滞后;
缺点:如果你在绘制任何东西之前已经使用了beginPath,那就不必要了
2.使用宽度/高度hack:
context.canvas.width = context.canvas.width;
OR
context.canvas.height = context.canvas.height;
优点:与IE兼容 缺点:重置strokeStyle, fillStyle为黑色;延迟;
我想知道为什么本地解决方案不存在。实际上,clearRect()被认为是单行解决方案,因为大多数用户在绘制任何新路径之前都会执行beginPath()。虽然beginPath只在绘制线条时使用,而不是像rect()那样使用封闭路径。
这就是为什么接受的答案并没有解决我的问题,我最终浪费时间尝试不同的方法。诅咒你mozilla
在webkit中,您需要将宽度设置为不同的值,然后您可以将其设置回初始值
This is a Free hand drawing Canvas with a Clear Canvas Button. See this live example of a canvas which you can draw on and also when required clear it for redrawing clearRect() is used to delete the prersent canvas and fillRect() is used to again draw the initial canvas which was clean and had no drawings on it. var canvas = document.getElementById("canvas"), ctx = canvas.getContext("2d"), painting = false, lastX = 0, lastY = 0, lineThickness = 1; canvas.width=canvas.height = 250; ctx.fillRect(0, 0, 250, 250); canvas.onmousedown = function(e) { painting = true; ctx.fillStyle = "#ffffff"; lastX = e.pageX - this.offsetLeft; lastY = e.pageY - this.offsetTop; }; canvas.onmouseup = function(e){ painting = false; } canvas.onmousemove = function(e) { if (painting) { mouseX = e.pageX - this.offsetLeft; mouseY = e.pageY - this.offsetTop; // find all points between var x1 = mouseX, x2 = lastX, y1 = mouseY, y2 = lastY; var steep = (Math.abs(y2 - y1) > Math.abs(x2 - x1)); if (steep){ var x = x1; x1 = y1; y1 = x; var y = y2; y2 = x2; x2 = y; } if (x1 > x2) { var x = x1; x1 = x2; x2 = x; var y = y1; y1 = y2; y2 = y; } var dx = x2 - x1, dy = Math.abs(y2 - y1), error = 0, de = dy / dx, yStep = -1, y = y1; if (y1 < y2) { yStep = 1; } lineThickness = 4; for (var x = x1; x < x2; x++) { if (steep) { ctx.fillRect(y, x, lineThickness , lineThickness ); } else { ctx.fillRect(x, y, lineThickness , lineThickness ); } error += de; if (error >= 0.5) { y += yStep; error -= 1.0; } } lastX = mouseX; lastY = mouseY; } } var button=document.getElementById("clear"); button.onclick=function clearcanvas(){ canvas=document.getElementById("canvas"), ctx = canvas.getContext('2d'); ctx.clearRect(0, 0, 250, 250); canvas.width=canvas.height = 250; ctx.fillRect(0, 0, 250, 250);} #clear{border-radius:10px; font-size:8px !important; position:absolute; top:1px;} #canvas{border-radius:10px} <link href="https://www.w3schools.com/w3css/4/w3.css" rel="stylesheet"/> <button id="clear" class="w3-padding w3-xxlarge w3-pink" type="button">Clear Canvas</button> <canvas id="canvas"></canvas>
我发现在我测试的所有浏览器中,最快的方法是用白色填充rect,或者任何你想要的颜色。我有一个非常大的显示器,在全屏模式下,clearRect非常慢,但fillRect是合理的。
context.fillStyle = "#ffffff";
context.fillRect(0,0,canvas.width, canvas.height);
缺点是画布不再是透明的。
Chrome响应良好:上下文。clearRect (x, y, w, h);正如@Pentium10所建议的,但IE9似乎完全忽略了这条指令。 IE9似乎对:canvas做出了响应。宽度= canvas.width;但它不清除线条,只是形状,图片和其他物体,除非你也使用@John Allsopp的解决方案,首先改变宽度。
如果你有一个canvas和context是这样创建的:
var canvas = document.getElementById('my-canvas');
var context = canvas.getContext('2d');
你可以使用这样的方法:
function clearCanvas(context, canvas) {
context.clearRect(0, 0, canvas.width, canvas.height);
var w = canvas.width;
canvas.width = 1;
canvas.width = w;
}