我希望这是一件简单的事情，但我找不到任何东西在那里这样做。
我只想获得给定文件夹/目录内的所有文件夹/目录。
例如:
<MyFolder>
|- SomeFolder
|- SomeOtherFolder
|- SomeFile.txt
|- SomeOtherFile.txt
|- x-directory
我期望得到一个数组:
["SomeFolder", "SomeOtherFolder", "x-directory"]
或者上面的路径，如果它是这样提供的……
那么，有什么东西已经存在了吗?
当前回答
你可以使用graph-fs
const {Node} = require("graph-fs");
const directory = new Node("/path/to/directory");
const subDirectories = directory.children.filter(child => child.is.directory);
其他回答
承诺
import { readdir } from 'fs/promises'
const getDirectories = async source =>
(await readdir(source, { withFileTypes: true }))
.filter(dirent => dirent.isDirectory())
.map(dirent => dirent.name)
回调
import { readdir } from 'fs'
const getDirectories = (source, callback) =>
readdir(source, { withFileTypes: true }, (err, files) => {
if (err) {
callback(err)
} else {
callback(
files
.filter(dirent => dirent.isDirectory())
.map(dirent => dirent.name)
)
}
})
Syncronous
import { readdirSync } from 'fs'
const getDirectories = source =>
readdirSync(source, { withFileTypes: true })
.filter(dirent => dirent.isDirectory())
.map(dirent => dirent.name)
你可以使用dree，如果使用一个模块是负担得起的
const dree = require('dree');
const options = {
depth: 1
};
const fileCallback = function() {};
const directories = [];
const dirCallback = function(dir) {
directories.push(dir.name);
};
dree.scan('./dir', {});
console.log(directories);
指定路径("./dir")的子目录将被打印。
如果您不设置选项depth: 1，您甚至会以递归的方式获取所有目录，而不仅仅是指定路径的有向子目录。
完全异步的版本与ES6，只有本机包，fs。Promises和async/await，并行执行文件操作:
const fs = require('fs');
const path = require('path');
async function listDirectories(rootPath) {
const fileNames = await fs.promises.readdir(rootPath);
const filePaths = fileNames.map(fileName => path.join(rootPath, fileName));
const filePathsAndIsDirectoryFlagsPromises = filePaths.map(async filePath => ({path: filePath, isDirectory: (await fs.promises.stat(filePath)).isDirectory()}))
const filePathsAndIsDirectoryFlags = await Promise.all(filePathsAndIsDirectoryFlagsPromises);
return filePathsAndIsDirectoryFlags.filter(filePathAndIsDirectoryFlag => filePathAndIsDirectoryFlag.isDirectory)
.map(filePathAndIsDirectoryFlag => filePathAndIsDirectoryFlag.path);
}
经过测试，它工作得很好。
你可以使用graph-fs
const {Node} = require("graph-fs");
const directory = new Node("/path/to/directory");
const subDirectories = directory.children.filter(child => child.is.directory);
对于getDirectories的异步版本，你需要async模块:
var fs = require('fs');
var path = require('path');
var async = require('async'); // https://github.com/caolan/async
// Original function
function getDirsSync(srcpath) {
return fs.readdirSync(srcpath).filter(function(file) {
return fs.statSync(path.join(srcpath, file)).isDirectory();
});
}
function getDirs(srcpath, cb) {
fs.readdir(srcpath, function (err, files) {
if(err) {
console.error(err);
return cb([]);
}
var iterator = function (file, cb) {
fs.stat(path.join(srcpath, file), function (err, stats) {
if(err) {
console.error(err);
return cb(false);
}
cb(stats.isDirectory());
})
}
async.filter(files, iterator, cb);
});
}
