函数式编程

const fs = require('fs')
const path = require('path')
const R = require('ramda')

const getDirectories = pathName => {
    const isDirectory = pathName => fs.lstatSync(pathName).isDirectory()
    const mapDirectories = pathName => R.map(name => path.join(pathName, name), fs.readdirSync(pathName))
    const filterDirectories = listPaths => R.filter(isDirectory, listPaths)

    return {
        paths:R.pipe(mapDirectories)(pathName),
        pathsFiltered: R.pipe(mapDirectories, filterDirectories)(pathName)
    }
}

以防其他人从网络搜索到这里，并且已经在他们的依赖列表中有Grunt，这个问题的答案变得微不足道。以下是我的解决方案:

/**
 * Return all the subfolders of this path
 * @param {String} parentFolderPath - valid folder path
 * @param {String} glob ['/*'] - optional glob so you can do recursive if you want
 * @returns {String[]} subfolder paths
 */
getSubfolders = (parentFolderPath, glob = '/*') => {
    return grunt.file.expand({filter: 'isDirectory'}, parentFolderPath + glob);
}

承诺

import { readdir } from 'fs/promises'

const getDirectories = async source =>
  (await readdir(source, { withFileTypes: true }))
    .filter(dirent => dirent.isDirectory())
    .map(dirent => dirent.name)

回调

import { readdir } from 'fs'

const getDirectories = (source, callback) =>
  readdir(source, { withFileTypes: true }, (err, files) => {
    if (err) {
      callback(err)
    } else {
      callback(
        files
          .filter(dirent => dirent.isDirectory())
          .map(dirent => dirent.name)
      )
    }
  })

Syncronous

import { readdirSync } from 'fs'

const getDirectories = source =>
  readdirSync(source, { withFileTypes: true })
    .filter(dirent => dirent.isDirectory())
    .map(dirent => dirent.name)

使用node.js版本>= v10.13.0, fs. js。readdirSync将返回一个fs数组。如果withFileTypes选项设置为true，则直接对象。

所以你可以用，

const fs = require('fs')

const directories = source => fs.readdirSync(source, {
   withFileTypes: true
}).reduce((a, c) => {
   c.isDirectory() && a.push(c.name)
   return a
}, [])

你可以使用dree，如果使用一个模块是负担得起的

const dree = require('dree');

const options = {
  depth: 1
};
const fileCallback = function() {};

const directories = [];
const dirCallback = function(dir) {
 directories.push(dir.name);
};

dree.scan('./dir', {});

console.log(directories);

指定路径("./dir")的子目录将被打印。

如果您不设置选项depth: 1，您甚至会以递归的方式获取所有目录，而不仅仅是指定路径的有向子目录。

这应该做到:

CoffeeScript(同步)

fs = require 'fs'

getDirs = (rootDir) ->
    files = fs.readdirSync(rootDir)
    dirs = []

    for file in files
        if file[0] != '.'
            filePath = "#{rootDir}/#{file}"
            stat = fs.statSync(filePath)

            if stat.isDirectory()
                dirs.push(file)

    return dirs

CoffeeScript(异步)

fs = require 'fs'

getDirs = (rootDir, cb) ->
    fs.readdir rootDir, (err, files) ->
        dirs = []

        for file, index in files
            if file[0] != '.'
                filePath = "#{rootDir}/#{file}"
                fs.stat filePath, (err, stat) ->
                    if stat.isDirectory()
                        dirs.push(file)
                    if files.length == (index + 1)
                        cb(dirs)

JavaScript(异步)

var fs = require('fs');
var getDirs = function(rootDir, cb) { 
    fs.readdir(rootDir, function(err, files) { 
        var dirs = []; 
        for (var index = 0; index < files.length; ++index) { 
            var file = files[index]; 
            if (file[0] !== '.') { 
                var filePath = rootDir + '/' + file; 
                fs.stat(filePath, function(err, stat) {
                    if (stat.isDirectory()) { 
                        dirs.push(this.file); 
                    } 
                    if (files.length === (this.index + 1)) { 
                        return cb(dirs); 
                    } 
                }.bind({index: index, file: file})); 
            }
        }
    });
}