我希望这是一件简单的事情,但我找不到任何东西在那里这样做。
我只想获得给定文件夹/目录内的所有文件夹/目录。
例如:
<MyFolder>
|- SomeFolder
|- SomeOtherFolder
|- SomeFile.txt
|- SomeOtherFile.txt
|- x-directory
我期望得到一个数组:
["SomeFolder", "SomeOtherFolder", "x-directory"]
或者上面的路径,如果它是这样提供的……
那么,有什么东西已经存在了吗?
这应该做到:
CoffeeScript(同步)
fs = require 'fs'
getDirs = (rootDir) ->
files = fs.readdirSync(rootDir)
dirs = []
for file in files
if file[0] != '.'
filePath = "#{rootDir}/#{file}"
stat = fs.statSync(filePath)
if stat.isDirectory()
dirs.push(file)
return dirs
CoffeeScript(异步)
fs = require 'fs'
getDirs = (rootDir, cb) ->
fs.readdir rootDir, (err, files) ->
dirs = []
for file, index in files
if file[0] != '.'
filePath = "#{rootDir}/#{file}"
fs.stat filePath, (err, stat) ->
if stat.isDirectory()
dirs.push(file)
if files.length == (index + 1)
cb(dirs)
JavaScript(异步)
var fs = require('fs');
var getDirs = function(rootDir, cb) {
fs.readdir(rootDir, function(err, files) {
var dirs = [];
for (var index = 0; index < files.length; ++index) {
var file = files[index];
if (file[0] !== '.') {
var filePath = rootDir + '/' + file;
fs.stat(filePath, function(err, stat) {
if (stat.isDirectory()) {
dirs.push(this.file);
}
if (files.length === (this.index + 1)) {
return cb(dirs);
}
}.bind({index: index, file: file}));
}
}
});
}
如果需要使用全异步版本。你可以有这样的东西。
记录目录长度,使用它作为一个指示器,以告知是否所有异步统计任务已完成。
如果异步统计任务已完成,则所有文件统计都已检查,因此调用回调
这将只在Node.js是单线程的情况下工作,因为它假设没有两个异步任务会同时增加计数器。
'use strict';
var fs = require("fs");
var path = require("path");
var basePath = "./";
function result_callback(results) {
results.forEach((obj) => {
console.log("isFile: " + obj.fileName);
console.log("fileName: " + obj.isFile);
});
};
fs.readdir(basePath, (err, files) => {
var results = [];
var total = files.length;
var finished = 0;
files.forEach((fileName) => {
// console.log(fileName);
var fullPath = path.join(basePath, fileName);
fs.stat(fullPath, (err, stat) => {
// this will work because Node.js is single thread
// therefore, the counter will not increment at the same time by two callback
finished++;
if (stat.isFile()) {
results.push({
fileName: fileName,
isFile: stat.isFile()
});
}
if (finished == total) {
result_callback(results);
}
});
});
});
正如您所看到的,这是一种“深度优先”的方法,这可能会导致回调地狱,而且它不是完全“功能性的”。人们试图用Promise来解决这个问题,方法是将异步任务包装到Promise对象中。
'use strict';
var fs = require("fs");
var path = require("path");
var basePath = "./";
function result_callback(results) {
results.forEach((obj) => {
console.log("isFile: " + obj.fileName);
console.log("fileName: " + obj.isFile);
});
};
fs.readdir(basePath, (err, files) => {
var results = [];
var total = files.length;
var finished = 0;
var promises = files.map((fileName) => {
// console.log(fileName);
var fullPath = path.join(basePath, fileName);
return new Promise((resolve, reject) => {
// try to replace fullPath wil "aaa", it will reject
fs.stat(fullPath, (err, stat) => {
if (err) {
reject(err);
return;
}
var obj = {
fileName: fileName,
isFile: stat.isFile()
};
resolve(obj);
});
});
});
Promise.all(promises).then((values) => {
console.log("All the promise resolved");
console.log(values);
console.log("Filter out folder: ");
values
.filter((obj) => obj.isFile)
.forEach((obj) => {
console.log(obj.fileName);
});
}, (reason) => {
console.log("Not all the promise resolved");
console.log(reason);
});
});
另一种递归方法
感谢Mayur了解我的withFileTypes。我写了下面的代码来递归地获取特定文件夹的文件。可以很容易地修改它以只获取目录。
const getFiles = (dir, base = '') => readdirSync(dir, {withFileTypes: true}).reduce((files, file) => {
const filePath = path.join(dir, file.name)
const relativePath = path.join(base, file.name)
if(file.isDirectory()) {
return files.concat(getFiles(filePath, relativePath))
} else if(file.isFile()) {
file.__fullPath = filePath
file.__relateivePath = relativePath
return files.concat(file)
}
}, [])