const groupBy = (array, callback) => {
  const groups = {};
  
  array.forEach((element) => {
    const groupName = callback(element);
    if (groupName in groups) {
      groups[groupName].push(element);
    } else {
      groups[groupName] = [element];
    }
  });
  
  return groups;
};

或者花哨的裤子:

(() => {
  Array.prototype.groupBy = function (callback) {
    const groups = {};
    this.forEach((element, ...args) => {
      const groupName = callback(element, ...args);
      if (groupName in groups) {
        groups[groupName].push(element);
      } else {
        groups[groupName] = [element];
      }
    });

    return groups;
  };
})();

const res = [{ name: 1 }, { name: 1 }, { name: 0 }].groupBy(({ name }) => name);

// const res = {
//   0: [{name: 0}],
//   1: [{name: 1}, {name: 1}]
// }

这是一个MDN阵列的填充。groupBy函数。

对于key可以为null的情况，我们希望将它们分组为其他

var cars = [{'make':'audi','model':'r8','year':'2012'},{'make':'audi','model':'rs5','year':'2013'},{'make':'ford','model':'mustang','year':'2012'},{'make':'ford','model':'fusion','year':'2015'},{'make':'kia','model':'optima','year':'2012'},
            {'make':'kia','model':'optima','year':'2033'},
            {'make':null,'model':'zen','year':'2012'},
            {'make':null,'model':'blue','year':'2017'},

           ];


 result = cars.reduce(function (r, a) {
        key = a.make || 'others';
        r[key] = r[key] || [];
        r[key].push(a);
        return r;
    }, Object.create(null));

您正在寻找_.groupBy()。

如果需要，从对象中删除分组的属性应该很简单:

Const cars = [{ “做”:“奥迪”, “模型”:“r8”, “年”:“2012” },{ “做”:“奥迪”, “模型”:“生活费”, “年”:“2013” },{ “做”:“福特”, “模型”:“野马”, “年”:“2012” },{ “做”:“福特”, “模型”:“融合”, “年”:“2015” },{ “做”:“克钦独立军”, “模型”:“最佳状态”, “年”:“2012” }); Const分组= _。groupBy(cars, car => car.make); console.log(分组); < script src = " https://cdn.jsdelivr.net/lodash/4.17.2/lodash.min.js " > < /脚本>

简单的for循环也可以实现:

 const result = {};

 for(const {make, model, year} of cars) {
   if(!result[make]) result[make] = [];
   result[make].push({ model, year });
 }

对象的分组数组在typescript中:

groupBy (list: any[], key: string): Map<string, Array<any>> {
    let map = new Map();
    list.map(val=> {
        if(!map.has(val[key])){
            map.set(val[key],list.filter(data => data[key] == val[key]));
        }
    });
    return map;
});

在简单的Javascript中，你可以使用array# reduce对象

Var cars = [{make: 'audi'，型号:'r8'，年份:'2012'}，{make: 'audi'，型号:'rs5'，年份:'2013'}，{make: 'ford'，型号:'mustang'，年份:'2012'}，{make: 'ford'，型号:'fusion'，年份:'2015'}，{make: 'kia'，型号:'optima'，年份:'2012'}]， 结果=汽车。Reduce(函数(r, a) { r (a。Make] = r[a]。Make] || []; r (a.make) .push(一个); 返回r; }, Object.create (null)); console.log(结果); .as-console-wrapper {max-height: 100% !重要;上图:0;｝