Let

var set = new HashSet<string>(
    new[] { ".mp3", ".jpg" },
    StringComparer.OrdinalIgnoreCase); // ignore case
var dir = new DirectoryInfo(path);

Then

dir.EnumerateFiles("*.*", SearchOption.AllDirectories)
   .Where(f => set.Contains(f.Extension));

or

from file in dir.EnumerateFiles("*.*", SearchOption.AllDirectories)
from ext in set // makes sense only if it's just IEnumerable<string> or similar
where String.Equals(ext, file.Extension, StringComparison.OrdinalIgnoreCase)
select file;

还有一个下降解决方案，似乎没有任何内存或性能开销，而且相当优雅:

string[] filters = new[]{"*.jpg", "*.png", "*.gif"};
string[] filePaths = filters.SelectMany(f => Directory.GetFiles(basePath, f)).ToArray();

我知道这是一个老问题，但LINQ:(.NET40+)

var files = Directory.GetFiles("path_to_files").Where(file => Regex.IsMatch(file, @"^.+\.(wav|mp3|txt)$"));

是什么

string[] filesPNG = Directory.GetFiles(path, "*.png");
string[] filesJPG = Directory.GetFiles(path, "*.jpg");
string[] filesJPEG = Directory.GetFiles(path, "*.jpeg");

int totalArraySizeAll = filesPNG.Length + filesJPG.Length + filesJPEG.Length;
List<string> filesAll = new List<string>(totalArraySizeAll);
filesAll.AddRange(filesPNG);
filesAll.AddRange(filesJPG);
filesAll.AddRange(filesJPEG);

另一种使用Linq的方式，但是不需要返回所有内容并在内存中过滤。

var files = Directory.GetFiles("C:\\path", "*.mp3", SearchOption.AllDirectories).Union(Directory.GetFiles("C:\\path", "*.jpg", SearchOption.AllDirectories));

它实际上是对GetFiles()的2次调用，但我认为这与问题的精神是一致的，并以一个可枚举的形式返回它们。

我不能使用. where方法，因为我在. net Framework 2.0中编程(Linq只在. net Framework 3.5+中被支持)。

下面的代码不区分大小写(因此.cab或.cab也会被列出)。

string[] ext = new string[2] { "*.CAB", "*.MSU" };

foreach (string found in ext)
{
    string[] extracted = Directory.GetFiles("C:\\test", found, System.IO.SearchOption.AllDirectories);

    foreach (string file in extracted)
    {
        Console.WriteLine(file);
    }
}