我一直在使用ES6 Promise。

通常,Promise是这样构造和使用的

new Promise(function(resolve, reject){
    if (someCondition){
        resolve();
    } else {
        reject();
    } 
});

但我一直在做下面这样的事情,为了灵活起见,把决心放在外面。

var outsideResolve;
var outsideReject;
new Promise(function(resolve, reject) { 
    outsideResolve = resolve; 
    outsideReject = reject; 
});

后来

onClick = function(){
    outsideResolve();
}

这很好,但是否有更简单的方法来做到这一点?如果不是,这是一个好的实践吗?


当前回答

公认的答案是错误的。使用范围和引用非常简单,尽管这可能会让Promise纯粹主义者生气:

const createPromise = () => {
    let resolver;
    return [
        new Promise((resolve, reject) => {
            resolver = resolve;
        }),
        resolver,
    ];
};

const [ promise, resolver ] = createPromise();
promise.then(value => console.log(value));
setTimeout(() => resolver('foo'), 1000);

我们实际上是在创建promise时获取resolve函数的引用,并返回该引用,以便可以在外部设置它。

在一秒钟内控制台将输出:

> foo

其他回答

helper方法可以减轻这种额外的开销,并给您同样的jQuery感觉。

function Deferred() {
    let resolve;
    let reject;
    const promise = new Promise((res, rej) => {
        resolve = res;
        reject = rej;
    });
    return { promise, resolve, reject };
}

用法是

const { promise, resolve, reject } = Deferred();
displayConfirmationDialog({
    confirm: resolve,
    cancel: reject
});
return promise;

它类似于jQuery

const dfd = $.Deferred();
displayConfirmationDialog({
    confirm: dfd.resolve,
    cancel: dfd.reject
});
return dfd.promise();

不过,在用例中,这种简单的本机语法就可以了

return new Promise((resolve, reject) => {
    displayConfirmationDialog({
        confirm: resolve,
        cancel: reject
    });
});

如何创建一个函数劫持拒绝并返回它?

function createRejectablePromise(handler) {
  let _reject;

  const promise = new Promise((resolve, reject) => {
    _reject = reject;

    handler(resolve, reject);
  })

  promise.reject = _reject;
  return promise;
}

// Usage
const { reject } = createRejectablePromise((resolve) => {
  setTimeout(() => {
    console.log('resolved')
    resolve();
  }, 2000)

});

reject();

我想分享一些不同的东西,这是这个话题的延伸。

有时,您希望“任务承诺”在解析时自动在相同的地址(属性或变量)重新创建。可以创建一个外部解析器来完成这个任务。

一个带有外部解析器的重复承诺的例子。无论何时调用解析器,都会在相同的地址/变量/属性处创建一个新的承诺。

let resolvePromise;
let thePromise;

const setPromise = (resolve) => {
  resolvePromise = () => {
    resolve();
    thePromise = new Promise(setPromise);   
  }
}
thePromise = new Promise(setPromise);

(async () => {
  let i = 0;
  while (true) {
    let msg = (i % 2 === 0) ? 'Tick' : 'Tock';
    document.body.innerHTML = msg;
    setTimeout(resolvePromise, 1000);
    await thePromise;
    i++;
  }
})();

https://jsfiddle.net/h3zvw5xr

我正在使用一个辅助函数来创建我所谓的“扁平承诺”-

function flatPromise() {

    let resolve, reject;

    const promise = new Promise((res, rej) => {
      resolve = res;
      reject = rej;
    });

    return { promise, resolve, reject };
}

我是这样用的

function doSomethingAsync() {

    // Get your promise and callbacks
    const { resolve, reject, promise } = flatPromise();

    // Do something amazing...
    setTimeout(() => {
        resolve('done!');
    }, 500);

    // Pass your promise to the world
    return promise;

}

参见完整的工作示例-

function flatPromise() { let resolve, reject; const promise = new Promise((res, rej) => { resolve = res; reject = rej; }); return { promise, resolve, reject }; } function doSomethingAsync() { // Get your promise and callbacks const { resolve, reject, promise } = flatPromise(); // Do something amazing... setTimeout(() => { resolve('done!'); }, 500); // Pass your promise to the world return promise; } (async function run() { const result = await doSomethingAsync() .catch(err => console.error('rejected with', err)); console.log(result); })();

编辑: 我已经创建了一个名为flat-promise的NPM包,代码也可以在GitHub上获得。

公认的答案是错误的。使用范围和引用非常简单,尽管这可能会让Promise纯粹主义者生气:

const createPromise = () => {
    let resolver;
    return [
        new Promise((resolve, reject) => {
            resolver = resolve;
        }),
        resolver,
    ];
};

const [ promise, resolver ] = createPromise();
promise.then(value => console.log(value));
setTimeout(() => resolver('foo'), 1000);

我们实际上是在创建promise时获取resolve函数的引用,并返回该引用,以便可以在外部设置它。

在一秒钟内控制台将输出:

> foo