我一直在使用ES6 Promise。
通常，Promise是这样构造和使用的
new Promise(function(resolve, reject){
if (someCondition){
resolve();
} else {
reject();
}
});
但我一直在做下面这样的事情，为了灵活起见，把决心放在外面。
var outsideResolve;
var outsideReject;
new Promise(function(resolve, reject) {
outsideResolve = resolve;
outsideReject = reject;
});
后来
onClick = function(){
outsideResolve();
}
这很好，但是否有更简单的方法来做到这一点?如果不是，这是一个好的实践吗?
当前回答
如何创建一个函数劫持拒绝并返回它?
function createRejectablePromise(handler) {
let _reject;
const promise = new Promise((resolve, reject) => {
_reject = reject;
handler(resolve, reject);
})
promise.reject = _reject;
return promise;
}
// Usage
const { reject } = createRejectablePromise((resolve) => {
setTimeout(() => {
console.log('resolved')
resolve();
}, 2000)
});
reject();
其他回答
公认的答案是错误的。使用范围和引用非常简单，尽管这可能会让Promise纯粹主义者生气:
const createPromise = () => {
let resolver;
return [
new Promise((resolve, reject) => {
resolver = resolve;
}),
resolver,
];
};
const [ promise, resolver ] = createPromise();
promise.then(value => console.log(value));
setTimeout(() => resolver('foo'), 1000);
我们实际上是在创建promise时获取resolve函数的引用，并返回该引用，以便可以在外部设置它。
在一秒钟内控制台将输出:
> foo
只是另一种从外部解决承诺的方法
class Lock {
#lock; // Promise to be resolved (on release)
release; // Release lock
id; // Id of lock
constructor(id) {
this.id = id
this.#lock = new Promise((resolve) => {
this.release = () => {
if (resolve) {
resolve()
} else {
Promise.resolve()
}
}
})
}
get() { return this.#lock }
}
使用
let lock = new Lock(... some id ...);
...
lock.get().then(()=>{console.log('resolved/released')})
lock.release() // Excpected 'resolved/released'
有点晚了，但另一种方法是使用Deferred对象。你基本上有相同数量的样板文件，但是如果你想要传递它们并且可能在它们的定义之外解析，这很方便。
天真的实现:
class Deferred {
constructor() {
this.promise = new Promise((resolve, reject)=> {
this.reject = reject
this.resolve = resolve
})
}
}
function asyncAction() {
var dfd = new Deferred()
setTimeout(()=> {
dfd.resolve(42)
}, 500)
return dfd.promise
}
asyncAction().then(result => {
console.log(result) // 42
})
ES5版本:
function Deferred() {
var self = this;
this.promise = new Promise(function(resolve, reject) {
self.reject = reject
self.resolve = resolve
})
}
function asyncAction() {
var dfd = new Deferred()
setTimeout(function() {
dfd.resolve(42)
}, 500)
return dfd.promise
}
asyncAction().then(function(result) {
console.log(result) // 42
})
如何创建一个函数劫持拒绝并返回它?
function createRejectablePromise(handler) {
let _reject;
const promise = new Promise((resolve, reject) => {
_reject = reject;
handler(resolve, reject);
})
promise.reject = _reject;
return promise;
}
// Usage
const { reject } = createRejectablePromise((resolve) => {
setTimeout(() => {
console.log('resolved')
resolve();
}, 2000)
});
reject();
以防有人来找简化这个任务的util的typescript版本:
export const deferred = <T>() => {
let resolve!: (value: T | PromiseLike<T>) => void;
let reject!: (reason?: any) => void;
const promise = new Promise<T>((res, rej) => {
resolve = res;
reject = rej;
});
return {
resolve,
reject,
promise,
};
};
这可以用在。如:
const {promise, resolve} = deferred<string>();
promise.then((value) => console.log(value)); // nothing
resolve('foo'); // console.log: foo
