只是另一种从外部解决承诺的方法

 class Lock {
        #lock;  // Promise to be resolved (on  release)
        release;  // Release lock
        id;  // Id of lock
        constructor(id) {
            this.id = id
            this.#lock = new Promise((resolve) => {
                this.release = () => {
                    if (resolve) {
                        resolve()
                    } else {
                        Promise.resolve()
                    }
                }
            })
        }
        get() { return this.#lock }
    }

使用

let lock = new Lock(... some id ...);
...
lock.get().then(()=>{console.log('resolved/released')})
lock.release()  // Excpected 'resolved/released'

公认的答案是错误的。使用范围和引用非常简单，尽管这可能会让Promise纯粹主义者生气:

const createPromise = () => {
    let resolver;
    return [
        new Promise((resolve, reject) => {
            resolver = resolve;
        }),
        resolver,
    ];
};

const [ promise, resolver ] = createPromise();
promise.then(value => console.log(value));
setTimeout(() => resolver('foo'), 1000);

我们实际上是在创建promise时获取resolve函数的引用，并返回该引用，以便可以在外部设置它。

在一秒钟内控制台将输出:

> foo

我喜欢@JonJaques的回答，但我想更进一步。

如果你绑定并捕获Deferred对象，那么它完全实现了Promise API，你可以将它视为Promise并等待它等等。

⚠️ Editor's Note: I don't recommend this kind of pattern anymore since at the time of writing, Promise.prototype.finally was not a thing yet, then it became a thing… This could happen to other methods so I recommend you augment the promise instance with resolve and reject functions instead: function createDeferredPromise() { let resolve let reject const promise = new Promise((thisResolve, thisReject) => { resolve = thisResolve reject = thisReject }) return Object.assign(promise, {resolve, reject}) } Go upvote someone else's answer.

class DeferredPromise { constructor() { this._promise = new Promise((resolve, reject) => { // assign the resolve and reject functions to `this` // making them usable on the class instance this.resolve = resolve; this.reject = reject; }); // bind `then` and `catch` to implement the same interface as Promise this.then = this._promise.then.bind(this._promise); this.catch = this._promise.catch.bind(this._promise); this.finally = this._promise.finally.bind(this._promise); this[Symbol.toStringTag] = 'Promise'; } } const deferred = new DeferredPromise(); console.log('waiting 2 seconds...'); setTimeout(() => { deferred.resolve('whoa!'); }, 2000); async function someAsyncFunction() { const value = await deferred; console.log(value); } someAsyncFunction();

不，没有其他方法可以做到这一点——我唯一能说的是这个用例不是很常见。就像Felix在评论中说的那样——你所做的将始终有效。

值得一提的是，promise构造函数以这种方式运行的原因是抛出安全——如果当你的代码在promise构造函数中运行时发生了你没有预料到的异常，它将变成拒绝，这种形式的抛出安全——将抛出的错误转换为拒绝是很重要的，有助于维护可预测的代码。

出于这个抛出安全的原因，承诺构造函数被选择而不是延迟(延迟是一种允许你正在做的事情的替代承诺构造方法)——至于最佳实践——我将传递元素并使用承诺构造函数:

var p = new Promise(function(resolve, reject){
    this.onclick = resolve;
}.bind(this));

出于这个原因——只要可以使用promise构造函数而不是导出函数——我建议您使用它。无论何时你可以避免两者，避免两者和链。

注意，你永远不应该在if(condition)这样的情况下使用promise构造函数，第一个例子可以这样写:

var p = Promise[(someCondition)?"resolve":"reject"]();

我发现自己在某些情况下也忽略了Deferred模式。你总是可以在ES6的顶部创建一个:

export default class Deferred<T> {
    private _resolve: (value: T) => void = () => {};
    private _reject: (value: T) => void = () => {};

    private _promise: Promise<T> = new Promise<T>((resolve, reject) => {
        this._reject = reject;
        this._resolve = resolve;
    })

    public get promise(): Promise<T> {
        return this._promise;
    }

    public resolve(value: T) {
        this._resolve(value);
    }

    public reject(value: T) {
        this._reject(value);
    }
}

如何创建一个函数劫持拒绝并返回它?

function createRejectablePromise(handler) {
  let _reject;

  const promise = new Promise((resolve, reject) => {
    _reject = reject;

    handler(resolve, reject);
  })

  promise.reject = _reject;
  return promise;
}

// Usage
const { reject } = createRejectablePromise((resolve) => {
  setTimeout(() => {
    console.log('resolved')
    resolve();
  }, 2000)

});

reject();