关联、聚合和组合之间的区别是什么? 请从实施的角度加以说明。


当前回答

我想这个链接可以帮到你:http://ootips.org/uml-hasa.html

为了理解这些术语,我记得我早期编程时的一个例子:

如果你有一个" chess board "对象它包含" box "对象那就是组合因为如果" chess board "被删除了盒子就没有理由再存在了。

如果你有一个'square'对象,它有一个'color'对象,正方形被删除了,'color'对象可能仍然存在,这就是聚合

它们都是关联,主要的区别是概念上的

其他回答

组合(如果你删除“整体”,“部分”也会自动删除-“所有权”)

在新类中创建现有类的对象。这称为组合,因为新类是由现有类的对象组成的。 通常使用普通成员变量。 如果组合类自动处理负责创建/销毁子类的分配/回收,则可以使用指针值。

c++中的复合

#include <iostream>
using namespace std;
/********************** Engine Class ******************/
class Engine
{
    int nEngineNumber;
    public:
    Engine(int nEngineNo);
    ~Engine(void);
};
Engine::Engine(int nEngineNo)
{
    cout<<" Engine :: Constructor " <<endl;
}
Engine::~Engine(void)
{
    cout<<" Engine :: Destructor " <<endl;
}
/********************** Car Class ******************/
class Car
{
    int nCarColorNumber;
    int nCarModelNumber;
    Engine objEngine;
    public:
    Car (int, int,int);
    ~Car(void);
};
Car::Car(int nModelNo,int nColorNo, int nEngineNo):
nCarModelNumber(nModelNo),nCarColorNumber(nColorNo),objEngine(nEngineNo)
{
    cout<<" Car :: Constructor " <<endl;
}
Car::~Car(void)
{
    cout<<" Car :: Destructor " <<endl;
    Car
    Engine
    Figure 1 : Composition
}
/********************** Bus Class ******************/
class Bus
{
    int nBusColorNumber;
    int nBusModelNumber;
    Engine* ptrEngine;
    public:
    Bus(int,int,int);
    ~Bus(void);
};
Bus::Bus(int nModelNo,int nColorNo, int nEngineNo):
nBusModelNumber(nModelNo),nBusColorNumber(nColorNo)
{
    ptrEngine = new Engine(nEngineNo);
    cout<<" Bus :: Constructor " <<endl;
}
Bus::~Bus(void)
{
    cout<<" Bus :: Destructor " <<endl;
    delete ptrEngine;
}
/********************** Main Function ******************/
int main()
{
    freopen ("InstallationDump.Log", "w", stdout);
    cout<<"--------------- Start Of Program --------------------"<<endl;
    // Composition using simple Engine in a car object
    {
        cout<<"------------- Inside Car Block ------------------"<<endl;
        Car objCar (1, 2,3);
    }
    cout<<"------------- Out of Car Block ------------------"<<endl;
    // Composition using pointer of Engine in a Bus object
    {
        cout<<"------------- Inside Bus Block ------------------"<<endl;
        Bus objBus(11, 22,33);
    }
    cout<<"------------- Out of Bus Block ------------------"<<endl;
    cout<<"--------------- End Of Program --------------------"<<endl;
    fclose (stdout);
}

输出

--------------- Start Of Program --------------------
------------- Inside Car Block ------------------
Engine :: Constructor
Car :: Constructor
Car :: Destructor
Engine :: Destructor
------------- Out of Car Block ------------------
------------- Inside Bus Block ------------------
Engine :: Constructor
Bus :: Constructor
Bus :: Destructor
Engine :: Destructor
------------- Out of Bus Block ------------------
--------------- End Of Program --------------------

聚合(如果你删除“整体”,“部分”可以存在-“无所有权”)

聚合是一种特定类型的组合,其中不暗示复杂对象和子对象之间的所有权。当一个聚合被销毁时,子对象不会被销毁。 通常使用指针变量/引用变量指向在聚合类作用域之外的对象 可以使用指向在聚合类范围之外的对象的引用值吗 不负责创建/销毁子类

c++中的聚合代码

#include <iostream>
#include <string>
using namespace std;
/********************** Teacher Class ******************/
class Teacher
{
    private:
    string m_strName;
    public:
    Teacher(string strName);
    ~Teacher(void);
    string GetName();
};
Teacher::Teacher(string strName) : m_strName(strName)
{
    cout<<" Teacher :: Constructor --- Teacher Name :: "<<m_strName<<endl;
}
Teacher::~Teacher(void)
{
    cout<<" Teacher :: Destructor --- Teacher Name :: "<<m_strName<<endl;
}
string Teacher::GetName()
{
    return m_strName;
}
/********************** Department Class ******************/
class Department
{
    private:
    Teacher *m_pcTeacher;
    Teacher& m_refTeacher;
    public:
    Department(Teacher *pcTeacher, Teacher& objTeacher);
    ~Department(void);
};
Department::Department(Teacher *pcTeacher, Teacher& objTeacher)
: m_pcTeacher(pcTeacher), m_refTeacher(objTeacher)
{
    cout<<" Department :: Constructor " <<endl;
}
Department::~Department(void)
{
    cout<<" Department :: Destructor " <<endl;
}
/********************** Main Function ******************/
int main()
{
    freopen ("InstallationDump.Log", "w", stdout);
    cout<<"--------------- Start Of Program --------------------"<<endl;
    {
        // Create a teacher outside the scope of the Department
        Teacher objTeacher("Reference Teacher");
        Teacher *pTeacher = new Teacher("Pointer Teacher"); // create a teacher
        {
            cout<<"------------- Inside Block ------------------"<<endl;
            // Create a department and use the constructor parameter to pass the teacher to it.
            Department cDept(pTeacher,objTeacher);
            Department
            Teacher
            Figure 2: Aggregation
        } // cDept goes out of scope here and is destroyed
        cout<<"------------- Out of Block ------------------"<<endl;
        // pTeacher still exists here because cDept did not destroy it
        delete pTeacher;
    }
    cout<<"--------------- End Of Program --------------------"<<endl;
    fclose (stdout);
}

输出

--------------- Start Of Program --------------------
Teacher :: Constructor --- Teacher Name :: Reference Teacher
Teacher :: Constructor --- Teacher Name :: Pointer Teacher
------------- Inside Block ------------------
Department :: Constructor
Department :: Destructor
------------- Out of Block ------------------
Teacher :: Destructor --- Teacher Name :: Pointer Teacher
Teacher :: Destructor --- Teacher Name :: Reference Teacher
--------------- End Of Program --------------------

我想说明如何在Rails中实现这三个术语。ActiveRecord将两个模型之间的任何类型的关系称为关联。在阅读文档或文章时,人们不会经常发现术语组合和聚合与ActiveRecord相关。通过向类的主体中添加一个关联类宏来创建关联。其中一些宏是belongs_to, has_one, has_many等。

If we want to set up a composition or aggregation, we need to add belongs_to to the owned model (also called child) and has_one or has_many to the owning model (also called parent). Wether we set up composition or aggregation depends on the options we pass to the belongs_to call in the child model. Prior to Rails 5, setting up belongs_to without any options created an aggregation, the child could exist without a parent. If we wanted a composition, we needed to explicitly declare this by adding the option required: true:

class Room < ActiveRecord::Base
  belongs_to :house, required: true
end

在Rails 5中,这一点被改变了。现在,声明belongs_to关联在默认情况下创建了一个组合,子元素不能没有父元素而存在。所以上面的例子可以重写为:

class Room < ApplicationRecord
  belongs_to :house
end

如果我们想要允许子对象在没有父对象的情况下存在,我们需要通过选项optional显式地声明这一点

class Product < ApplicationRecord
  belongs_to :category, optional: true
end

关联是两个独立的类之间的关系,关联可以是任何类型,比如one to one, one to may等等。它连接了两个完全独立的实体。

聚合是一种特殊形式的关联,它是类(或实体)之间的单向关系,例如钱包类和货币类。钱包里有钱,但钱不一定要有钱包,所以这是一种单向关系。在这种关系中,如果另一个条目结束,两个条目都可以存活。在我们的例子中,如果Wallet类不存在,并不意味着Money类不存在。

复合是聚合的一种受限形式,其中两个实体(或者可以说类)高度依赖于彼此。例如:人与心。人需要心脏才能生存,心脏也需要人体才能生存。换句话说,当类(实体)是相互依赖的,它们的生命周期是相同的(如果一个死了,另一个也死了),那么它就是一个复合。如果人类职业不存在,心脏职业就没有意义。

在一个非常简单的句子中: 聚合和组合是关联的子集。

A使用B ->这是一个聚合 A需要B ->是复合。

点击这里阅读更多。

联想是关系的广义概念。它包括组合和聚合。

组合(混合)是一种将简单对象或数据类型包装成单个单元的方法。组合是许多基本数据结构的关键构建块

聚合(将许多事物形成一个集群)不同于普通的组合,因为它不意味着所有权。在组合中,当拥有的对象被销毁时,包含的对象也被销毁。总的来说,这并不一定正确。

记住区别的技巧:

“有一个”:聚合 “局部”:comPOsitoin “是一个”:继承

context Aggregation Composition
Life time objects have their own lifetime and there is no owner controlled by whole or parent that owns it
Scope parent objects and child objects are independent parent object also means the death of its children.
Relationship Has-a Part-of
Strength weak relationship strong relationship.
Real-life example Car and Driver Car and wheels

现在让我们观察下面的图像

类比:

合成:下图是图像合成,即使用单独的图像合成一张图像。

聚合:图像在单一位置的集合

例如,A大学有多个系,每个系都有一些教授。如果大学关闭,这些部门将不复存在,但这些部门的教授将继续存在。因此,一所大学可以被看作是一个系的组成部分,而系则是教授的集合。此外,教授可以在一个以上的部门工作,但一个部门不能属于一所以上的大学。