我如何找到一个Bash脚本位于该脚本内部的目录的路径?
我想用Bash脚本作为另一个应用程序的启动器,我想将工作目录更改为Bash脚本所在的目录,所以我可以在该目录中的文件上运行,如下:
$ ./application
我如何找到一个Bash脚本位于该脚本内部的目录的路径?
我想用Bash脚本作为另一个应用程序的启动器,我想将工作目录更改为Bash脚本所在的目录,所以我可以在该目录中的文件上运行,如下:
$ ./application
当前回答
以下是一個符合 POSIX 的單線:
SCRIPT_PATH=`dirname "$0"`; SCRIPT_PATH=`eval "cd \"$SCRIPT_PATH\" && pwd"`
# test
echo $SCRIPT_PATH
其他回答
這是Linux的特點,但你可以使用:
SELF=$(readlink /proc/$$/fd/255)
以下是一個符合 POSIX 的單線:
SCRIPT_PATH=`dirname "$0"`; SCRIPT_PATH=`eval "cd \"$SCRIPT_PATH\" && pwd"`
# test
echo $SCRIPT_PATH
总结:
FULL_PATH_TO_SCRIPT="$(realpath "${BASH_SOURCE[-1]}")"
# OR, if you do NOT need it to work for **sourced** scripts too:
# FULL_PATH_TO_SCRIPT="$(realpath "$0")"
# OR, depending on which path you want, in case of nested `source` calls
# FULL_PATH_TO_SCRIPT="$(realpath "${BASH_SOURCE[0]}")"
# OR, add `-s` to NOT expand symlinks in the path:
# FULL_PATH_TO_SCRIPT="$(realpath -s "${BASH_SOURCE[-1]}")"
SCRIPT_DIRECTORY="$(dirname "$FULL_PATH_TO_SCRIPT")"
SCRIPT_FILENAME="$(basename "$FULL_PATH_TO_SCRIPT")"
细节:
在很多情况下,所有你需要获得的是你刚刚打电话的脚本的完整路径. 这可以很容易地通过 realpath 实现. 请注意, realpath 是 GNU 核心工具的一部分. 如果你没有它已经安装(它是默认的在 Ubuntu 上),你可以安装它与 sudo apt 更新 && sudo apt 安装核心工具。
#!/bin/bash
# A. Obtain the full path, and expand (walk down) symbolic links
# A.1. `"$0"` works only if the file is **run**, but NOT if it is **sourced**.
# FULL_PATH_TO_SCRIPT="$(realpath "$0")"
# A.2. `"${BASH_SOURCE[-1]}"` works whether the file is sourced OR run, and even
# if the script is called from within another bash function!
# NB: if `"${BASH_SOURCE[-1]}"` doesn't give you quite what you want, use
# `"${BASH_SOURCE[0]}"` instead in order to get the first element from the array.
FULL_PATH_TO_SCRIPT="$(realpath "${BASH_SOURCE[-1]}")"
# B.1. `"$0"` works only if the file is **run**, but NOT if it is **sourced**.
# FULL_PATH_TO_SCRIPT_KEEP_SYMLINKS="$(realpath -s "$0")"
# B.2. `"${BASH_SOURCE[-1]}"` works whether the file is sourced OR run, and even
# if the script is called from within another bash function!
# NB: if `"${BASH_SOURCE[-1]}"` doesn't give you quite what you want, use
# `"${BASH_SOURCE[0]}"` instead in order to get the first element from the array.
FULL_PATH_TO_SCRIPT_KEEP_SYMLINKS="$(realpath -s "${BASH_SOURCE[-1]}")"
# You can then also get the full path to the directory, and the base
# filename, like this:
SCRIPT_DIRECTORY="$(dirname "$FULL_PATH_TO_SCRIPT")"
SCRIPT_FILENAME="$(basename "$FULL_PATH_TO_SCRIPT")"
# Now print it all out
echo "FULL_PATH_TO_SCRIPT = \"$FULL_PATH_TO_SCRIPT\""
echo "SCRIPT_DIRECTORY = \"$SCRIPT_DIRECTORY\""
echo "SCRIPT_FILENAME = \"$SCRIPT_FILENAME\""
如果您在脚本中使用“$0”而不是“${BASH_SOURCE[-1]}”,则在运行脚本时,您将获得相同的输出,而不是在提取脚本时,您将获得此不需要的输出:
~/GS/dev/eRCaGuy_hello_world/bash$ . get_script_path.sh
FULL_PATH_TO_SCRIPT = "/bin/bash"
SCRIPT_DIRECTORY = "/bin"
SCRIPT_FILENAME = "bash"
路径与路径之间的区别:
请注意,直路也成功地走下象征性链接来确定并指向他们的目标,而不是指向象征性链接。 如果你不想要这种行为(有时我不),然后添加到上面的直路命令,使该线看起来像这样:
# Obtain the full path, but do NOT expand (walk down) symbolic links; in
# other words: **keep** the symlinks as part of the path!
FULL_PATH_TO_SCRIPT="$(realpath -s "${BASH_SOURCE[-1]}")"
参考:
[我的答案] Unix 和 Linux:确定路径到源头 Shell 脚本
dirname ${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}
如果您想跟随同步链接,请使用您上面的路径上的阅读链接,重复或非重复。
#
# Location: test1/test2/test_script.sh
#
echo $0
echo $_
echo ${BASH_SOURCE}
echo ${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}
cur_file="${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}"
cur_dir="$(dirname "${cur_file}")"
source "${cur_dir}/func_def.sh"
function test_within_func_inside {
echo ${BASH_SOURCE}
echo ${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}
}
echo "Testing within function inside"
test_within_func_inside
echo "Testing within function outside"
test_within_func_outside
#
# Location: test1/test2/func_def.sh
#
function test_within_func_outside {
echo ${BASH_SOURCE}
echo ${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}
}
BASH - 来源
一个序列变量,其成员是源文件名,在 FUNCNAME序列变量中定义了相应的序列函数名称。
功能
这个变量可以使用 BASH_LINENO 和 BASH_SOURCE. FUNCNAME 的每个元素都有相应的元素在 BASH_LINENO 和 BASH_SOURCE 描述呼叫板. 例如, ${FUNCNAME[$i]} 被呼叫从文件 ${BASH_SOURCE[$i+1]} 到线号 ${BASH_LINENO[$i]}。
(源:Bash手册)
保持简单。
#!/usr/bin/env bash
sourceDir=`pwd`
echo $sourceDir