反正你也不可能对字典进行排序。它们实际上并不是有序的。字典的保证是键和值集合是可迭代的，值可以通过索引或键检索，但不保证任何特定的顺序。因此，您需要将名称值对放入一个列表中。

最好的方法:

var list = dict.Values.OrderByDescending(x => x).ToList();
var sortedData = dict.OrderBy(x => list.IndexOf(x.Value));

所需的命名空间:使用System.Linq;

Dictionary<string, int> counts = new Dictionary<string, int>();
counts.Add("one", 1);
counts.Add("four", 4);
counts.Add("two", 2);
counts.Add("three", 3);

按描述排序:

foreach (KeyValuePair<string, int> kvp in counts.OrderByDescending(key => key.Value))
{
// some processing logic for each item if you want.
}

按Asc排序:

foreach (KeyValuePair<string, int> kvp in counts.OrderBy(key => key.Value))
{
// some processing logic for each item if you want.
}

下面的代码片段按值对Dictionary进行排序。

代码首先创建一个字典，然后使用OrderBy方法对条目进行排序。

public void SortDictionary()  
{  
  
    // Create a dictionary with string key and Int16 value pair  
    Dictionary<string, Int16> AuthorList = new Dictionary<string, Int16>();  
    AuthorList.Add("Mahesh Chand", 35);  
    AuthorList.Add("Mike Gold", 25);  
    AuthorList.Add("Praveen Kumar", 29);  
    AuthorList.Add("Raj Beniwal", 21);  
    AuthorList.Add("Dinesh Beniwal", 84);   
  
    // Sorted by Value  
  
    Console.WriteLine("Sorted by Value");  
    Console.WriteLine("=============");  
    foreach (KeyValuePair<string, Int16> author in AuthorList.OrderBy(key => key.Value))  
    {  
        Console.WriteLine("Key: {0}, Value: {1}", author.Key, author.Value);  
    }  
} 

或者为了好玩，你可以使用一些LINQ扩展的优点:

var dictionary = new Dictionary<string, int> { { "c", 3 }, { "a", 1 }, { "b", 2 } };
dictionary.OrderBy(x => x.Value)
  .ForEach(x => Console.WriteLine("{0}={1}", x.Key,x.Value));

在较高的层次上，您别无选择，只能遍历整个Dictionary并查看每个值。

也许这有帮助: http://bytes.com/forum/thread563638.html 复制/粘贴自John Timney:

Dictionary<string, string> s = new Dictionary<string, string>();
s.Add("1", "a Item");
s.Add("2", "c Item");
s.Add("3", "b Item");

List<KeyValuePair<string, string>> myList = new List<KeyValuePair<string, string>>(s);
myList.Sort(
    delegate(KeyValuePair<string, string> firstPair,
    KeyValuePair<string, string> nextPair)
    {
        return firstPair.Value.CompareTo(nextPair.Value);
    }
);