二进制信号量和互斥量之间有区别吗?或者它们本质上是相同的?
当前回答
I think most of the answers here were confusing especially those saying that mutex can be released only by the process that holds it but semaphore can be signaled by ay process. The above line is kind of vague in terms of semaphore. To understand we should know that there are two kinds of semaphore one is called counting semaphore and the other is called a binary semaphore. In counting semaphore handles access to n number of resources where n can be defined before the use. Each semaphore has a count variable, which keeps the count of the number of resources in use, initially, it is set to n. Each process that wishes to uses a resource performs a wait() operation on the semaphore (thereby decrementing the count). When a process releases a resource, it performs a release() operation (incrementing the count). When the count becomes 0, all the resources are being used. After that, the process waits until the count becomes more than 0. Now here is the catch only the process that holds the resource can increase the count no other process can increase the count only the processes holding a resource can increase the count and the process waiting for the semaphore again checks and when it sees the resource available it decreases the count again. So in terms of binary semaphore, only the process holding the semaphore can increase the count, and count remains zero until it stops using the semaphore and increases the count and other process gets the chance to access the semaphore.
二进制信号量和互斥量之间的主要区别在于,信号量是一种信号机制,而互斥量是一种锁定机制,但二进制信号量的功能似乎与互斥量类似,这造成了混乱,但两者是适用于不同类型工作的不同概念。
其他回答
在窗口,差异如下所示。 MUTEX:成功执行等待的进程必须执行一个信号,反之亦然。二进制信号量:不同的进程可以在一个信号量上执行等待或信号操作。
互斥量是任何想要解决临界区问题的算法都必须遵循的标准,而二进制信号量本身是一个可以取0和1值的变量。
Mutex uses a locking mechanism i.e. if a process wants to use a resource then it locks the resource, uses it and then release it. But on the other hand, semaphore uses a signalling mechanism where wait() and signal() methods are used to show if a process is releasing a resource or taking a resource. A mutex is an object but semaphore is an integer variable. In semaphore, we have wait() and signal() functions. But in mutex, there is no such function. A mutex object allows multiple process threads to access a single shared resource but only one at a time. On the other hand, semaphore allows multiple process threads to access the finite instance of the resource until available. In mutex, the lock can be acquired and released by the same process at a time. But the value of the semaphore variable can be modified by any process that needs some resource but only one process can change the value at a time.
一本有用的书,我从这里学习和复制
在Windows上,互斥量和二进制信号量之间有两个区别:
互斥锁只能由拥有所有权的线程释放,即之前调用Wait函数的线程(或在创建互斥锁时获得所有权的线程)。任何线程都可以释放信号量。 线程可以在互斥锁上重复调用等待函数而不会阻塞。但是,如果你在一个二进制信号量上调用了两次等待函数,而中间没有释放信号量,线程就会阻塞。
神话:
一些文章说“二进制信号量和互斥量是相同的”或“值为1的信号量是互斥量”,但基本的区别是互斥量只能由获得它的线程释放,而你可以从任何其他线程发出信号量
重点:
一个线程可以获得多个锁(互斥锁)。
只有递归互斥锁才能被锁多次,这里的锁和锁应该是一样的
•如果一个线程已经锁定了一个互斥锁,试图再次锁定互斥锁,它将进入该互斥锁的等待列表,这将导致死锁。
二进制信号量和互斥量相似但不相同。
互斥是昂贵的操作,因为与它相关的保护协议。
互斥的主要目的是实现对资源的原子访问或锁定
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