我用这个方法使每小时产生60个事件，其中大多数事件在整分钟后的相同秒数内发生:

import math
import time
import random

TICK = 60 # one minute tick size
TICK_TIMING = 59 # execute on 59th second of the tick
TICK_MINIMUM = 30 # minimum catch up tick size when lagging

def set_timing():

    now = time.time()
    elapsed = now - info['begin']
    minutes = math.floor(elapsed/TICK)
    tick_elapsed = now - info['completion_time']
    if (info['tick']+1) > minutes:
        wait = max(0,(TICK_TIMING-(time.time() % TICK)))
        print ('standard wait: %.2f' % wait)
        time.sleep(wait)
    elif tick_elapsed < TICK_MINIMUM:
        wait = TICK_MINIMUM-tick_elapsed
        print ('minimum wait: %.2f' % wait)
        time.sleep(wait)
    else:
        print ('skip set_timing(); no wait')
    drift = ((time.time() - info['begin']) - info['tick']*TICK -
        TICK_TIMING + info['begin']%TICK)
    print ('drift: %.6f' % drift)

info['tick'] = 0
info['begin'] = time.time()
info['completion_time'] = info['begin'] - TICK

while 1:

    set_timing()

    print('hello world')

    #random real world event
    time.sleep(random.random()*TICK_MINIMUM)

    info['tick'] += 1
    info['completion_time'] = time.time()

根据实际情况，你可能会得到长度的刻度:

60,60,62,58,60,60,120,30,30,60,60,60,60,60...etc.

但在60分钟结束时，你会有60个滴答;而且它们中的大多数都将出现在您喜欢的正确偏移时间。

在我的系统中，我得到了< 1/20秒的典型漂移，直到需要纠正。

该方法的优点是具有较好的时钟漂移分辨率;这可能会导致问题，如果你做的事情，比如每tick追加一个项目，你希望每小时追加60个项目。未能考虑漂移可能导致次要指标，如移动平均线，将数据考虑得过于深入过去，从而导致错误的输出。

这里是另一个不使用任何额外库的解决方案。

def delay_until(condition_fn, interval_in_sec, timeout_in_sec):
    """Delay using a boolean callable function.

    `condition_fn` is invoked every `interval_in_sec` until `timeout_in_sec`.
    It can break early if condition is met.

    Args:
        condition_fn     - a callable boolean function
        interval_in_sec  - wait time between calling `condition_fn`
        timeout_in_sec   - maximum time to run

    Returns: None
    """
    start = last_call = time.time()
    while time.time() - start < timeout_in_sec:
        if (time.time() - last_call) > interval_in_sec:
            if condition_fn() is True:
                break
            last_call = time.time()

以下是MestreLion代码的改编版本。 除了原来的函数，这段代码:

1)添加用于在特定时间触发计时器的first_interval(调用者需要计算first_interval并传递进来)

2)在原代码中解决一个竞态条件。在原始代码中，如果控制线程未能取消正在运行的计时器(“停止计时器，并取消计时器动作的执行。这只会在计时器仍处于等待阶段时起作用。”引用自https://docs.python.org/2/library/threading.html)，计时器将无休止地运行。

class RepeatedTimer(object):
def __init__(self, first_interval, interval, func, *args, **kwargs):
    self.timer      = None
    self.first_interval = first_interval
    self.interval   = interval
    self.func   = func
    self.args       = args
    self.kwargs     = kwargs
    self.running = False
    self.is_started = False

def first_start(self):
    try:
        # no race-condition here because only control thread will call this method
        # if already started will not start again
        if not self.is_started:
            self.is_started = True
            self.timer = Timer(self.first_interval, self.run)
            self.running = True
            self.timer.start()
    except Exception as e:
        log_print(syslog.LOG_ERR, "timer first_start failed %s %s"%(e.message, traceback.format_exc()))
        raise

def run(self):
    # if not stopped start again
    if self.running:
        self.timer = Timer(self.interval, self.run)
        self.timer.start()
    self.func(*self.args, **self.kwargs)

def stop(self):
    # cancel current timer in case failed it's still OK
    # if already stopped doesn't matter to stop again
    if self.timer:
        self.timer.cancel()
    self.running = False

如果漂移不是一个问题

import threading, time

def print_every_n_seconds(n=2):
    while True:
        print(time.ctime())
        time.sleep(n)
    
thread = threading.Thread(target=print_every_n_seconds, daemon=True)
thread.start()

异步输出。

#Tue Oct 16 17:29:40 2018
#Tue Oct 16 17:29:42 2018
#Tue Oct 16 17:29:44 2018

如果正在运行的任务需要相当多的时间，那么间隔就变成2秒+任务时间，所以如果您需要精确的调度，那么这并不适合您。

注意daemon=True标志意味着这个线程不会阻止应用程序关闭。例如，在运行测试等待此头停止后，pytest将无限期挂起的问题。

    ''' tracking number of times it prints'''
import threading

global timeInterval
count=0
def printit():
  threading.Timer(timeInterval, printit).start()
  print( "Hello, World!")
  global count
  count=count+1
  print(count)
printit

if __name__ == "__main__":
    timeInterval= int(input('Enter Time in Seconds:'))
    printit()

你可能会考虑Twisted，它是一个实现了Reactor Pattern的Python网络库。

from twisted.internet import task, reactor

timeout = 60.0 # Sixty seconds

def doWork():
    #do work here
    pass

l = task.LoopingCall(doWork)
l.start(timeout) # call every sixty seconds

reactor.run()

虽然“While True: sleep(60)”可能会工作，Twisted可能已经实现了许多你最终需要的功能(如bobince指出的守护进程化、日志记录或异常处理)，并且可能是一个更健壮的解决方案