另一种灵活性解决方案是Apscheduler。

pip install apscheduler

from apscheduler.schedulers.background import BlockingScheduler
def print_t():
  pass

sched = BlockingScheduler()
sched.add_job(print_t, 'interval', seconds =60) #will do the print_t work for every 60 seconds

sched.start()

另外，apscheduler提供了如下所示的许多调度程序。

BlockingScheduler: use when the scheduler is the only thing running in your process BackgroundScheduler: use when you’re not using any of the frameworks below, and want the scheduler to run in the background inside your application AsyncIOScheduler: use if your application uses the asyncio module GeventScheduler: use if your application uses gevent TornadoScheduler: use if you’re building a Tornado application TwistedScheduler: use if you’re building a Twisted application QtScheduler: use if you’re building a Qt application

如果您的程序还没有事件循环，请使用sched模块，它实现了一个通用的事件调度器。

import sched, time

def do_something(scheduler): 
    # schedule the next call first
    scheduler.enter(60, 1, do_something, (scheduler,))
    print("Doing stuff...")
    # then do your stuff

my_scheduler = sched.scheduler(time.time, time.sleep)
my_scheduler.enter(60, 1, do_something, (my_scheduler,))
my_scheduler.run()

如果您已经在使用事件循环库，如asyncio、trio、tkinter、PyQt5、gobject、kivy等，则只需使用现有事件循环库的方法来调度任务。

一个可能的答案是:

import time
t=time.time()

while True:
    if time.time()-t>10:
        #run your task here
        t=time.time()

计时计数可以做到高精度(即< 1毫秒)，因为它与系统时钟同步。它不会随着时间的推移而漂移，也不受代码执行时间长度的影响(当然，前提是它小于间隔时间)。

一个简单的阻塞的例子:

from timed_count import timed_count

for count in timed_count(60):
    # Execute code here exactly every 60 seconds
    ...

你可以通过在线程中运行它来让它变得不阻塞:

from threading import Thread
from timed_count import timed_count

def periodic():
    for count in timed_count(60):
        # Execute code here exactly every 60 seconds
        ...

thread = Thread(target=periodic)
thread.start()

我认为这取决于你想做什么，你的问题没有详细说明。

对我来说，我想在一个已经多线程的进程中做一个昂贵的操作。所以我让leader流程检查时间，只有她做昂贵的操作(检查点深度学习模型)。为了做到这一点，我增加了计数器，以确保5秒、10秒、15秒过去，每5秒保存一次(或使用math.floor的模块化算术):

def print_every_5_seconds_have_passed_exit_eventually():
    """
    https://stackoverflow.com/questions/3393612/run-certain-code-every-n-seconds
    https://stackoverflow.com/questions/474528/what-is-the-best-way-to-repeatedly-execute-a-function-every-x-seconds
    :return:
    """
    opts = argparse.Namespace(start=time.time())
    next_time_to_print = 0
    while True:
        current_time_passed = time.time() - opts.start
        if current_time_passed >= next_time_to_print:
            next_time_to_print += 5
            print(f'worked and {current_time_passed=}')
            print(f'{current_time_passed % 5=}')
            print(f'{math.floor(current_time_passed % 5) == 0}')

starting __main__ at __init__
worked and current_time_passed=0.0001709461212158203
current_time_passed % 5=0.0001709461212158203
True
worked and current_time_passed=5.0
current_time_passed % 5=0.0
True
worked and current_time_passed=10.0
current_time_passed % 5=0.0
True
worked and current_time_passed=15.0
current_time_passed % 5=0.0
True

对我来说，检查if语句是我所需要的。在我已经复杂的多处理器多gpu代码中拥有线程，调度器并不是我想要添加的复杂性，如果我可以避免它，似乎我可以。检查worker id很容易确保只有一个进程在做这件事。

注意，我使用True print语句来确保模块化的算术技巧有效，因为检查确切的时间显然是行不通的!但令我惊喜的是，地板竟然起了作用。

以下是MestreLion代码的改编版本。 除了原来的函数，这段代码:

1)添加用于在特定时间触发计时器的first_interval(调用者需要计算first_interval并传递进来)

2)在原代码中解决一个竞态条件。在原始代码中，如果控制线程未能取消正在运行的计时器(“停止计时器，并取消计时器动作的执行。这只会在计时器仍处于等待阶段时起作用。”引用自https://docs.python.org/2/library/threading.html)，计时器将无休止地运行。

class RepeatedTimer(object):
def __init__(self, first_interval, interval, func, *args, **kwargs):
    self.timer      = None
    self.first_interval = first_interval
    self.interval   = interval
    self.func   = func
    self.args       = args
    self.kwargs     = kwargs
    self.running = False
    self.is_started = False

def first_start(self):
    try:
        # no race-condition here because only control thread will call this method
        # if already started will not start again
        if not self.is_started:
            self.is_started = True
            self.timer = Timer(self.first_interval, self.run)
            self.running = True
            self.timer.start()
    except Exception as e:
        log_print(syslog.LOG_ERR, "timer first_start failed %s %s"%(e.message, traceback.format_exc()))
        raise

def run(self):
    # if not stopped start again
    if self.running:
        self.timer = Timer(self.interval, self.run)
        self.timer.start()
    self.func(*self.args, **self.kwargs)

def stop(self):
    # cancel current timer in case failed it's still OK
    # if already stopped doesn't matter to stop again
    if self.timer:
        self.timer.cancel()
    self.running = False