最佳实践是定义一个可多次访问的可重用函数。

可重用的功能:

例如，AppDelegate.swift是一个全局函数。

func backgroundThread(_ delay: Double = 0.0, background: (() -> Void)? = nil, completion: (() -> Void)? = nil) {
    dispatch_async(dispatch_get_global_queue(Int(QOS_CLASS_USER_INITIATED.value), 0)) {
        background?()

        let popTime = dispatch_time(DISPATCH_TIME_NOW, Int64(delay * Double(NSEC_PER_SEC)))
        dispatch_after(popTime, dispatch_get_main_queue()) {
            completion?()
        }
    }
}

注意:在Swift 2.0中替换QOS_CLASS_USER_INITIATED。使用QOS_CLASS_USER_INITIATED。rawValue相反

用法:

a .在后台运行一个进程，延迟3秒:

    backgroundThread(3.0, background: {
            // Your background function here
    })

B.在后台运行一个进程，然后在前台运行一个补全:

    backgroundThread(background: {
            // Your function here to run in the background
    },
    completion: {
            // A function to run in the foreground when the background thread is complete
    })

C.延迟3秒-注意使用completion参数而不使用background参数:

    backgroundThread(3.0, completion: {
            // Your delayed function here to be run in the foreground
    })

来自Jameson Quave的教程

斯威夫特2

dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0), {
    //All stuff here
})

斯威夫特5

为了简化，创建一个“DispatchQueue+Extensions.swift”文件，内容如下:

import Foundation

typealias Dispatch = DispatchQueue

extension Dispatch {

    static func background(_ task: @escaping () -> ()) {
        Dispatch.global(qos: .background).async {
            task()
        }
    }

    static func main(_ task: @escaping () -> ()) {
        Dispatch.main.async {
            task()
        }
    }
}

用法:

Dispatch.background {
    // do stuff

    Dispatch.main { 
        // update UI
    }
}

我真的很喜欢Dan Beaulieu的答案，但是它在Swift 2.2中不起作用，我认为我们可以避免那些讨厌的强制打开!

func backgroundThread(delay: Double = 0.0, background: (() -> Void)? = nil, completion: (() -> Void)? = nil) {

    dispatch_async(dispatch_get_global_queue(QOS_CLASS_USER_INITIATED, 0)) {

        background?()

        if let completion = completion{
            let popTime = dispatch_time(DISPATCH_TIME_NOW, Int64(delay * Double(NSEC_PER_SEC)))
            dispatch_after(popTime, dispatch_get_main_queue()) {
                completion()
            }
        }
    }
}

Dan Beaulieu在swift5中给出了答案(从swift 3.0.1开始也可以工作)。

斯威夫特5.0.1

extension DispatchQueue {

    static func background(delay: Double = 0.0, background: (()->Void)? = nil, completion: (() -> Void)? = nil) {
        DispatchQueue.global(qos: .background).async {
            background?()
            if let completion = completion {
                DispatchQueue.main.asyncAfter(deadline: .now() + delay, execute: {
                    completion()
                })
            }
        }
    }

}

使用

DispatchQueue.background(delay: 3.0, background: {
    // do something in background
}, completion: {
    // when background job finishes, wait 3 seconds and do something in main thread
})

DispatchQueue.background(background: {
    // do something in background
}, completion:{
    // when background job finished, do something in main thread
})

DispatchQueue.background(delay: 3.0, completion:{
    // do something in main thread after 3 seconds
})

你必须将你想要在后台运行的更改与你想要在UI上运行的更新分开:

dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0)) {
    // do your task

    dispatch_async(dispatch_get_main_queue()) {
        // update some UI
    }
}