下面是我如何使用正则表达式和Kotlin来做到这一点

val BOLD_SPAN = StyleSpan(Typeface.BOLD)

    fun TextView.boldMatches(regexString: String) {
        this.applyStyleSpanToMatches(regexString, BOLD_SPAN)
    }
    

fun TextView.applyStyleSpanToMatches(regexString: String, span: StyleSpan){
        this.text = this.text.toString().applyStyleSpanToMatches(regexString, span)
        }

        fun String.applyStyleSpanToMatches(regexString: String, span: StyleSpan): Spannable {
            val result = SpannableString.valueOf(this)
            if(regexString.isEmpty()) return result
            val pattern = try{
                Pattern.compile(regexString)
            } catch (e: PatternSyntaxException){
                return result
            }
            val matcher = pattern.matcher(result)
            while (matcher.find()) {
                val start = matcher.start()
                val end = matcher.end()
                result.setSpan(span, start, end, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE)
            }
            return result
        }

使用问句 它可以这样应用:

txtResult.boldMatches(id)

下面是我如何使用正则表达式和Kotlin来做到这一点

val BOLD_SPAN = StyleSpan(Typeface.BOLD)

    fun TextView.boldMatches(regexString: String) {
        this.applyStyleSpanToMatches(regexString, BOLD_SPAN)
    }
    

fun TextView.applyStyleSpanToMatches(regexString: String, span: StyleSpan){
        this.text = this.text.toString().applyStyleSpanToMatches(regexString, span)
        }

        fun String.applyStyleSpanToMatches(regexString: String, span: StyleSpan): Spannable {
            val result = SpannableString.valueOf(this)
            if(regexString.isEmpty()) return result
            val pattern = try{
                Pattern.compile(regexString)
            } catch (e: PatternSyntaxException){
                return result
            }
            val matcher = pattern.matcher(result)
            while (matcher.find()) {
                val start = matcher.start()
                val end = matcher.end()
                result.setSpan(span, start, end, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE)
            }
            return result
        }

使用问句 它可以这样应用:

txtResult.boldMatches(id)

如果你想使用XML中的字符串，你可以这样做:

xml(“CDATA”部分很重要，否则它将不起作用)

<string name="test">
     <![CDATA[
 <b>bold!</b> normal
    ]]>
</string>

布局文件

<FrameLayout
    xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent" android:layout_height="match_parent" tools:context=".MainActivity">

    <TextView
        android:id="@+id/textView" android:layout_width="wrap_content" android:layout_height="wrap_content"
        android:layout_gravity="center" />

</FrameLayout>

code

textView.text = HtmlCompat.fromHtml(getString(R.string.test), HtmlCompat.FROM_HTML_MODE_LEGACY)

只需在标签中添加这个

dangerouslySetInnerHTML={{__html: "<p>Your html text here.<p>"}}

public static Spanned getBoldString(String textNotBoldFirst, String textToBold, String textNotBoldLast) {
    String resultant = null;

    resultant = textNotBoldFirst + " " + "<b>" + textToBold + "</b>" + " " + textNotBoldLast;

    return Html.fromHtml(resultant);

}

试试这个。这绝对有帮助

根据@mladj0ni的回答，我得到了下面的代码。问题是如果你使用String。格式，它剥离了HTML标记，所以你必须转义strings.xml中的括号符号:

strings.xml:

<string name="welcome_messages">Hello， %1$s!你有&lt;b>%2$d新消息&lt;/b>.</string> .</string> .

code.java:

String unspanned = String.format(Locale.US, "%s%s", getResources().getString(R.string. welcome_messages), 99);

Spanned spanned;
if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.N) {
    spanned = Html.fromHtml(unspanned, Html.FROM_HTML_MODE_LEGACY);
} else {
    spanned = Html.fromHtml(unspanned);
}

textView.setText(spanned);

它比SpannableStringBuilder简单。至于性能，如果只显示一个字符串，那么用户不会注意到解析它所花费的额外毫秒。

请在这里查看文档。