下面是我如何使用正则表达式和Kotlin来做到这一点

val BOLD_SPAN = StyleSpan(Typeface.BOLD)

    fun TextView.boldMatches(regexString: String) {
        this.applyStyleSpanToMatches(regexString, BOLD_SPAN)
    }
    

fun TextView.applyStyleSpanToMatches(regexString: String, span: StyleSpan){
        this.text = this.text.toString().applyStyleSpanToMatches(regexString, span)
        }

        fun String.applyStyleSpanToMatches(regexString: String, span: StyleSpan): Spannable {
            val result = SpannableString.valueOf(this)
            if(regexString.isEmpty()) return result
            val pattern = try{
                Pattern.compile(regexString)
            } catch (e: PatternSyntaxException){
                return result
            }
            val matcher = pattern.matcher(result)
            while (matcher.find()) {
                val start = matcher.start()
                val end = matcher.end()
                result.setSpan(span, start, end, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE)
            }
            return result
        }

使用问句 它可以这样应用:

txtResult.boldMatches(id)

当在list/recycler中搜索char时，使字符串的第一个char可扩展

拉维和阿杰

以前突出显示像这样，但我想像下面

ravi和ajay OR ravi和ajay

为此，我搜索单词长度，如果它等于1，我将主字符串分离成单词并计算单词开始位置，然后我搜索单词以char开头。

 public static SpannableString colorString(int color, String text, String... wordsToColor) {
    SpannableString coloredString = new SpannableString(text);

    for (String word : wordsToColor) {

        Log.e("tokentoken", "-wrd len-" + word.length());
        if (word.length() !=1) {
            int startColorIndex = text.toLowerCase().indexOf(word.toLowerCase());
            int endColorIndex = startColorIndex + word.length();
            try {
                coloredString.setSpan(new ForegroundColorSpan(color), startColorIndex, endColorIndex,
                        Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);

            } catch (Exception e) {
                e.getMessage();
            }
        } else {
            int start = 0;

            for (String token : text.split("[\u00A0 \n]")) {
                if (token.length() > 0) {
                    start = text.indexOf(token, start);
                   // Log.e("tokentoken", "-token-" + token + "   --start--" + start);
                    char x = token.toLowerCase().charAt(0);
                    char w = word.toLowerCase().charAt(0);
                   // Log.e("tokentoken", "-w-" + w + "   --x--" + x);

                    if (x == w) {
                        // int startColorIndex = text.toLowerCase().indexOf(word.toLowerCase());
                        int endColorIndex = start + word.length();
                        try {
                            coloredString.setSpan(new ForegroundColorSpan(color), start, endColorIndex,
                                    Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);

                        } catch (Exception e) {
                            e.getMessage();
                        }
                    }
                }
            }

        }

    }

    return coloredString;
}

如果你想使用XML中的字符串，你可以这样做:

xml(“CDATA”部分很重要，否则它将不起作用)

<string name="test">
     <![CDATA[
 <b>bold!</b> normal
    ]]>
</string>

布局文件

<FrameLayout
    xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent" android:layout_height="match_parent" tools:context=".MainActivity">

    <TextView
        android:id="@+id/textView" android:layout_width="wrap_content" android:layout_height="wrap_content"
        android:layout_gravity="center" />

</FrameLayout>

code

textView.text = HtmlCompat.fromHtml(getString(R.string.test), HtmlCompat.FROM_HTML_MODE_LEGACY)

这是我使用的Kotlin扩展函数

/**
 * Sets the specified Typeface Style on the first instance of the specified substring(s)
 * @param one or more [Pair] of [String] and [Typeface] style (e.g. BOLD, ITALIC, etc.)
 */
fun TextView.setSubstringTypeface(vararg textsToStyle: Pair<String, Int>) {
    val spannableString = SpannableString(this.text)
    for (textToStyle in textsToStyle) {
        val startIndex = this.text.toString().indexOf(textToStyle.first)
        val endIndex = startIndex + textToStyle.first.length

        if (startIndex >= 0) {
            spannableString.setSpan(
                StyleSpan(textToStyle.second),
                startIndex,
                endIndex,
                Spannable.SPAN_EXCLUSIVE_EXCLUSIVE
            )
        }
    }
    this.setText(spannableString, TextView.BufferType.SPANNABLE)
}

用法:

text_view.text="something bold"
text_view.setSubstringTypeface(
    Pair(
        "something bold",
        Typeface.BOLD
    )
)

.

text_view.text="something bold something italic"
text_view.setSubstringTypeface(
    Pair(
        "something bold ",
        Typeface.BOLD
    ),
    Pair(
        "something italic",
        Typeface.ITALIC
    )
)

找到了一种方法，如果你想处理多种语言的本地化，这很无聊，但它是有效的，让我们假设我们想要这样:

英文:

没有付款记录

西班牙语:

没有付款记录

你必须创建3个字符串

中文:

<string name="start_string">There are no</string>
<string name="middle_string">payments</string>
<string name="end_string">registered.</string>
<string name="string_format" translatable="false">%1$s %2$s %3$s</string>

西班牙语:

<string name="start_string">No hay</string>
<string name="middle_string">pagos</string>
<string name="end_string">registrados</string>

现在你可以这样做:

val startSpanPosition = getString(R.string.start_string).length
val endSpanPosition = startSpanPosition + getString(R.string.middle_string).length
val mySpannableString = SpannableStringBuilder(String.format(getString(R.string.string_format),
        getString(R.string.start_string), getString(R.string.middle_string))), getString(R.string.end_string)))

mySpannableString.setSpan(StyleSpan(Typeface.BOLD), spanStartPosition, endSpanPosition, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE)

简单的例子

在you strings.xml中

<string name="str_privacy_policy">This is our Privacy Policy.</string>

如果你想让“隐私政策”特别加粗，就在加粗标签之间加字符串。

像这样

<string name="str_privacy_policy">This is our <b>Privacy Policy.</b></string>

结果是

这是我们的隐私政策