我不知道如何使TextView上的特定文本变成粗体。

是这样的

txtResult.setText(id+" "+name);

我希望输出是这样的:

1111年尼尔

id和名称是我从数据库中检索值的变量,我想将id改为粗体,但只有id,所以名称不会受到影响,我不知道如何做到这一点。


当前回答

字符串资源

<resources>
   <string name="your_string_resource_name">This is normal text<![CDATA[<b> but this is bold </b>]]> and <![CDATA[<u> but this is underline text</u>]]></string>
</resources> 

您的Java类

yourtextView.setText(getString(R.string.your_string_resource_name));

其他回答

如果你想使用XML中的字符串,你可以这样做:

xml(“CDATA”部分很重要,否则它将不起作用)

<string name="test">
     <![CDATA[
 <b>bold!</b> normal
    ]]>
</string>

布局文件

<FrameLayout
    xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent" android:layout_height="match_parent" tools:context=".MainActivity">

    <TextView
        android:id="@+id/textView" android:layout_width="wrap_content" android:layout_height="wrap_content"
        android:layout_gravity="center" />

</FrameLayout>

code

textView.text = HtmlCompat.fromHtml(getString(R.string.test), HtmlCompat.FROM_HTML_MODE_LEGACY)

字符串资源

<resources>
   <string name="your_string_resource_name">This is normal text<![CDATA[<b> but this is bold </b>]]> and <![CDATA[<u> but this is underline text</u>]]></string>
</resources> 

您的Java类

yourtextView.setText(getString(R.string.your_string_resource_name));

我创建了一个静态方法来设置文本粗体的TextView和EditText部分

public static void boldPartOfText(View mView, String contentData, int startIndex, int endIndex){
        if(!contentData.isEmpty() && contentData.length() > endIndex) {
            final SpannableStringBuilder sb = new SpannableStringBuilder(contentData);

            final StyleSpan bss = new StyleSpan(Typeface.BOLD); // Span to make text bold
            final StyleSpan iss = new StyleSpan(Typeface.NORMAL); //Span to make text normal
            sb.setSpan(iss, 0, startIndex, Spanned.SPAN_INCLUSIVE_INCLUSIVE);
            sb.setSpan(bss, startIndex, endIndex, Spannable.SPAN_INCLUSIVE_INCLUSIVE); // make first 4 characters Bold
            sb.setSpan(iss,endIndex, contentData.length()-1, Spanned.SPAN_INCLUSIVE_INCLUSIVE);

            if(mView instanceof TextView)
               ((TextView) mView).setText(sb);
            else if(mView instanceof EditText)
               ((EditText) mView).setText(sb);

        }
    }

另一个更定制的代码

  /*typeFaceStyle can be passed as 

    Typeface.NORMAL = 0;
    Typeface.BOLD = 1;
    Typeface.ITALIC = 2;
    Typeface.BOLD_ITALIC = 3;*/

    public static void boldPartOfText(View mView, String contentData, int startIndex, int endIndex,int typeFaceStyle){
        if(!contentData.isEmpty() && contentData.length() > endIndex) {
            final SpannableStringBuilder sb = new SpannableStringBuilder(contentData);

            final StyleSpan bss = new StyleSpan(typeFaceStyle); // Span to make text bold
            final StyleSpan iss = new StyleSpan(Typeface.NORMAL); //Span to make text italic
            sb.setSpan(iss, 0, startIndex, Spanned.SPAN_INCLUSIVE_INCLUSIVE);
            sb.setSpan(bss, startIndex, endIndex, Spannable.SPAN_INCLUSIVE_INCLUSIVE); // make first 4 characters Bold
            sb.setSpan(iss,endIndex,contentData.length()-1,Spanned.SPAN_INCLUSIVE_INCLUSIVE);

            if(mView instanceof TextView)
                ((TextView) mView).setText(sb);
            else if(mView instanceof EditText)
                ((EditText) mView).setText(sb);
        }
    }

找到了一种方法,如果你想处理多种语言的本地化,这很无聊,但它是有效的,让我们假设我们想要这样:

英文:

没有付款记录

西班牙语:

没有付款记录

你必须创建3个字符串

中文:

<string name="start_string">There are no</string>
<string name="middle_string">payments</string>
<string name="end_string">registered.</string>
<string name="string_format" translatable="false">%1$s %2$s %3$s</string>

西班牙语:

<string name="start_string">No hay</string>
<string name="middle_string">pagos</string>
<string name="end_string">registrados</string>

现在你可以这样做:

val startSpanPosition = getString(R.string.start_string).length
val endSpanPosition = startSpanPosition + getString(R.string.middle_string).length
val mySpannableString = SpannableStringBuilder(String.format(getString(R.string.string_format),
        getString(R.string.start_string), getString(R.string.middle_string))), getString(R.string.end_string)))

mySpannableString.setSpan(StyleSpan(Typeface.BOLD), spanStartPosition, endSpanPosition, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE)

当在list/recycler中搜索char时,使字符串的第一个char可扩展

拉维和阿杰

以前突出显示像这样,但我想像下面

ravi和ajay OR ravi和ajay

为此,我搜索单词长度,如果它等于1,我将主字符串分离成单词并计算单词开始位置,然后我搜索单词以char开头。

 public static SpannableString colorString(int color, String text, String... wordsToColor) {
    SpannableString coloredString = new SpannableString(text);

    for (String word : wordsToColor) {

        Log.e("tokentoken", "-wrd len-" + word.length());
        if (word.length() !=1) {
            int startColorIndex = text.toLowerCase().indexOf(word.toLowerCase());
            int endColorIndex = startColorIndex + word.length();
            try {
                coloredString.setSpan(new ForegroundColorSpan(color), startColorIndex, endColorIndex,
                        Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);

            } catch (Exception e) {
                e.getMessage();
            }
        } else {
            int start = 0;

            for (String token : text.split("[\u00A0 \n]")) {
                if (token.length() > 0) {
                    start = text.indexOf(token, start);
                   // Log.e("tokentoken", "-token-" + token + "   --start--" + start);
                    char x = token.toLowerCase().charAt(0);
                    char w = word.toLowerCase().charAt(0);
                   // Log.e("tokentoken", "-w-" + w + "   --x--" + x);

                    if (x == w) {
                        // int startColorIndex = text.toLowerCase().indexOf(word.toLowerCase());
                        int endColorIndex = start + word.length();
                        try {
                            coloredString.setSpan(new ForegroundColorSpan(color), start, endColorIndex,
                                    Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);

                        } catch (Exception e) {
                            e.getMessage();
                        }
                    }
                }
            }

        }

    }

    return coloredString;
}