当在list/recycler中搜索char时，使字符串的第一个char可扩展

拉维和阿杰

以前突出显示像这样，但我想像下面

ravi和ajay OR ravi和ajay

为此，我搜索单词长度，如果它等于1，我将主字符串分离成单词并计算单词开始位置，然后我搜索单词以char开头。

 public static SpannableString colorString(int color, String text, String... wordsToColor) {
    SpannableString coloredString = new SpannableString(text);

    for (String word : wordsToColor) {

        Log.e("tokentoken", "-wrd len-" + word.length());
        if (word.length() !=1) {
            int startColorIndex = text.toLowerCase().indexOf(word.toLowerCase());
            int endColorIndex = startColorIndex + word.length();
            try {
                coloredString.setSpan(new ForegroundColorSpan(color), startColorIndex, endColorIndex,
                        Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);

            } catch (Exception e) {
                e.getMessage();
            }
        } else {
            int start = 0;

            for (String token : text.split("[\u00A0 \n]")) {
                if (token.length() > 0) {
                    start = text.indexOf(token, start);
                   // Log.e("tokentoken", "-token-" + token + "   --start--" + start);
                    char x = token.toLowerCase().charAt(0);
                    char w = word.toLowerCase().charAt(0);
                   // Log.e("tokentoken", "-w-" + w + "   --x--" + x);

                    if (x == w) {
                        // int startColorIndex = text.toLowerCase().indexOf(word.toLowerCase());
                        int endColorIndex = start + word.length();
                        try {
                            coloredString.setSpan(new ForegroundColorSpan(color), start, endColorIndex,
                                    Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);

                        } catch (Exception e) {
                            e.getMessage();
                        }
                    }
                }
            }

        }

    }

    return coloredString;
}

这是我的完整的解决方案，动态字符串值与大小写检查。

/**
 * Makes a portion of String formatted in BOLD.
 *
 * @param completeString       String from which a portion needs to be extracted and formatted.<br> eg. I am BOLD.
 * @param targetStringToFormat Target String value to format. <br>eg. BOLD
 * @param matchCase Match by target character case or not. If true, BOLD != bold
 * @return A string with a portion formatted in BOLD. <br> I am <b>BOLD</b>.
 */
public static SpannableStringBuilder formatAStringPortionInBold(String completeString, String targetStringToFormat, boolean matchCase) {
    //Null complete string return empty
    if (TextUtils.isEmpty(completeString)) {
        return new SpannableStringBuilder("");
    }

    SpannableStringBuilder str = new SpannableStringBuilder(completeString);
    int start_index = 0;

    //if matchCase is true, match exact string
    if (matchCase) {
        if (TextUtils.isEmpty(targetStringToFormat) || !completeString.contains(targetStringToFormat)) {
            return str;
        }

        start_index = str.toString().indexOf(targetStringToFormat);
    } else {
        //else find in lower cases
        if (TextUtils.isEmpty(targetStringToFormat) || !completeString.toLowerCase().contains(targetStringToFormat.toLowerCase())) {
            return str;
        }

        start_index = str.toString().toLowerCase().indexOf(targetStringToFormat.toLowerCase());
    }

    int end_index = start_index + targetStringToFormat.length();
    str.setSpan(new StyleSpan(BOLD), start_index, end_index, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
    return str;
}

如。completeString = "I am BOLD"

情况下,我 if *targetStringToFormat* = "bold" and *matchCase* = true

返回“I am BOLD”(因为BOLD != BOLD)

案例二世 if *targetStringToFormat* = "bold" and *matchCase* = false

返回“I am BOLD”

应用:

myTextView.setText(formatAStringPortionInBold("I am BOLD", "bold", false))

希望有帮助!

public static Spanned getBoldString(String textNotBoldFirst, String textToBold, String textNotBoldLast) {
    String resultant = null;

    resultant = textNotBoldFirst + " " + "<b>" + textToBold + "</b>" + " " + textNotBoldLast;

    return Html.fromHtml(resultant);

}

试试这个。这绝对有帮助

当在list/recycler中搜索char时，使字符串的第一个char可扩展

拉维和阿杰

以前突出显示像这样，但我想像下面

ravi和ajay OR ravi和ajay

为此，我搜索单词长度，如果它等于1，我将主字符串分离成单词并计算单词开始位置，然后我搜索单词以char开头。

 public static SpannableString colorString(int color, String text, String... wordsToColor) {
    SpannableString coloredString = new SpannableString(text);

    for (String word : wordsToColor) {

        Log.e("tokentoken", "-wrd len-" + word.length());
        if (word.length() !=1) {
            int startColorIndex = text.toLowerCase().indexOf(word.toLowerCase());
            int endColorIndex = startColorIndex + word.length();
            try {
                coloredString.setSpan(new ForegroundColorSpan(color), startColorIndex, endColorIndex,
                        Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);

            } catch (Exception e) {
                e.getMessage();
            }
        } else {
            int start = 0;

            for (String token : text.split("[\u00A0 \n]")) {
                if (token.length() > 0) {
                    start = text.indexOf(token, start);
                   // Log.e("tokentoken", "-token-" + token + "   --start--" + start);
                    char x = token.toLowerCase().charAt(0);
                    char w = word.toLowerCase().charAt(0);
                   // Log.e("tokentoken", "-w-" + w + "   --x--" + x);

                    if (x == w) {
                        // int startColorIndex = text.toLowerCase().indexOf(word.toLowerCase());
                        int endColorIndex = start + word.length();
                        try {
                            coloredString.setSpan(new ForegroundColorSpan(color), start, endColorIndex,
                                    Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);

                        } catch (Exception e) {
                            e.getMessage();
                        }
                    }
                }
            }

        }

    }

    return coloredString;
}

这是我使用的Kotlin扩展函数

/**
 * Sets the specified Typeface Style on the first instance of the specified substring(s)
 * @param one or more [Pair] of [String] and [Typeface] style (e.g. BOLD, ITALIC, etc.)
 */
fun TextView.setSubstringTypeface(vararg textsToStyle: Pair<String, Int>) {
    val spannableString = SpannableString(this.text)
    for (textToStyle in textsToStyle) {
        val startIndex = this.text.toString().indexOf(textToStyle.first)
        val endIndex = startIndex + textToStyle.first.length

        if (startIndex >= 0) {
            spannableString.setSpan(
                StyleSpan(textToStyle.second),
                startIndex,
                endIndex,
                Spannable.SPAN_EXCLUSIVE_EXCLUSIVE
            )
        }
    }
    this.setText(spannableString, TextView.BufferType.SPANNABLE)
}

用法:

text_view.text="something bold"
text_view.setSubstringTypeface(
    Pair(
        "something bold",
        Typeface.BOLD
    )
)

.

text_view.text="something bold something italic"
text_view.setSubstringTypeface(
    Pair(
        "something bold ",
        Typeface.BOLD
    ),
    Pair(
        "something italic",
        Typeface.ITALIC
    )
)

以防有人使用数据绑定。我们可以像这样定义绑定适配器

@BindingAdapter("html")
fun setHtml(view: TextView, html: String) {
    view.setText(HtmlCompat.fromHtml(html, HtmlCompat.FROM_HTML_MODE_LEGACY))
}

然后我们可以在TextView上使用它

app:html="@{@string/bold_text}"

bold_text在哪里

<string name="bold_text"><![CDATA[Part of text is <b>bold</b>]]></string>