这个版本的非阻塞读取不需要特殊的模块，并且可以在大多数Linux发行版上开箱即用。

import os
import sys
import time
import fcntl
import subprocess

def async_read(fd):
    # set non-blocking flag while preserving old flags
    fl = fcntl.fcntl(fd, fcntl.F_GETFL)
    fcntl.fcntl(fd, fcntl.F_SETFL, fl | os.O_NONBLOCK)
    # read char until EOF hit
    while True:
        try:
            ch = os.read(fd.fileno(), 1)
            # EOF
            if not ch: break                                                                                                                                                              
            sys.stdout.write(ch)
        except OSError:
            # waiting for data be available on fd
            pass

def shell(args, async=True):
    # merge stderr and stdout
    proc = subprocess.Popen(args, shell=False, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
    if async: async_read(proc.stdout)
    sout, serr = proc.communicate()
    return (sout, serr)

if __name__ == '__main__':
    cmd = 'ping 8.8.8.8'
    sout, serr = shell(cmd.split())

使用select & read(1)。

import subprocess     #no new requirements
def readAllSoFar(proc, retVal=''): 
  while (select.select([proc.stdout],[],[],0)[0]!=[]):   
    retVal+=proc.stdout.read(1)
  return retVal
p = subprocess.Popen(['/bin/ls'], stdout=subprocess.PIPE)
while not p.poll():
  print (readAllSoFar(p))

readline()例如:

lines = ['']
while not p.poll():
  lines = readAllSoFar(p, lines[-1]).split('\n')
  for a in range(len(lines)-1):
    print a
lines = readAllSoFar(p, lines[-1]).split('\n')
for a in range(len(lines)-1):
  print a

下面是一个基于线程的简单解决方案:

适用于Linux和Windows(不依赖于select)。 异步读取stdout和stderr。 不依赖于具有任意等待时间的活动轮询(CPU友好)。 不使用asyncio(这可能与其他库冲突)。 一直运行到子进程终止为止。

printer.py

import time
import sys

sys.stdout.write("Hello\n")
sys.stdout.flush()
time.sleep(1)
sys.stdout.write("World!\n")
sys.stdout.flush()
time.sleep(1)
sys.stderr.write("That's an error\n")
sys.stderr.flush()
time.sleep(2)
sys.stdout.write("Actually, I'm fine\n")
sys.stdout.flush()
time.sleep(1)

reader.py

import queue
import subprocess
import sys
import threading


def enqueue_stream(stream, queue, type):
    for line in iter(stream.readline, b''):
        queue.put(str(type) + line.decode('utf-8'))
    stream.close()


def enqueue_process(process, queue):
    process.wait()
    queue.put('x')


p = subprocess.Popen('python printer.py', stdout=subprocess.PIPE, stderr=subprocess.PIPE)
q = queue.Queue()
to = threading.Thread(target=enqueue_stream, args=(p.stdout, q, 1))
te = threading.Thread(target=enqueue_stream, args=(p.stderr, q, 2))
tp = threading.Thread(target=enqueue_process, args=(p, q))
te.start()
to.start()
tp.start()

while True:
    line = q.get()
    if line[0] == 'x':
        break
    if line[0] == '2':  # stderr
        sys.stdout.write("\033[0;31m")  # ANSI red color
    sys.stdout.write(line[1:])
    if line[0] == '2':
        sys.stdout.write("\033[0m")  # reset ANSI code
    sys.stdout.flush()

tp.join()
to.join()
te.join()

为什么要打扰线程和队列? 与readline()不同，BufferedReader.read1()不会阻塞等待\r\n，如果有任何输出进入，它会尽快返回。

#!/usr/bin/python
from subprocess import Popen, PIPE, STDOUT
import io

def __main__():
    try:
        p = Popen( ["ping", "-n", "3", "127.0.0.1"], stdin=PIPE, stdout=PIPE, stderr=STDOUT )
    except: print("Popen failed"); quit()
    sout = io.open(p.stdout.fileno(), 'rb', closefd=False)
    while True:
        buf = sout.read1(1024)
        if len(buf) == 0: break
        print buf,

if __name__ == '__main__':
    __main__()

编辑:这个实现仍然会阻塞。请用j·f·塞巴斯蒂安的答案。

我尝试了上面的答案，但是线程代码的额外风险和维护令人担忧。

通过io模块(仅限于2.6)，我找到了BufferedReader。这是我的无线程、无阻塞的解决方案。

import io
from subprocess import PIPE, Popen

p = Popen(['myprogram.exe'], stdout=PIPE)

SLEEP_DELAY = 0.001

# Create an io.BufferedReader on the file descriptor for stdout
with io.open(p.stdout.fileno(), 'rb', closefd=False) as buffer:
  while p.poll() == None:
      time.sleep(SLEEP_DELAY)
      while '\n' in bufferedStdout.peek(bufferedStdout.buffer_size):
          line = buffer.readline()
          # do stuff with the line

  # Handle any remaining output after the process has ended
  while buffer.peek():
    line = buffer.readline()
    # do stuff with the line

一种解决方案是让另一个进程执行对该进程的读取，或者创建一个带有超时的进程线程。

这是一个超时函数的线程版本:

http://code.activestate.com/recipes/473878/

但是，是否需要在stdout传入时读取它? 另一种解决方案可能是将输出转储到一个文件中，然后使用p.t wait()等待进程完成。

f = open('myprogram_output.txt','w')
p = subprocess.Popen('myprogram.exe', stdout=f)
p.wait()
f.close()


str = open('myprogram_output.txt','r').read()