现有的解决方案不适合我(详情见下文)。最后成功的是使用read(1)实现readline(基于这个答案)。后者不阻塞:

from subprocess import Popen, PIPE
from threading import Thread
def process_output(myprocess): #output-consuming thread
    nextline = None
    buf = ''
    while True:
        #--- extract line using read(1)
        out = myprocess.stdout.read(1)
        if out == '' and myprocess.poll() != None: break
        if out != '':
            buf += out
            if out == '\n':
                nextline = buf
                buf = ''
        if not nextline: continue
        line = nextline
        nextline = None

        #--- do whatever you want with line here
        print 'Line is:', line
    myprocess.stdout.close()

myprocess = Popen('myprogram.exe', stdout=PIPE) #output-producing process
p1 = Thread(target=process_output, args=(myprocess,)) #output-consuming thread
p1.daemon = True
p1.start()

#--- do whatever here and then kill process and thread if needed
if myprocess.poll() == None: #kill process; will automatically stop thread
    myprocess.kill()
    myprocess.wait()
if p1 and p1.is_alive(): #wait for thread to finish
    p1.join()

为什么现有的解决方案不起作用:

Solutions that require readline (including the Queue based ones) always block. It is difficult (impossible?) to kill the thread that executes readline. It only gets killed when the process that created it finishes, but not when the output-producing process is killed. Mixing low-level fcntl with high-level readline calls may not work properly as anonnn has pointed out. Using select.poll() is neat, but doesn't work on Windows according to python docs. Using third-party libraries seems overkill for this task and adds additional dependencies.

免责声明:这只适用于龙卷风

您可以通过将fd设置为非阻塞，然后使用ioloop来注册回调来实现这一点。我把它打包在一个名为tornado_subprocess的鸡蛋中，你可以通过PyPI安装它:

easy_install tornado_subprocess

现在你可以这样做:

import tornado_subprocess
import tornado.ioloop

    def print_res( status, stdout, stderr ) :
    print status, stdout, stderr
    if status == 0:
        print "OK:"
        print stdout
    else:
        print "ERROR:"
        print stderr

t = tornado_subprocess.Subprocess( print_res, timeout=30, args=[ "cat", "/etc/passwd" ] )
t.start()
tornado.ioloop.IOLoop.instance().start()

你也可以将它与RequestHandler一起使用

class MyHandler(tornado.web.RequestHandler):
    def on_done(self, status, stdout, stderr):
        self.write( stdout )
        self.finish()

    @tornado.web.asynchronous
    def get(self):
        t = tornado_subprocess.Subprocess( self.on_done, timeout=30, args=[ "cat", "/etc/passwd" ] )
        t.start()

I have often had a similar problem; Python programs I write frequently need to have the ability to execute some primary functionality while simultaneously accepting user input from the command line (stdin). Simply putting the user input handling functionality in another thread doesn't solve the problem because readline() blocks and has no timeout. If the primary functionality is complete and there is no longer any need to wait for further user input I typically want my program to exit, but it can't because readline() is still blocking in the other thread waiting for a line. A solution I have found to this problem is to make stdin a non-blocking file using the fcntl module:

import fcntl
import os
import sys

# make stdin a non-blocking file
fd = sys.stdin.fileno()
fl = fcntl.fcntl(fd, fcntl.F_GETFL)
fcntl.fcntl(fd, fcntl.F_SETFL, fl | os.O_NONBLOCK)

# user input handling thread
while mainThreadIsRunning:
      try: input = sys.stdin.readline()
      except: continue
      handleInput(input)

在我看来，这比使用select或signal模块来解决这个问题要简洁一些，但它只适用于UNIX…

根据J.F. Sebastian的答案和其他几个来源，我组合了一个简单的子流程管理器。它提供了请求的非阻塞读取，以及并行运行几个进程。它不使用任何特定于操作系统的调用(我知道)，因此应该在任何地方工作。

它可以从pypi获得，所以只需pip安装shelljob。参考项目页面的示例和完整的文档。

在类unix系统和Python 3.5+上有os。Set_blocking，做的就是它所说的。

import os
import time
import subprocess

cmd = 'python3', '-c', 'import time; [(print(i), time.sleep(1)) for i in range(5)]'
p = subprocess.Popen(cmd, stdout=subprocess.PIPE)
os.set_blocking(p.stdout.fileno(), False)
start = time.time()
while True:
    # first iteration always produces empty byte string in non-blocking mode
    for i in range(2):    
        line = p.stdout.readline()
        print(i, line)
        time.sleep(0.5)
    if time.time() > start + 5:
        break
p.terminate()

这个输出:

1 b''
2 b'0\n'
1 b''
2 b'1\n'
1 b''
2 b'2\n'
1 b''
2 b'3\n'
1 b''
2 b'4\n'

与操作系统。Set_blocking注释它是:

0 b'0\n'
1 b'1\n'
0 b'2\n'
1 b'3\n'
0 b'4\n'
1 b''

我基于J. F. Sebastian的解决方案创建了一个库。你可以使用它。

https://github.com/cenkalti/what