Enthought Traits有一个模块很好地解决了这个问题。https://traits.readthedocs.org/en/4.3.0/_modules/traits/util/refresh.html

它将重新加载任何已更改的模块，并更新正在使用它的其他模块和实例对象。它在__very_private__方法的大多数时候都不起作用，并且可能会阻塞类继承，但它为我节省了大量的时间，使我不必在编写PyQt gui或在Maya或Nuke等程序中运行的东西时重新启动主机应用程序。它可能有20% - 30%的时间不起作用，但它仍然非常有帮助。

Enthought的包不会在文件更改时重新加载它们——您必须显式地调用它——但如果您确实需要它，实现它应该不是那么困难

我遇到了很多麻烦，试图在Sublime Text中重新加载一些东西，但最后我可以编写这个实用程序来基于sublime_plugin.py用于重新加载模块的代码在Sublime Text上重新加载模块。

下面的代码允许您从名称上带有空格的路径重新加载模块，然后在重新加载后，您可以像往常一样导入。

def reload_module(full_module_name):
    """
        Assuming the folder `full_module_name` is a folder inside some
        folder on the python sys.path, for example, sys.path as `C:/`, and
        you are inside the folder `C:/Path With Spaces` on the file 
        `C:/Path With Spaces/main.py` and want to re-import some files on
        the folder `C:/Path With Spaces/tests`

        @param full_module_name   the relative full path to the module file
                                  you want to reload from a folder on the
                                  python `sys.path`
    """
    import imp
    import sys
    import importlib

    if full_module_name in sys.modules:
        module_object = sys.modules[full_module_name]
        module_object = imp.reload( module_object )

    else:
        importlib.import_module( full_module_name )

def run_tests():
    print( "\n\n" )
    reload_module( "Path With Spaces.tests.semantic_linefeed_unit_tests" )
    reload_module( "Path With Spaces.tests.semantic_linefeed_manual_tests" )

    from .tests import semantic_linefeed_unit_tests
    from .tests import semantic_linefeed_manual_tests

    semantic_linefeed_unit_tests.run_unit_tests()
    semantic_linefeed_manual_tests.run_manual_tests()

if __name__ == "__main__":
    run_tests()

如果您第一次运行，这将加载模块，但如果稍后您可以再次运行run_tests()方法/函数，它将重新加载测试文件。对于Sublime Text (Python 3.3.6)，这种情况经常发生，因为它的解释器从不关闭(除非你重新启动Sublime Text，即Python3.3解释器)。

对于Python 2，使用内置函数reload:

reload(module)

对于Python 2和Python 3.2-3.3，使用reload from module imp:

import imp
imp.reload(module)

对于Python≥3.4,imp已弃用，改用importlib，因此使用以下命令:

import importlib
importlib.reload(module)

or:

from importlib import reload
reload(module)

TL; diana:

Python≥3.4:importlib.reload(module) Python 3.2 - 3.3: imp.reload(module) Python 2: reload(module)

其他选项。请参阅Python默认importlib。Reload将只是重新导入作为参数传递的库。它不会重新加载库导入的库。如果您更改了很多文件，并且有一个有点复杂的包要导入，那么您必须进行深度重载。

如果你安装了IPython或Jupyter，你可以使用一个函数来深度重载所有库:

from IPython.lib.deepreload import reload as dreload
dreload(foo)

如果你没有Jupyter，在你的shell中使用以下命令安装它:

pip3 install jupyter

编辑(答案V2)

前面的解决方案只适用于获取重置信息，但它不会更改所有引用(超过重新加载，但小于所需)。为了设置所有的引用，我必须进入垃圾收集器，并在那里重写引用。现在它就像一个咒语!

请注意，如果GC被关闭，或者如果重新加载不受GC监视的数据，这将不起作用。如果您不想打乱GC，原始答案可能就足够了。

新代码:

import importlib
import inspect
import gc
from enum import EnumMeta
from weakref import ref


_readonly_attrs = {'__annotations__', '__call__', '__class__', '__closure__', '__code__', '__defaults__', '__delattr__',
               '__dict__', '__dir__', '__doc__', '__eq__', '__format__', '__func__', '__ge__', '__get__',
               '__getattribute__', '__globals__', '__gt__', '__hash__', '__init__', '__init_subclass__',
               '__kwdefaults__', '__le__', '__lt__', '__module__', '__name__', '__ne__', '__new__', '__qualname__',
               '__reduce__', '__reduce_ex__', '__repr__', '__self__', '__setattr__', '__sizeof__', '__str__',
               '__subclasshook__', '__weakref__', '__members__', '__mro__', '__itemsize__', '__isabstractmethod__',
               '__basicsize__', '__base__'}


def reset_module(module, inner_modules_also=True):
    """
    This function is a stronger form of importlib's `reload` function. What it does, is that aside from reloading a
    module, it goes to the old instance of the module, and sets all the (not read-only) attributes, functions and classes
    to be the reloaded-module's
    :param module: The module to reload (module reference, not the name)
    :param inner_modules_also: Whether to treat ths module as a package as well, and reload all the modules within it.
    """

    # For the case when the module is actually a package
    if inner_modules_also:
        submods = {submod for _, submod in inspect.getmembers(module)
                   if (type(submod).__name__ == 'module') and (submod.__package__.startswith(module.__name__))}
        for submod in submods:
            reset_module(submod, True)

    # First, log all the references before reloading (because some references may be changed by the reload operation).
    module_tree = _get_tree_references_to_reset_recursively(module, module.__name__)

    new_module = importlib.reload(module)
    _reset_item_recursively(module, module_tree, new_module)


def _update_referrers(item, new_item):
    refs = gc.get_referrers(item)

    weak_ref_item = ref(item)
    for coll in refs:
        if type(coll) == dict:
            enumerator = coll.keys()
        elif type(coll) == list:
            enumerator = range(len(coll))
        else:
            continue

        for key in enumerator:

            if weak_ref_item() is None:
                # No refs are left in the GC
                return

            if coll[key] is weak_ref_item():
                coll[key] = new_item

def _get_tree_references_to_reset_recursively(item, module_name, grayed_out_item_ids = None):
    if grayed_out_item_ids is None:
        grayed_out_item_ids = set()

    item_tree = dict()
    attr_names = set(dir(item)) - _readonly_attrs
    for sub_item_name in attr_names:

        sub_item = getattr(item, sub_item_name)
        item_tree[sub_item_name] = [sub_item, None]

        try:
            # Will work for classes and functions defined in that module.
            mod_name = sub_item.__module__
        except AttributeError:
            mod_name = None

        # If this item was defined within this module, deep-reset
        if (mod_name is None) or (mod_name != module_name) or (id(sub_item) in grayed_out_item_ids) \
                or isinstance(sub_item, EnumMeta):
            continue

        grayed_out_item_ids.add(id(sub_item))
        item_tree[sub_item_name][1] = \
            _get_tree_references_to_reset_recursively(sub_item, module_name, grayed_out_item_ids)

    return item_tree


def _reset_item_recursively(item, item_subtree, new_item):

    # Set children first so we don't lose the current references.
    if item_subtree is not None:
        for sub_item_name, (sub_item, sub_item_tree) in item_subtree.items():

            try:
                new_sub_item = getattr(new_item, sub_item_name)
            except AttributeError:
                # The item doesn't exist in the reloaded module. Ignore.
                continue

            try:
                # Set the item
                _reset_item_recursively(sub_item, sub_item_tree, new_sub_item)
            except Exception as ex:
                pass

    _update_referrers(item, new_item)

原来的答案

正如在@bobince的回答中所写的，如果在另一个模块中已经有对该模块的引用(特别是如果它是用As关键字导入的，如import numpy As np)，该实例将不会被覆盖。

当应用需要配置模块的“全新”状态的测试时，这对我来说是相当有问题的，所以我写了一个名为reset_module的函数，它使用importlib的reload函数并递归地覆盖所有声明的模块属性。它已经用Python版本3.6进行了测试。

import importlib
import inspect
from enum import EnumMeta

_readonly_attrs = {'__annotations__', '__call__', '__class__', '__closure__', '__code__', '__defaults__', '__delattr__',
               '__dict__', '__dir__', '__doc__', '__eq__', '__format__', '__func__', '__ge__', '__get__',
               '__getattribute__', '__globals__', '__gt__', '__hash__', '__init__', '__init_subclass__',
               '__kwdefaults__', '__le__', '__lt__', '__module__', '__name__', '__ne__', '__new__', '__qualname__',
               '__reduce__', '__reduce_ex__', '__repr__', '__self__', '__setattr__', '__sizeof__', '__str__',
               '__subclasshook__', '__weakref__', '__members__', '__mro__', '__itemsize__', '__isabstractmethod__',
               '__basicsize__', '__base__'}


def reset_module(module, inner_modules_also=True):
    """
    This function is a stronger form of importlib's `reload` function. What it does, is that aside from reloading a
    module, it goes to the old instance of the module, and sets all the (not read-only) attributes, functions and classes
    to be the reloaded-module's
    :param module: The module to reload (module reference, not the name)
    :param inner_modules_also: Whether to treat ths module as a package as well, and reload all the modules within it.
    """

    new_module = importlib.reload(module)

    reset_items = set()

    # For the case when the module is actually a package
    if inner_modules_also:
        submods = {submod for _, submod in inspect.getmembers(module)
                   if (type(submod).__name__ == 'module') and (submod.__package__.startswith(module.__name__))}
        for submod in submods:
            reset_module(submod, True)

    _reset_item_recursively(module, new_module, module.__name__, reset_items)


def _reset_item_recursively(item, new_item, module_name, reset_items=None):
    if reset_items is None:
        reset_items = set()

    attr_names = set(dir(item)) - _readonly_attrs

    for sitem_name in attr_names:

        sitem = getattr(item, sitem_name)
        new_sitem = getattr(new_item, sitem_name)

        try:
            # Set the item
            setattr(item, sitem_name, new_sitem)

            try:
                # Will work for classes and functions defined in that module.
                mod_name = sitem.__module__
            except AttributeError:
                mod_name = None

            # If this item was defined within this module, deep-reset
            if (mod_name is None) or (mod_name != module_name) or (id(sitem) in reset_items) \
                    or isinstance(sitem, EnumMeta):  # Deal with enums
                continue

            reset_items.add(id(sitem))
            _reset_item_recursively(sitem, new_sitem, module_name, reset_items)
        except Exception as ex:
            raise Exception(sitem_name) from ex

注意事项:请谨慎使用!在非外围模块(例如，定义外部使用的类的模块)上使用这些可能会导致Python中的内部问题(例如pickle / unpickling问题)。

下面的代码允许你兼容Python 2/3:

try:
    reload
except NameError:
    # Python 3
    from imp import reload

你可以在两个版本中使用它作为reload()，这让事情变得更简单。