我需要在一个图表中绘制一个显示计数的柱状图和一个显示率的折线图,我可以分别做这两个,但当我把它们放在一起时,我的第一层(即geom_bar)的比例被第二层(即geom_line)重叠。
我可以将geom_line的轴向右移动吗?
我需要在一个图表中绘制一个显示计数的柱状图和一个显示率的折线图,我可以分别做这两个,但当我把它们放在一起时,我的第一层(即geom_bar)的比例被第二层(即geom_line)重叠。
我可以将geom_line的轴向右移动吗?
当前回答
Hadley的回答参考了Stephen Few的报告《双缩放轴在图中是最好的解决方案吗?》
我不知道OP中的“counts”和“rate”是什么意思,但快速搜索会给我counts和Rates,所以我得到了一些关于北美登山事故的数据:
Years<-c("1998","1999","2000","2001","2002","2003","2004")
Persons.Involved<-c(281,248,301,276,295,231,311)
Fatalities<-c(20,17,24,16,34,18,35)
rate=100*Fatalities/Persons.Involved
df<-data.frame(Years=Years,Persons.Involved=Persons.Involved,Fatalities=Fatalities,rate=rate)
print(df,row.names = FALSE)
Years Persons.Involved Fatalities rate
1998 281 20 7.117438
1999 248 17 6.854839
2000 301 24 7.973422
2001 276 16 5.797101
2002 295 34 11.525424
2003 231 18 7.792208
2004 311 35 11.254019
然后,我尝试按照Few在上述报告第7页建议的那样绘制图表(并按照OP的要求将计数绘制为柱状图,将率绘制为折线图):
The other less obvious solution, which works only for time series, is to convert all sets of values to a common quantitative scale by displaying percentage differences between each value and a reference (or index) value. For instance, select a particular point in time, such as the first interval that appears in the graph, and express each subsequent value as the percentage difference between it and the initial value. This is done by dividing the value at each point in time by the value for the initial point in time and then multiplying it by 100 to convert the rate to a percentage, as illustrated below.
df2<-df
df2$Persons.Involved <- 100*df$Persons.Involved/df$Persons.Involved[1]
df2$rate <- 100*df$rate/df$rate[1]
plot(ggplot(df2)+
geom_bar(aes(x=Years,weight=Persons.Involved))+
geom_line(aes(x=Years,y=rate,group=1))+
theme(text = element_text(size=30))
)
这就是结果:
但我不是很喜欢它,我不能轻易地给它加上一个传奇……
1 威廉森,杰德,等人。2005年北美登山事故。The Mountaineers Books, 2005。
其他回答
Hadley的回答参考了Stephen Few的报告《双缩放轴在图中是最好的解决方案吗?》
我不知道OP中的“counts”和“rate”是什么意思,但快速搜索会给我counts和Rates,所以我得到了一些关于北美登山事故的数据:
Years<-c("1998","1999","2000","2001","2002","2003","2004")
Persons.Involved<-c(281,248,301,276,295,231,311)
Fatalities<-c(20,17,24,16,34,18,35)
rate=100*Fatalities/Persons.Involved
df<-data.frame(Years=Years,Persons.Involved=Persons.Involved,Fatalities=Fatalities,rate=rate)
print(df,row.names = FALSE)
Years Persons.Involved Fatalities rate
1998 281 20 7.117438
1999 248 17 6.854839
2000 301 24 7.973422
2001 276 16 5.797101
2002 295 34 11.525424
2003 231 18 7.792208
2004 311 35 11.254019
然后,我尝试按照Few在上述报告第7页建议的那样绘制图表(并按照OP的要求将计数绘制为柱状图,将率绘制为折线图):
The other less obvious solution, which works only for time series, is to convert all sets of values to a common quantitative scale by displaying percentage differences between each value and a reference (or index) value. For instance, select a particular point in time, such as the first interval that appears in the graph, and express each subsequent value as the percentage difference between it and the initial value. This is done by dividing the value at each point in time by the value for the initial point in time and then multiplying it by 100 to convert the rate to a percentage, as illustrated below.
df2<-df
df2$Persons.Involved <- 100*df$Persons.Involved/df$Persons.Involved[1]
df2$rate <- 100*df$rate/df$rate[1]
plot(ggplot(df2)+
geom_bar(aes(x=Years,weight=Persons.Involved))+
geom_line(aes(x=Years,y=rate,group=1))+
theme(text = element_text(size=30))
)
这就是结果:
但我不是很喜欢它,我不能轻易地给它加上一个传奇……
1 威廉森,杰德,等人。2005年北美登山事故。The Mountaineers Books, 2005。
下面的文章帮助我将ggplot2生成的两个图合并到单行上:
一页上的多个图(ggplot2)由Cookbook for R
下面是代码在这种情况下的样子:
p1 <-
ggplot() + aes(mns)+ geom_histogram(aes(y=..density..), binwidth=0.01, colour="black", fill="white") + geom_vline(aes(xintercept=mean(mns, na.rm=T)), color="red", linetype="dashed", size=1) + geom_density(alpha=.2)
p2 <-
ggplot() + aes(mns)+ geom_histogram( binwidth=0.01, colour="black", fill="white") + geom_vline(aes(xintercept=mean(mns, na.rm=T)), color="red", linetype="dashed", size=1)
multiplot(p1,p2,cols=2)
常见的用例有双y轴,例如,显示每月温度和降水的气体图。这里是一个简单的解决方案,从威震天的解决方案中推广,允许你设置变量的下限为零:
示例数据:
climate <- tibble(
Month = 1:12,
Temp = c(-4,-4,0,5,11,15,16,15,11,6,1,-3),
Precip = c(49,36,47,41,53,65,81,89,90,84,73,55)
)
将以下两个值设置为接近数据限制的值(您可以使用这些值来调整图形的位置;坐标轴仍然是正确的):
ylim.prim <- c(0, 180) # in this example, precipitation
ylim.sec <- c(-4, 18) # in this example, temperature
下面根据这些极限进行必要的计算,并制作出图本身:
b <- diff(ylim.prim)/diff(ylim.sec)
a <- ylim.prim[1] - b*ylim.sec[1]) # there was a bug here
ggplot(climate, aes(Month, Precip)) +
geom_col() +
geom_line(aes(y = a + Temp*b), color = "red") +
scale_y_continuous("Precipitation", sec.axis = sec_axis(~ (. - a)/b, name = "Temperature")) +
scale_x_continuous("Month", breaks = 1:12) +
ggtitle("Climatogram for Oslo (1961-1990)")
如果你想确保红线对应右边的y轴,你可以在代码中添加一个主题句:
ggplot(climate, aes(Month, Precip)) +
geom_col() +
geom_line(aes(y = a + Temp*b), color = "red") +
scale_y_continuous("Precipitation", sec.axis = sec_axis(~ (. - a)/b, name = "Temperature")) +
scale_x_continuous("Month", breaks = 1:12) +
theme(axis.line.y.right = element_line(color = "red"),
axis.ticks.y.right = element_line(color = "red"),
axis.text.y.right = element_text(color = "red"),
axis.title.y.right = element_text(color = "red")
) +
ggtitle("Climatogram for Oslo (1961-1990)")
右轴的颜色:
It seemingly appears to be a simple question but it boggles around 2 fundamental questions. A) How to deal with a multi-scalar data while presenting in a comparative chart, and secondly, B) whether this can be done without some thumb rule practices of R programming such as i) melting data, ii) faceting, iii) adding another layer to existing one. The solution given below satisfies both the above conditions as it deals data without having to rescale it and secondly, the techniques mentioned are not used.
这是结果,
如果有兴趣了解更多关于此方法的信息,请点击下面的链接。 如何绘制一个2 y轴图表与条形并排而不重新缩放数据
我们当然可以用R函数图来建立一个双y轴的图。
# pseudo dataset
df <- data.frame(x = seq(1, 1000, 1), y1 = sample.int(100, 1000, replace=T), y2 = sample(50, 1000, replace = T))
# plot first plot
with(df, plot(y1 ~ x, col = "red"))
# set new plot
par(new = T)
# plot second plot, but without axis
with(df, plot(y2 ~ x, type = "l", xaxt = "n", yaxt = "n", xlab = "", ylab = ""))
# define y-axis and put y-labs
axis(4)
with(df, mtext("y2", side = 4))