我想了解以下内容：给定一个日期（datetime对象），一周中对应的日期是什么？
例如，星期天是第一天，星期一是第二天。。等等
然后如果输入的内容类似于今天的日期。
实例
>>> today = datetime.datetime(2017, 10, 20)
>>> today.get_weekday() # what I look for
产量可能是6（因为现在是星期五）
当前回答
datetime库有时会出现strptime（）错误，所以我切换到dateutil库。下面是一个如何使用它的示例：
from dateutil import parser
parser.parse('January 11, 2010').strftime("%a")
您从中获得的输出是“Mon”。如果希望输出为“星期一”，请使用以下命令：
parser.parse('January 11, 2010').strftime("%A")
这对我很快奏效。我在使用日期时间库时遇到了问题，因为我想存储工作日名称而不是工作日编号，而使用日期时间的格式导致了问题。如果你对此没有问题，那太好了！如果你是这样的话，你可以明确地这样做，因为它的语法也更简单。希望这有帮助。
其他回答
假设你得到了日期、月份和年份，你可以做到：
import datetime
DayL = ['Mon','Tues','Wednes','Thurs','Fri','Satur','Sun']
date = DayL[datetime.date(year,month,day).weekday()] + 'day'
#Set day, month, year to your value
#Now, date is set as an actual day, not a number from 0 to 6.
print(date)
以下是如何将小端字符串日期列表转换为datetime：
import datetime, time
ls = ['31/1/2007', '14/2/2017']
for d in ls:
dt = datetime.datetime.strptime(d, "%d/%m/%Y")
print(dt)
print(dt.strftime("%A"))
假设您有timeStamp：字符串变量YYYY-MM-DD HH:MM:SS
步骤1：使用blow代码将其转换为dateTime函数。。。
df['timeStamp'] = pd.to_datetime(df['timeStamp'])
步骤2：现在您可以提取所有必需的功能，如下所示，这将为每个字段创建新的列-小时、月、星期、年、日期
df['Hour'] = df['timeStamp'].apply(lambda time: time.hour)
df['Month'] = df['timeStamp'].apply(lambda time: time.month)
df['Day of Week'] = df['timeStamp'].apply(lambda time: time.dayofweek)
df['Year'] = df['timeStamp'].apply(lambda t: t.year)
df['Date'] = df['timeStamp'].apply(lambda t: t.day)
1700/1/1之后的日期不需要导入的解决方案
def weekDay(year, month, day):
offset = [0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334]
week = ['Sunday',
'Monday',
'Tuesday',
'Wednesday',
'Thursday',
'Friday',
'Saturday']
afterFeb = 1
if month > 2: afterFeb = 0
aux = year - 1700 - afterFeb
# dayOfWeek for 1700/1/1 = 5, Friday
dayOfWeek = 5
# partial sum of days betweem current date and 1700/1/1
dayOfWeek += (aux + afterFeb) * 365
# leap year correction
dayOfWeek += aux / 4 - aux / 100 + (aux + 100) / 400
# sum monthly and day offsets
dayOfWeek += offset[month - 1] + (day - 1)
dayOfWeek %= 7
return dayOfWeek, week[dayOfWeek]
print weekDay(2013, 6, 15) == (6, 'Saturday')
print weekDay(1969, 7, 20) == (0, 'Sunday')
print weekDay(1945, 4, 30) == (1, 'Monday')
print weekDay(1900, 1, 1) == (1, 'Monday')
print weekDay(1789, 7, 14) == (2, 'Tuesday')
使用Canlendar模块
import calendar
a=calendar.weekday(year,month,day)
days=["MONDAY","TUESDAY","WEDNESDAY","THURSDAY","FRIDAY","SATURDAY","SUNDAY"]
print(days[a])
