我知道如何创建一个有String参数并返回int的方法的引用,它是:
Function<String, Integer>
然而,如果函数抛出异常,比如它被定义为:
Integer myMethod(String s) throws IOException
我该如何定义这个引用呢?
我知道如何创建一个有String参数并返回int的方法的引用,它是:
Function<String, Integer>
然而,如果函数抛出异常,比如它被定义为:
Integer myMethod(String s) throws IOException
我该如何定义这个引用呢?
当前回答
你可以使用ET。ET是一个用于异常转换/转换的小型Java 8库。
对于ET,它看起来是这样的:
// Do this once
ExceptionTranslator et = ET.newConfiguration().done();
...
// if your method returns something
Function<String, Integer> f = (t) -> et.withReturningTranslation(() -> myMethod(t));
// if your method returns nothing
Consumer<String> c = (t) -> et.withTranslation(() -> myMethod(t));
ExceptionTranslator实例是线程安全的,可以由多个组件共享。如果你喜欢,你可以配置更具体的异常转换规则(例如FooCheckedException -> BarRuntimeException)。 如果没有其他可用的规则,被检查的异常将自动转换为RuntimeException。
(声明:我是ET的作者)
其他回答
我会做一些一般的事情:
public interface Lambda {
@FunctionalInterface
public interface CheckedFunction<T> {
T get() throws Exception;
}
public static <T> T handle(CheckedFunction<T> supplier) {
try {
return supplier.get();
} catch (Exception exception) {
throw new RuntimeException(exception);
}
}
}
用法:
Lambda.handle(() -> method());
public void frankTest() {
int pageId= -1;
List<Book> users= null;
try {
//Does Not Compile: Object page=DatabaseConnection.getSpringConnection().queryForObject("SELECT * FROM bookmark_page", (rw, n) -> new Portal(rw.getInt("id"), "", users.parallelStream().filter(uu -> uu.getVbid() == rw.getString("user_id")).findFirst().get(), rw.getString("name")));
//Compiles:
Object page= DatabaseConnection.getSpringConnection().queryForObject("SELECT * FROM bookmark_page", (rw, n) -> {
try {
final Book bk= users.stream().filter(bp -> {
String name= null;
try {
name = rw.getString("name");
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return bp.getTitle().equals(name);
}).limit(1).collect(Collectors.toList()).get(0);
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return new Portal(rw.getInt("id"), "", users.get(0), rw.getString("name"));
} );
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
我使用一个名为unchecked()的重载实用程序函数来处理多个用例。
一些用法示例
unchecked(() -> new File("hello.txt").createNewFile());
boolean fileWasCreated = unchecked(() -> new File("hello.txt").createNewFile());
myFiles.forEach(unchecked(file -> new File(file.path).createNewFile()));
支持工具
public class UncheckedUtils {
@FunctionalInterface
public interface ThrowingConsumer<T> {
void accept(T t) throws Exception;
}
@FunctionalInterface
public interface ThrowingSupplier<T> {
T get() throws Exception;
}
@FunctionalInterface
public interface ThrowingRunnable {
void run() throws Exception;
}
public static <T> Consumer<T> unchecked(
ThrowingConsumer<T> throwingConsumer
) {
return i -> {
try {
throwingConsumer.accept(i);
} catch (Exception ex) {
throw new RuntimeException(ex);
}
};
}
public static <T> T unchecked(
ThrowingSupplier<T> throwingSupplier
) {
try {
return throwingSupplier.get();
} catch (Exception ex) {
throw new RuntimeException(ex);
}
}
public static void unchecked(
ThrowingRunnable throwing
) {
try {
throwing.run();
} catch (Exception ex) {
throw new RuntimeException(ex);
}
}
}
您需要执行以下操作之一。
If it's your code, then define your own functional interface that declares the checked exception: @FunctionalInterface public interface CheckedFunction<T, R> { R apply(T t) throws IOException; } and use it: void foo (CheckedFunction f) { ... } Otherwise, wrap Integer myMethod(String s) in a method that doesn't declare a checked exception: public Integer myWrappedMethod(String s) { try { return myMethod(s); } catch(IOException e) { throw new UncheckedIOException(e); } } and then: Function<String, Integer> f = (String t) -> myWrappedMethod(t); or: Function<String, Integer> f = (String t) -> { try { return myMethod(t); } catch(IOException e) { throw new UncheckedIOException(e); } };
如果你不介意使用第三方自由库(Vavr),你可以写
CheckedFunction1<String, Integer> f = this::myMethod;
它也有所谓的Try单子来处理错误:
Try(() -> f.apply("test")) // results in a Success(Integer) or Failure(Throwable)
.map(i -> ...) // only executed on Success
...
请在这里阅读更多。
声明:我是Vavr的创造者。