我知道如何创建一个有String参数并返回int的方法的引用,它是:
Function<String, Integer>
然而,如果函数抛出异常,比如它被定义为:
Integer myMethod(String s) throws IOException
我该如何定义这个引用呢?
我知道如何创建一个有String参数并返回int的方法的引用,它是:
Function<String, Integer>
然而,如果函数抛出异常,比如它被定义为:
Integer myMethod(String s) throws IOException
我该如何定义这个引用呢?
当前回答
我在课堂上遇到了这个问题。forName和Class。newInstance在lambda中,所以我做了:
public Object uncheckedNewInstanceForName (String name) {
try {
return Class.forName(name).newInstance();
}
catch (ClassNotFoundException | InstantiationException | IllegalAccessException e) {
throw new RuntimeException(e);
}
}
在lambda中,我没有调用Class.forName("myClass").newInstance(),而是调用uncheckedNewInstanceForName ("myClass")
其他回答
Sneaky throw成语允许绕过Lambda表达式的CheckedException。将CheckedException包装在RuntimeException中不利于严格的错误处理。
它可以用作Java集合中使用的Consumer函数。
下面是jib答案的一个简单改进版本。
import static Throwing.rethrow;
@Test
public void testRethrow() {
thrown.expect(IOException.class);
thrown.expectMessage("i=3");
Arrays.asList(1, 2, 3).forEach(rethrow(e -> {
int i = e.intValue();
if (i == 3) {
throw new IOException("i=" + i);
}
}));
}
这只是在重新抛出中包装lambda。它使CheckedException重新抛出在lambda中抛出的任何异常。
public final class Throwing {
private Throwing() {}
@Nonnull
public static <T> Consumer<T> rethrow(@Nonnull final ThrowingConsumer<T> consumer) {
return consumer;
}
/**
* The compiler sees the signature with the throws T inferred to a RuntimeException type, so it
* allows the unchecked exception to propagate.
*
* http://www.baeldung.com/java-sneaky-throws
*/
@SuppressWarnings("unchecked")
@Nonnull
public static <E extends Throwable> void sneakyThrow(@Nonnull Throwable ex) throws E {
throw (E) ex;
}
}
在这里找到完整的代码和单元测试。
默认情况下,Java 8函数不允许抛出异常,正如在多个回答中所建议的那样,有许多方法来实现它,其中一种方法是:
@FunctionalInterface
public interface FunctionWithException<T, R, E extends Exception> {
R apply(T t) throws E;
}
定义为:
private FunctionWithException<String, Integer, IOException> myMethod = (str) -> {
if ("abc".equals(str)) {
throw new IOException();
}
return 1;
};
并在调用者方法中添加抛出或尝试/捕获相同的异常。
我在课堂上遇到了这个问题。forName和Class。newInstance在lambda中,所以我做了:
public Object uncheckedNewInstanceForName (String name) {
try {
return Class.forName(name).newInstance();
}
catch (ClassNotFoundException | InstantiationException | IllegalAccessException e) {
throw new RuntimeException(e);
}
}
在lambda中,我没有调用Class.forName("myClass").newInstance(),而是调用uncheckedNewInstanceForName ("myClass")
我使用一个名为unchecked()的重载实用程序函数来处理多个用例。
一些用法示例
unchecked(() -> new File("hello.txt").createNewFile());
boolean fileWasCreated = unchecked(() -> new File("hello.txt").createNewFile());
myFiles.forEach(unchecked(file -> new File(file.path).createNewFile()));
支持工具
public class UncheckedUtils {
@FunctionalInterface
public interface ThrowingConsumer<T> {
void accept(T t) throws Exception;
}
@FunctionalInterface
public interface ThrowingSupplier<T> {
T get() throws Exception;
}
@FunctionalInterface
public interface ThrowingRunnable {
void run() throws Exception;
}
public static <T> Consumer<T> unchecked(
ThrowingConsumer<T> throwingConsumer
) {
return i -> {
try {
throwingConsumer.accept(i);
} catch (Exception ex) {
throw new RuntimeException(ex);
}
};
}
public static <T> T unchecked(
ThrowingSupplier<T> throwingSupplier
) {
try {
return throwingSupplier.get();
} catch (Exception ex) {
throw new RuntimeException(ex);
}
}
public static void unchecked(
ThrowingRunnable throwing
) {
try {
throwing.run();
} catch (Exception ex) {
throw new RuntimeException(ex);
}
}
}
您需要执行以下操作之一。
If it's your code, then define your own functional interface that declares the checked exception: @FunctionalInterface public interface CheckedFunction<T, R> { R apply(T t) throws IOException; } and use it: void foo (CheckedFunction f) { ... } Otherwise, wrap Integer myMethod(String s) in a method that doesn't declare a checked exception: public Integer myWrappedMethod(String s) { try { return myMethod(s); } catch(IOException e) { throw new UncheckedIOException(e); } } and then: Function<String, Integer> f = (String t) -> myWrappedMethod(t); or: Function<String, Integer> f = (String t) -> { try { return myMethod(t); } catch(IOException e) { throw new UncheckedIOException(e); } };