这个问题也一直困扰着我;这就是我创建这个项目的原因。

用它你可以做:

final ThrowingFunction<String, Integer> f = yourMethodReferenceHere;

JDK总共定义了39个接口，它们都有类似的抛出功能;这些都是流中使用的@ functionalinterface(基本流，还有IntStream, LongStream和DoubleStream)。

当它们中的每一个都扩展了它们的非抛出对应对象时，你也可以直接在lambdas中使用它们:

myStringStream.map(f) // <-- works

默认行为是，当您抛出lambda抛出一个检查异常时，抛出一个ThrownByLambdaException，并将检查异常作为原因。因此，您可以捕捉到它并得到原因。

其他特性也可用。

public void frankTest() {
    int pageId= -1;

    List<Book> users= null;
    try {
        //Does Not Compile:  Object page=DatabaseConnection.getSpringConnection().queryForObject("SELECT * FROM bookmark_page", (rw, n) -> new Portal(rw.getInt("id"), "", users.parallelStream().filter(uu -> uu.getVbid() == rw.getString("user_id")).findFirst().get(), rw.getString("name")));

        //Compiles:
        Object page= DatabaseConnection.getSpringConnection().queryForObject("SELECT * FROM bookmark_page", (rw, n) -> { 
            try {
                final Book bk= users.stream().filter(bp -> { 
                    String name= null;
                    try {
                        name = rw.getString("name");
                    } catch (Exception e) {
                        // TODO Auto-generated catch block
                        e.printStackTrace();
                    }
                    return bp.getTitle().equals(name); 
                }).limit(1).collect(Collectors.toList()).get(0);
            } catch (Exception e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            return new Portal(rw.getInt("id"), "", users.get(0), rw.getString("name")); 
        } );
    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

这里已经贴出了很多很棒的回复。只是试图用不同的角度来解决问题。这只是我的两毛钱，如果我哪里说错了，请指正。

在FunctionalInterface中抛出子句不是一个好主意

我认为强制抛出IOException可能不是一个好主意，原因如下

This looks to me like an anti-pattern to Stream/Lambda. The whole idea is that the caller will decide what code to provide and how to handle the exception. In many scenarios, the IOException might not be applicable for the client. For example, if the client is getting value from cache/memory instead of performing actual I/O. Also, the exceptions handling in streams becomes really hideous. For example, here is my code will look like if I use your API acceptMyMethod(s -> { try { Integer i = doSomeOperation(s); return i; } catch (IOException e) { // try catch block because of throws clause // in functional method, even though doSomeOperation // might not be throwing any exception at all. e.printStackTrace(); } return null; }); Ugly isn't it? Moreover, as I mentioned in my first point, that the doSomeOperation method may or may not be throwing IOException (depending on the implementation of the client/caller), but because of the throws clause in your FunctionalInterface method, I always have to write the try-catch.

如果我知道这个API抛出IOException怎么办

Then probably we are confusing FunctionalInterface with typical Interfaces. If you know this API will throw IOException, then most probably you also know some default/abstract behavior as well. I think you should define an interface and deploy your library (with default/abstract implementation) as follows public interface MyAmazingAPI { Integer myMethod(String s) throws IOException; } But, the try-catch problem still exists for the client. If I use your API in stream, I still need to handle IOException in hideous try-catch block. Provide a default stream-friendly API as follows public interface MyAmazingAPI { Integer myMethod(String s) throws IOException; default Optional<Integer> myMethod(String s, Consumer<? super Exception> exceptionConsumer) { try { return Optional.ofNullable(this.myMethod(s)); } catch (Exception e) { if (exceptionConsumer != null) { exceptionConsumer.accept(e); } else { e.printStackTrace(); } } return Optional.empty(); } } The default method takes the consumer object as argument, which will be responsible to handle the exception. Now, from client's point of view, the code will look like this strStream.map(str -> amazingAPIs.myMethod(str, Exception::printStackTrace)) .filter(Optional::isPresent) .map(Optional::get).collect(toList()); Nice right? Of course, logger or other handling logic could be used instead of Exception::printStackTrace. You can also expose a method similar to https://docs.oracle.com/javase/8/docs/api/java/util/concurrent/CompletableFuture.html#exceptionally-java.util.function.Function- . Meaning that you can expose another method, which will contain the exception from previous method call. The disadvantage is that you are now making your APIs stateful, which means that you need to handle thread-safety and which will be eventually become a performance hit. Just an option to consider though.

免责声明:我还没有使用过Java 8，只是阅读过它。

Function<String, Integer>不抛出IOException，所以你不能在其中放入任何抛出IOException的代码。如果你正在调用一个期望Function<String, Integer>的方法，那么你传递给该方法的lambda不能抛出IOException，句号。你可以这样写一个lambda(我认为这是lambda语法，不确定):

(String s) -> {
    try {
        return myMethod(s);
    } catch (IOException ex) {
        throw new RuntimeException(ex);
        // (Or do something else with it...)
    }
}

或者，如果你传递lambda的方法是你自己写的，你可以定义一个新的函数接口，并使用它作为参数类型，而不是Function<String, Integer>:

public interface FunctionThatThrowsIOException<I, O> {
    O apply(I input) throws IOException;
}

我使用一个名为unchecked()的重载实用程序函数来处理多个用例。

一些用法示例

unchecked(() -> new File("hello.txt").createNewFile());

boolean fileWasCreated = unchecked(() -> new File("hello.txt").createNewFile());

myFiles.forEach(unchecked(file -> new File(file.path).createNewFile()));

支持工具

public class UncheckedUtils {

    @FunctionalInterface
    public interface ThrowingConsumer<T> {
        void accept(T t) throws Exception;
    }

    @FunctionalInterface
    public interface ThrowingSupplier<T> {
        T get() throws Exception;
    }

    @FunctionalInterface
    public interface ThrowingRunnable {
        void run() throws Exception;
    }

    public static <T> Consumer<T> unchecked(
            ThrowingConsumer<T> throwingConsumer
    ) {
        return i -> {
            try {
                throwingConsumer.accept(i);
            } catch (Exception ex) {
                throw new RuntimeException(ex);
            }
        };
    }

    public static <T> T unchecked(
            ThrowingSupplier<T> throwingSupplier
    ) {
        try {
            return throwingSupplier.get();
        } catch (Exception ex) {
            throw new RuntimeException(ex);
        }
    }

    public static void unchecked(
            ThrowingRunnable throwing
    ) {
        try {
            throwing.run();
        } catch (Exception ex) {
            throw new RuntimeException(ex);
        }
    }
}

默认情况下，Java 8函数不允许抛出异常，正如在多个回答中所建议的那样，有许多方法来实现它，其中一种方法是:

@FunctionalInterface
public interface FunctionWithException<T, R, E extends Exception> {
    R apply(T t) throws E;
}

定义为:

private FunctionWithException<String, Integer, IOException> myMethod = (str) -> {
    if ("abc".equals(str)) {
        throw new IOException();
    }
  return 1;
};

并在调用者方法中添加抛出或尝试/捕获相同的异常。