我知道如何创建一个有String参数并返回int的方法的引用,它是:

Function<String, Integer>

然而,如果函数抛出异常,比如它被定义为:

Integer myMethod(String s) throws IOException

我该如何定义这个引用呢?


当前回答

我会做一些一般的事情:

public interface Lambda {

    @FunctionalInterface
    public interface CheckedFunction<T> {

        T get() throws Exception;
    }

    public static <T> T handle(CheckedFunction<T> supplier) {
        try {
            return supplier.get();
        } catch (Exception exception) {
            throw new RuntimeException(exception);

        }
    }
}

用法:

 Lambda.handle(() -> method());

其他回答

public void frankTest() {
    int pageId= -1;

    List<Book> users= null;
    try {
        //Does Not Compile:  Object page=DatabaseConnection.getSpringConnection().queryForObject("SELECT * FROM bookmark_page", (rw, n) -> new Portal(rw.getInt("id"), "", users.parallelStream().filter(uu -> uu.getVbid() == rw.getString("user_id")).findFirst().get(), rw.getString("name")));

        //Compiles:
        Object page= DatabaseConnection.getSpringConnection().queryForObject("SELECT * FROM bookmark_page", (rw, n) -> { 
            try {
                final Book bk= users.stream().filter(bp -> { 
                    String name= null;
                    try {
                        name = rw.getString("name");
                    } catch (Exception e) {
                        // TODO Auto-generated catch block
                        e.printStackTrace();
                    }
                    return bp.getTitle().equals(name); 
                }).limit(1).collect(Collectors.toList()).get(0);
            } catch (Exception e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            return new Portal(rw.getInt("id"), "", users.get(0), rw.getString("name")); 
        } );
    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

Sneaky throw成语允许绕过Lambda表达式的CheckedException。将CheckedException包装在RuntimeException中不利于严格的错误处理。

它可以用作Java集合中使用的Consumer函数。

下面是jib答案的一个简单改进版本。

import static Throwing.rethrow;

@Test
public void testRethrow() {
    thrown.expect(IOException.class);
    thrown.expectMessage("i=3");

    Arrays.asList(1, 2, 3).forEach(rethrow(e -> {
        int i = e.intValue();
        if (i == 3) {
            throw new IOException("i=" + i);
        }
    }));
}

这只是在重新抛出中包装lambda。它使CheckedException重新抛出在lambda中抛出的任何异常。

public final class Throwing {
    private Throwing() {}

    @Nonnull
    public static <T> Consumer<T> rethrow(@Nonnull final ThrowingConsumer<T> consumer) {
        return consumer;
    }

    /**
     * The compiler sees the signature with the throws T inferred to a RuntimeException type, so it
     * allows the unchecked exception to propagate.
     * 
     * http://www.baeldung.com/java-sneaky-throws
     */
    @SuppressWarnings("unchecked")
    @Nonnull
    public static <E extends Throwable> void sneakyThrow(@Nonnull Throwable ex) throws E {
        throw (E) ex;
    }

}

在这里找到完整的代码和单元测试。

免责声明:我还没有使用过Java 8,只是阅读过它。

Function<String, Integer>不抛出IOException,所以你不能在其中放入任何抛出IOException的代码。如果你正在调用一个期望Function<String, Integer>的方法,那么你传递给该方法的lambda不能抛出IOException,句号。你可以这样写一个lambda(我认为这是lambda语法,不确定):

(String s) -> {
    try {
        return myMethod(s);
    } catch (IOException ex) {
        throw new RuntimeException(ex);
        // (Or do something else with it...)
    }
}

或者,如果你传递lambda的方法是你自己写的,你可以定义一个新的函数接口,并使用它作为参数类型,而不是Function<String, Integer>:

public interface FunctionThatThrowsIOException<I, O> {
    O apply(I input) throws IOException;
}

你可以使用ET。ET是一个用于异常转换/转换的小型Java 8库。

对于ET,它看起来是这样的:

// Do this once
ExceptionTranslator et = ET.newConfiguration().done();

...

// if your method returns something
Function<String, Integer> f = (t) -> et.withReturningTranslation(() -> myMethod(t));

// if your method returns nothing
Consumer<String> c = (t) -> et.withTranslation(() -> myMethod(t));

ExceptionTranslator实例是线程安全的,可以由多个组件共享。如果你喜欢,你可以配置更具体的异常转换规则(例如FooCheckedException -> BarRuntimeException)。 如果没有其他可用的规则,被检查的异常将自动转换为RuntimeException。

(声明:我是ET的作者)

然而,你可以创建自己的FunctionalInterface,抛出如下..

@FunctionalInterface
public interface UseInstance<T, X extends Throwable> {
  void accept(T instance) throws X;
}

然后使用Lambdas或引用实现它,如下所示。

import java.io.FileWriter;
import java.io.IOException;

//lambda expressions and the execute around method (EAM) pattern to
//manage resources

public class FileWriterEAM  {
  private final FileWriter writer;

  private FileWriterEAM(final String fileName) throws IOException {
    writer = new FileWriter(fileName);
  }
  private void close() throws IOException {
    System.out.println("close called automatically...");
    writer.close();
  }
  public void writeStuff(final String message) throws IOException {
    writer.write(message);
  }
  //...

  public static void use(final String fileName, final UseInstance<FileWriterEAM, IOException> block) throws IOException {

    final FileWriterEAM writerEAM = new FileWriterEAM(fileName);    
    try {
      block.accept(writerEAM);
    } finally {
      writerEAM.close();
    }
  }

  public static void main(final String[] args) throws IOException {

    FileWriterEAM.use("eam.txt", writerEAM -> writerEAM.writeStuff("sweet"));

    FileWriterEAM.use("eam2.txt", writerEAM -> {
        writerEAM.writeStuff("how");
        writerEAM.writeStuff("sweet");      
      });

    FileWriterEAM.use("eam3.txt", FileWriterEAM::writeIt);     

  }


 void writeIt() throws IOException{
     this.writeStuff("How ");
     this.writeStuff("sweet ");
     this.writeStuff("it is");

 }

}