我想要一个5个字符的字符串,由从集合[a-zA-Z0-9]中随机选取的字符组成。
用JavaScript实现这一点的最佳方法是什么?
我想要一个5个字符的字符串,由从集合[a-zA-Z0-9]中随机选取的字符组成。
用JavaScript实现这一点的最佳方法是什么?
当前回答
function generate(length) {
var letters = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z","A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z","0","1","2","3","4","5","6","7","8","9"];
var IDtext = "";
var i = 0;
while (i < length) {
var letterIndex = Math.floor(Math.random() * letters.length);
var letter = letters[letterIndex];
IDtext = IDtext + letter;
i++;
}
console.log(IDtext)
}
其他回答
递归解决方案:
function generateRamdomId (seedStr) {
const len = seedStr.length
console.log('possibleStr', seedStr , ' len ', len)
if(len <= 1){
return seedStr
}
const randomValidIndex = Math.floor(Math.random() * len)
const randomChar = seedStr[randomValidIndex]
const chunk1 = seedStr.slice(0, randomValidIndex)
const chunk2 = seedStr.slice(randomValidIndex +1)
const possibleStrWithoutRandomChar = chunk1.concat(chunk2)
return randomChar + generateRamdomId(possibleStrWithoutRandomChar)
}
你可以用你想要的种子,如果你不想,不要重复字符。实例
generateRandomId("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789")
生成包含aA zZ和0-9字符集合的随机字符串。只需使用长度参数调用此函数。
所以要回答这个问题:generateRandomString(5)
generateRandomString(length){
let result = "", seeds
for(let i = 0; i < length - 1; i++){
//Generate seeds array, that will be the bag from where randomly select generated char
seeds = [
Math.floor(Math.random() * 10) + 48,
Math.floor(Math.random() * 25) + 65,
Math.floor(Math.random() * 25) + 97
]
//Choise randomly from seeds, convert to char and append to result
result += String.fromCharCode(seeds[Math.floor(Math.random() * 3)])
}
return result
}
生成不带数字的字符串的版本:
generateRandomString(length){
let result = "", seeds
for(let i = 0; i < length - 1; i++){
seeds = [
Math.floor(Math.random() * 25) + 65,
Math.floor(Math.random() * 25) + 97
]
result += String.fromCharCode(seeds[Math.floor(Math.random() * 2)])
}
return result
}
我想这会对你有用:
函数makeid(长度){let result=“”;const characters=‘EFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvxyz0123456789’;常量字符长度=字符长度;让计数器=0;while(计数器<长度){result+=characters.charAt(Math.floor(Math.random()*charactersLength));计数器+=1;}返回结果;}console.log(makeid(5));
试试这个,我每次都用的:
函数myFunction(){var hash=“abcdefghijklmnopqrstuvxyzABCDEFGHIJKLMNOPQRSTUVWXYZ012346789”;var random8=“”;对于(变量i=0;i<5;i++){random8+=哈希[parseInt(Math.random()*hash.length)];}控制台日志(random8);document.getElementById(“demo”).innerHTML=“您的5个字符串==>”+random8;} <!DOCTYPE html><html><body><p>单击按钮生成5个字符的随机字符串</p><button onclick=“myFunction()”>单击我</button><p id=“demo”></p></body></html>
你可以使用coderain。这是一个根据给定模式生成随机代码的库。使用#作为大写和小写字符以及数字的占位符:
var cr = new CodeRain("#####");
console.log(cr.next());
还有其他占位符,如A表示大写字母或9表示数字。
可能有用的是,调用.next()将始终为您提供唯一的结果,因此您不必担心重复。
这里是一个生成唯一随机代码列表的演示应用程序。
完全披露:我是《代码雨》的作者。