我想要一个5个字符的字符串,由从集合[a-zA-Z0-9]中随机选取的字符组成。

用JavaScript实现这一点的最佳方法是什么?


当前回答

生成10个字符长的字符串。长度由参数设置(默认值为10)。

function random_string_generator(len) {
var len = len || 10;
var str = '';
var i = 0;

for(i=0; i<len; i++) {
    switch(Math.floor(Math.random()*3+1)) {
        case 1: // digit
            str += (Math.floor(Math.random()*9)).toString();
        break;

        case 2: // small letter
            str += String.fromCharCode(Math.floor(Math.random()*26) + 97); //'a'.charCodeAt(0));
        break;

        case 3: // big letter
            str += String.fromCharCode(Math.floor(Math.random()*26) + 65); //'A'.charCodeAt(0));
        break;

        default:
        break;
    }
}
return str;
}

其他回答

仅仅一个简单的map或reduce实现就足够了:

const charset: string =
  "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";

const random1: string = [...Array(5)]
  .map((_) => charset[Math.floor(Math.random() * charset.length)])
  .join("");

const random2: string = [...Array(5)]
  .reduce<string>(
    (acc) => acc += charset[Math.floor(Math.random() * charset.length)],
    "",
  );

这是肯定的

<script language="javascript" type="text/javascript">
function randomString() {
 var chars = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXTZabcdefghiklmnopqrstuvwxyz";
 var string_length = 8;
 var randomstring = '';
 for (var i=0; i<string_length; i++) {
  var rnum = Math.floor(Math.random() * chars.length);
  randomstring += chars.substring(rnum,rnum+1);
 }
 document.randform.randomfield.value = randomstring;
}
</script>

您可以使用base64:

function randomString(length)
{
    var rtn = "";

    do {
        rtn += btoa("" + Math.floor(Math.random() * 100000)).substring(0, length);
    }
    while(rtn.length < length);

    return rtn;
}

函数randomstring(L){var s=“”;var randomchar=函数(){var n=数学地板(Math.random()*62);如果(n<10)返回n//1-10如果(n<36)返回String.fromCharCode(n+55)//A-Z型return String.fromCharCode(n+61)//a-z型}而(s.length<L)s+=randomchar();返回s;}console.log(随机字符串(5));

以下是CoffeeScript中的示例:

String::add_Random_Letters   = (size )->
                                         charSet = 'abcdefghijklmnopqrstuvwxyz'
                                         @ + (charSet[Math.floor(Math.random() * charSet.length)]  for i in [1..size]).join('')

可以使用

value = "abc_"
value_with_exta_5_random_letters = value.add_Random_Letters(5)