我想要一个5个字符的字符串，由从集合[a-zA-Z0-9]中随机选取的字符组成。
用JavaScript实现这一点的最佳方法是什么？
当前回答
随机unicode字符串
此方法将返回一个随机字符串，其中包含任何受支持的unicode字符，这不是OP要求的100%，而是我想要的：
function randomUnicodeString(length){
return Array.from({length: length}, ()=>{
return String.fromCharCode(Math.floor(Math.random() * (65536)))
}).join('')
}
根本原因
这是谷歌搜索“随机字符串javascript”时的最高结果，但OP只要求a-zA-Z0-9。
其他回答
下面这个怎么样。。。这将产生真正随机的值：
function getRandomStrings(length) {
const value = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789';
const randoms = [];
for(let i=0; i < length; i++) {
randoms.push(value[Math.floor(Math.random()*value.length)]);
}
return randoms.join('');
}
但如果您在ES6中寻找一个较短的语法：
const getRandomStrings = length => Math.random().toString(36).substr(-length);
随机unicode字符串
此方法将返回一个随机字符串，其中包含任何受支持的unicode字符，这不是OP要求的100%，而是我想要的：
function randomUnicodeString(length){
return Array.from({length: length}, ()=>{
return String.fromCharCode(Math.floor(Math.random() * (65536)))
}).join('')
}
根本原因
这是谷歌搜索“随机字符串javascript”时的最高结果，但OP只要求a-zA-Z0-9。
简单方法：
function randomString(length) {
let chars = [], output = '';
for (let i = 32; i < 127; i ++) {
chars.push(String.fromCharCode(i));
}
for (let i = 0; i < length; i ++) {
output += chars[Math.floor(Math.random() * chars.length )];
}
return output;
}
如果您想要更多或更少的字符，请将“127”更改为其他字符。
function generate(length) {
var letters = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z","A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z","0","1","2","3","4","5","6","7","8","9"];
var IDtext = "";
var i = 0;
while (i < length) {
var letterIndex = Math.floor(Math.random() * letters.length);
var letter = letters[letterIndex];
IDtext = IDtext + letter;
i++;
}
console.log(IDtext)
}
[..."abcdefghijklmnopqrsuvwxyz0123456789"].map((e, i, a) => a[Math.floor(Math.random() * a.length)]).join('')
