我想要一个5个字符的字符串,由从集合[a-zA-Z0-9]中随机选取的字符组成。

用JavaScript实现这一点的最佳方法是什么?


当前回答

为了从一个数组中生成一个散列作为一个盐,[0,1,2,3]在这个例子中,通过这种方式,我们可以稍后检索散列来填充一个条件。

只需输入一个随机数组,或作为数组的额外安全和快速指纹。

/*该方法非常快速,适用于密集循环*//*返回大小写混合字符*//*这将始终输出相同的哈希,因为salt数组是相同的*/控制台日志(btoa(String.fromCharCode(…新Uint8Array([0,1,2,3])))/*始终输出此处的随机十六进制哈希:30个字符*/控制台日志(btoa(String.fromCharCode(…new Uint8Array(Array(30).fill().map(()=>Math.round(Math.random()*30)))))

使用加密API中的HMAC,了解更多信息:https://stackoverflow.com/a/56416039/2494754

其他回答

"12345".split('').map(function(){return 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789'.charAt(Math.floor(62*Math.random()));}).join('');

//or

String.prototype.rand = function() {return this.split('').map(function(){return 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789'.charAt(Math.floor(62*Math.random()));}).join('');};

将生成长度为第一个/调用字符串的随机字母数字字符串

function generate(length) {
  var letters = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z","A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z","0","1","2","3","4","5","6","7","8","9"];
  var IDtext = "";
  var i = 0;
  while (i < length) {
    var letterIndex = Math.floor(Math.random() * letters.length);
    var letter = letters[letterIndex];
    IDtext = IDtext + letter;
    i++;
  }
  console.log(IDtext)
}

改进了上面@Andrew的回答:

Array.from({ length : 1 }, () => Math.random().toString(36)[2]).join('');

随机数的基数36转换是不一致的,因此选择一个标记可以解决这个问题。您可以使用所需的确切长度更改字符串的长度。

这是我创建的方法。它将创建一个包含大小写字符的字符串。此外,我还包含了将创建字母数字字符串的函数。

工作示例:http://jsfiddle.net/greatbigmassive/vhsxs/(仅限alpha)http://jsfiddle.net/greatbigmassive/PJwg8/(字母数字)

function randString(x){
    var s = "";
    while(s.length<x&&x>0){
        var r = Math.random();
        s+= String.fromCharCode(Math.floor(r*26) + (r>0.5?97:65));
    }
    return s;
}

2015年7月升级这做了同样的事情,但更有意义,包括所有字母。

var s = "";
while(s.length<x&&x>0){
    v = Math.random()<0.5?32:0;
    s += String.fromCharCode(Math.round(Math.random()*((122-v)-(97-v))+(97-v)));
}

这将在变量c中存储5个字母数字字符。

for(var c = ''; c.length < 5;) c += Math.random().toString(36).substr(2, 1)