我的程序在后台线程中执行一些网络活动。在开始之前,它会弹出一个进度对话框。该对话框在处理程序上被解除。这一切都很好,除了当对话框打开时屏幕方向发生变化(背景线程正在运行)。此时,应用程序要么崩溃,要么死锁,要么进入一个奇怪的阶段,在所有线程被杀死之前,应用程序根本无法工作。

我如何处理屏幕方向的变化优雅?

下面的示例代码大致匹配我的实际程序:

public class MyAct extends Activity implements Runnable {
    public ProgressDialog mProgress;

    // UI has a button that when pressed calls send

    public void send() {
         mProgress = ProgressDialog.show(this, "Please wait", 
                      "Please wait", 
                      true, true);
        Thread thread = new Thread(this);
        thread.start();
    }

    public void run() {
        Thread.sleep(10000);
        Message msg = new Message();
        mHandler.sendMessage(msg);
    }

    private final Handler mHandler = new Handler() {
        @Override
        public void handleMessage(Message msg) {
            mProgress.dismiss();
        }
    };
}

栈:

E/WindowManager(  244): Activity MyAct has leaked window com.android.internal.policy.impl.PhoneWindow$DecorView@433b7150 that was originally added here
E/WindowManager(  244): android.view.WindowLeaked: Activity MyAct has leaked window com.android.internal.policy.impl.PhoneWindow$DecorView@433b7150 that was originally added here
E/WindowManager(  244):     at android.view.ViewRoot.<init>(ViewRoot.java:178)
E/WindowManager(  244):     at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:147)
E/WindowManager(  244):     at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:90)
E/WindowManager(  244):     at android.view.Window$LocalWindowManager.addView(Window.java:393)
E/WindowManager(  244):     at android.app.Dialog.show(Dialog.java:212)
E/WindowManager(  244):     at android.app.ProgressDialog.show(ProgressDialog.java:103)
E/WindowManager(  244):     at android.app.ProgressDialog.show(ProgressDialog.java:91)
E/WindowManager(  244):     at MyAct.send(MyAct.java:294)
E/WindowManager(  244):     at MyAct$4.onClick(MyAct.java:174)
E/WindowManager(  244):     at android.view.View.performClick(View.java:2129)
E/WindowManager(  244):     at android.view.View.onTouchEvent(View.java:3543)
E/WindowManager(  244):     at android.widget.TextView.onTouchEvent(TextView.java:4664)
E/WindowManager(  244):     at android.view.View.dispatchTouchEvent(View.java:3198)

我已经尝试在onSaveInstanceState中取消进度对话框,但这只是防止了立即崩溃。背景线程仍在运行,UI处于部分绘制状态。需要在它重新开始工作之前杀死整个应用程序。


当前回答

我是这样做的:

    package com.palewar;
    import android.app.Activity;
    import android.app.ProgressDialog;
    import android.os.Bundle;
    import android.os.Handler;
    import android.os.Message;

    public class ThreadActivity extends Activity {


        static ProgressDialog dialog;
        private Thread downloadThread;
        final static Handler handler = new Handler() {

            @Override
            public void handleMessage(Message msg) {

                super.handleMessage(msg);

                dialog.dismiss();

            }

        };

        protected void onDestroy() {
    super.onDestroy();
            if (dialog != null && dialog.isShowing()) {
                dialog.dismiss();
                dialog = null;
            }

        }

        /** Called when the activity is first created. */
        @Override
        public void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.main);

            downloadThread = (Thread) getLastNonConfigurationInstance();
            if (downloadThread != null && downloadThread.isAlive()) {
                dialog = ProgressDialog.show(ThreadActivity.this, "",
                        "Signing in...", false);
            }

            dialog = ProgressDialog.show(ThreadActivity.this, "",
                    "Signing in ...", false);

            downloadThread = new MyThread();
            downloadThread.start();
            // processThread();
        }

        // Save the thread
        @Override
        public Object onRetainNonConfigurationInstance() {
            return downloadThread;
        }


        static public class MyThread extends Thread {
            @Override
            public void run() {

                try {
                    // Simulate a slow network
                    try {
                        new Thread().sleep(5000);
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                    handler.sendEmptyMessage(0);

                } finally {

                }
            }
        }

    }

你也可以试着让我知道它对你是否有效

其他回答

看起来太“快速和肮脏”了,所以请指出缺点,但我发现有用的是……

在我的AsyncTask的onPostExecute方法中,我简单地包装了`。try/catch块中的进度对话框(带有空捕获)的Dismiss ',然后简单地忽略所引发的异常。似乎是错误的,但似乎没有不良影响(至少对于我随后所做的事情,这是启动另一个活动,将我的长时间运行查询的结果传递为一个额外)

诀窍是在onPreExecute/onPostExecute期间像往常一样在AsyncTask中显示/解散对话框,尽管在方向改变的情况下,在活动中创建/显示一个对话框的新实例,并将其引用传递给任务。

public class MainActivity extends Activity {
    private Button mButton;
    private MyTask mTask = null;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        MyTask task = (MyTask) getLastNonConfigurationInstance();
        if(task != null){
            mTask = task;
            mTask.mContext = this;
            mTask.mDialog = ProgressDialog.show(this, "", "", true);        
        }

        mButton = (Button) findViewById(R.id.button1);
        mButton.setOnClickListener(new View.OnClickListener(){
            public void onClick(View v){
                mTask = new MyTask(MainActivity.this);
                mTask.execute();
            }
        });
    }


    @Override
    public Object onRetainNonConfigurationInstance() {
        String str = "null";
        if(mTask != null){
            str = mTask.toString();
            mTask.mDialog.dismiss();
        }
        Toast.makeText(this, str, Toast.LENGTH_SHORT).show();
        return mTask;
    }



    private class MyTask extends AsyncTask<Void, Void, Void>{
        private ProgressDialog mDialog;
        private MainActivity mContext;


        public MyTask(MainActivity context){
            super();
            mContext = context;
        }


        protected void onPreExecute() {
            mDialog = ProgressDialog.show(MainActivity.this, "", "", true);
        }

        protected void onPostExecute(Void result) {
            mContext.mTask = null;
            mDialog.dismiss();
        }


        @Override
        protected Void doInBackground(Void... params) {
            SystemClock.sleep(5000);
            return null;
        }       
    }
}

最简单和最灵活的解决方案是使用带有ProgressBar静态引用的AsyncTask。这为方向更改问题提供了一个封装的、因此可重用的解决方案。这个解决方案很好地帮助我完成了各种异步任务,包括互联网下载、与服务通信和文件系统扫描。该解决方案已经在多个安卓版本和手机型号上进行了良好的测试。完整的演示可以在DownloadFile.java中找到

下面是一个概念示例

public class SimpleAsync extends AsyncTask<String, Integer, String> {
    private static ProgressDialog mProgressDialog = null;
    private final Context mContext;

    public SimpleAsync(Context context) {
        mContext = context;
        if ( mProgressDialog != null ) {
            onPreExecute();
        }
    }

    @Override
    protected void onPreExecute() {
        mProgressDialog = new ProgressDialog( mContext );
        mProgressDialog.show();
    }

    @Override
    protected void onPostExecute(String result) {
        if ( mProgressDialog != null ) {
            mProgressDialog.dismiss();
            mProgressDialog = null;
        }
    }

    @Override
    protected void onProgressUpdate(Integer... progress) {
        mProgressDialog.setProgress( progress[0] );
    }

    @Override
    protected String doInBackground(String... sUrl) {
        // Do some work here
        publishProgress(1);
        return null;
    }

    public void dismiss() {
        if ( mProgressDialog != null ) {
            mProgressDialog.dismiss();
        }
    }
}

在Android Activity中的使用很简单

public class MainActivity extends Activity {
    DemoServiceClient mClient = null;
    DownloadFile mDownloadFile = null;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate( savedInstanceState );
        setContentView( R.layout.main );
        mDownloadFile = new DownloadFile( this );

        Button downloadButton = (Button) findViewById( R.id.download_file_button );
        downloadButton.setOnClickListener( new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                mDownloadFile.execute( "http://www.textfiles.com/food/bakebred.txt");
            }
        });
    }

    @Override
    public void onPause() {
        super.onPause();
        mDownloadFile.dismiss();
    }
}

如果你创建了一个后台服务来完成所有繁重的工作(tcp请求/响应,解组),视图和活动可以被销毁并重新创建,而不会泄漏窗口或丢失数据。这允许Android推荐的行为,即在每次配置更改时销毁一个Activity。对于每个方向变化)。

它有点复杂,但它是调用服务器请求、数据预处理/后处理等的最佳方式。

您甚至可以使用您的服务将每个请求排队到服务器,因此它使处理这些事情变得简单和高效。

开发指南有一个关于服务的完整章节。

这是一个非常古老的问题,出于某种原因出现在侧栏上。

如果后台任务只需要在活动处于前台时存活,“新的”解决方案是在保留的片段中托管后台线程(或者,最好是AsyncTask),如本开发指南和大量q&a中所述。

如果活动因配置更改而被销毁,则保留的片段将继续存在,但当活动在后台或后台堆栈中被销毁时则不存在。因此,如果onPause()中的isChangingConfigurations()为false,后台任务仍然应该被中断。