我的程序在后台线程中执行一些网络活动。在开始之前,它会弹出一个进度对话框。该对话框在处理程序上被解除。这一切都很好,除了当对话框打开时屏幕方向发生变化(背景线程正在运行)。此时,应用程序要么崩溃,要么死锁,要么进入一个奇怪的阶段,在所有线程被杀死之前,应用程序根本无法工作。

我如何处理屏幕方向的变化优雅?

下面的示例代码大致匹配我的实际程序:

public class MyAct extends Activity implements Runnable {
    public ProgressDialog mProgress;

    // UI has a button that when pressed calls send

    public void send() {
         mProgress = ProgressDialog.show(this, "Please wait", 
                      "Please wait", 
                      true, true);
        Thread thread = new Thread(this);
        thread.start();
    }

    public void run() {
        Thread.sleep(10000);
        Message msg = new Message();
        mHandler.sendMessage(msg);
    }

    private final Handler mHandler = new Handler() {
        @Override
        public void handleMessage(Message msg) {
            mProgress.dismiss();
        }
    };
}

栈:

E/WindowManager(  244): Activity MyAct has leaked window com.android.internal.policy.impl.PhoneWindow$DecorView@433b7150 that was originally added here
E/WindowManager(  244): android.view.WindowLeaked: Activity MyAct has leaked window com.android.internal.policy.impl.PhoneWindow$DecorView@433b7150 that was originally added here
E/WindowManager(  244):     at android.view.ViewRoot.<init>(ViewRoot.java:178)
E/WindowManager(  244):     at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:147)
E/WindowManager(  244):     at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:90)
E/WindowManager(  244):     at android.view.Window$LocalWindowManager.addView(Window.java:393)
E/WindowManager(  244):     at android.app.Dialog.show(Dialog.java:212)
E/WindowManager(  244):     at android.app.ProgressDialog.show(ProgressDialog.java:103)
E/WindowManager(  244):     at android.app.ProgressDialog.show(ProgressDialog.java:91)
E/WindowManager(  244):     at MyAct.send(MyAct.java:294)
E/WindowManager(  244):     at MyAct$4.onClick(MyAct.java:174)
E/WindowManager(  244):     at android.view.View.performClick(View.java:2129)
E/WindowManager(  244):     at android.view.View.onTouchEvent(View.java:3543)
E/WindowManager(  244):     at android.widget.TextView.onTouchEvent(TextView.java:4664)
E/WindowManager(  244):     at android.view.View.dispatchTouchEvent(View.java:3198)

我已经尝试在onSaveInstanceState中取消进度对话框,但这只是防止了立即崩溃。背景线程仍在运行,UI处于部分绘制状态。需要在它重新开始工作之前杀死整个应用程序。


当前回答

对于这些问题,我想出了一个坚如磐石的解决方案,它符合“Android方式”。我使用IntentService模式进行所有长时间运行的操作。

也就是说,我的活动广播意图,IntentService负责工作,将数据保存在DB中,然后广播粘性意图。粘性部分很重要,即使Activity在用户启动工作后暂停,并且错过了来自IntentService的实时广播,我们仍然可以响应并从调用Activity中获取数据。progressdialog可以很好地使用onSaveInstanceState()与此模式一起工作。

Basically, you need to save a flag that you have a progress dialog running in the saved instance bundle. Do not save the progress dialog object because this will leak the entire Activity. To have a persistent handle to the progress dialog, I store it as a weak reference in the application object. On orientation change or anything else that causes the Activity to pause (phone call, user hits home etc.) and then resume, I dismiss the old dialog and recreate a new dialog in the newly created Activity.

对于无限进度对话框来说,这很容易。对于进度条样式,您必须将最后一个已知的进度放在bundle中,并将您在活动中本地使用的任何信息用于跟踪进度。在恢复进度时,您将使用此信息以与之前相同的状态重新生成进度条,然后根据当前状态进行更新。

总之,将长时间运行的任务放到IntentService中,再加上明智地使用onSaveInstanceState(),可以让你有效地跟踪对话框,并在活动生命周期事件中恢复对话框。活动代码的相关部分如下。您还需要BroadcastReceiver中的逻辑来适当地处理Sticky意图,但这超出了本文的范围。

public void doSignIn(View view) {
    waiting=true;
    AppClass app=(AppClass) getApplication();
    String logingon=getString(R.string.signon);
    app.Dialog=new WeakReference<ProgressDialog>(ProgressDialog.show(AddAccount.this, "", logingon, true));
    ...
}

@Override
protected void onSaveInstanceState(Bundle saveState) {
    super.onSaveInstanceState(saveState);
    saveState.putBoolean("waiting",waiting);
}

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    if(savedInstanceState!=null) {
        restoreProgress(savedInstanceState);    
    }
    ...
}

private void restoreProgress(Bundle savedInstanceState) {
    waiting=savedInstanceState.getBoolean("waiting");
    if (waiting) {
        AppClass app=(AppClass) getApplication();
        ProgressDialog refresher=(ProgressDialog) app.Dialog.get();
        refresher.dismiss();
        String logingon=getString(R.string.signon);
        app.Dialog=new WeakReference<ProgressDialog>(ProgressDialog.show(AddAccount.this, "", logingon, true));
    }
}

其他回答

最简单和最灵活的解决方案是使用带有ProgressBar静态引用的AsyncTask。这为方向更改问题提供了一个封装的、因此可重用的解决方案。这个解决方案很好地帮助我完成了各种异步任务,包括互联网下载、与服务通信和文件系统扫描。该解决方案已经在多个安卓版本和手机型号上进行了良好的测试。完整的演示可以在DownloadFile.java中找到

下面是一个概念示例

public class SimpleAsync extends AsyncTask<String, Integer, String> {
    private static ProgressDialog mProgressDialog = null;
    private final Context mContext;

    public SimpleAsync(Context context) {
        mContext = context;
        if ( mProgressDialog != null ) {
            onPreExecute();
        }
    }

    @Override
    protected void onPreExecute() {
        mProgressDialog = new ProgressDialog( mContext );
        mProgressDialog.show();
    }

    @Override
    protected void onPostExecute(String result) {
        if ( mProgressDialog != null ) {
            mProgressDialog.dismiss();
            mProgressDialog = null;
        }
    }

    @Override
    protected void onProgressUpdate(Integer... progress) {
        mProgressDialog.setProgress( progress[0] );
    }

    @Override
    protected String doInBackground(String... sUrl) {
        // Do some work here
        publishProgress(1);
        return null;
    }

    public void dismiss() {
        if ( mProgressDialog != null ) {
            mProgressDialog.dismiss();
        }
    }
}

在Android Activity中的使用很简单

public class MainActivity extends Activity {
    DemoServiceClient mClient = null;
    DownloadFile mDownloadFile = null;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate( savedInstanceState );
        setContentView( R.layout.main );
        mDownloadFile = new DownloadFile( this );

        Button downloadButton = (Button) findViewById( R.id.download_file_button );
        downloadButton.setOnClickListener( new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                mDownloadFile.execute( "http://www.textfiles.com/food/bakebred.txt");
            }
        });
    }

    @Override
    public void onPause() {
        super.onPause();
        mDownloadFile.dismiss();
    }
}

我尝试执行jfelectron的解决方案,因为它是“解决这些问题的坚如磐石的解决方案,符合‘Android方式’”,但我花了一些时间来查找并整合所有提到的元素。最终得到了这个略有不同的,我认为更优雅的解决方案,完整地贴在这里。

使用从活动中触发的IntentService在单独的线程上执行长时间运行的任务。该服务向更新对话框的活动发出sticky Broadcast intent。Activity使用showDialog(), onCreateDialog()和onPrepareDialog()来消除在应用程序对象或savedInstanceState包中传递持久化数据的需要。无论应用程序如何中断,这都应该工作。

活动类:

public class TesterActivity extends Activity {
private ProgressDialog mProgressDialog;
private static final int PROGRESS_DIALOG = 0;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    Button b = (Button) this.findViewById(R.id.test_button);
    b.setOnClickListener(new OnClickListener() {
        public void onClick(View v) {
            buttonClick();
        }
    });
}

private void buttonClick(){
    clearPriorBroadcast();
    showDialog(PROGRESS_DIALOG);
    Intent svc = new Intent(this, MyService.class);
    startService(svc);
}

protected Dialog onCreateDialog(int id) {
    switch(id) {
    case PROGRESS_DIALOG:
        mProgressDialog = new ProgressDialog(TesterActivity.this);
        mProgressDialog.setProgressStyle(ProgressDialog.STYLE_HORIZONTAL);
        mProgressDialog.setMax(MyService.MAX_COUNTER);
        mProgressDialog.setMessage("Processing...");
        return mProgressDialog;
    default:
        return null;
    }
}

@Override
protected void onPrepareDialog(int id, Dialog dialog) {
    switch(id) {
    case PROGRESS_DIALOG:
        // setup a broadcast receiver to receive update events from the long running process
        IntentFilter filter = new IntentFilter();
        filter.addAction(MyService.BG_PROCESS_INTENT);
        registerReceiver(new MyBroadcastReceiver(), filter);
        break;
    }
}

public class MyBroadcastReceiver extends BroadcastReceiver{
    @Override
    public void onReceive(Context context, Intent intent) {
        if (intent.hasExtra(MyService.KEY_COUNTER)){
            int count = intent.getIntExtra(MyService.KEY_COUNTER, 0);
            mProgressDialog.setProgress(count);
            if (count >= MyService.MAX_COUNTER){
                dismissDialog(PROGRESS_DIALOG);
            }
        }
    }
}

/*
 * Sticky broadcasts persist and any prior broadcast will trigger in the 
 * broadcast receiver as soon as it is registered.
 * To clear any prior broadcast this code sends a blank broadcast to clear 
 * the last sticky broadcast.
 * This broadcast has no extras it will be ignored in the broadcast receiver 
 * setup in onPrepareDialog()
 */
private void clearPriorBroadcast(){
    Intent broadcastIntent = new Intent();
    broadcastIntent.setAction(MyService.BG_PROCESS_INTENT);
    sendStickyBroadcast(broadcastIntent);
}}

IntentService经济舱:

public class MyService extends IntentService {

public static final String BG_PROCESS_INTENT = "com.mindspiker.Tester.MyService.TEST";
public static final String KEY_COUNTER = "counter";
public static final int MAX_COUNTER = 100;

public MyService() {
  super("");
}

@Override
protected void onHandleIntent(Intent intent) {
    for (int i = 0; i <= MAX_COUNTER; i++) {
        Log.e("Service Example", " " + i);
        try {
            Thread.sleep(100);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }

        Intent broadcastIntent = new Intent();
        broadcastIntent.setAction(BG_PROCESS_INTENT);
        broadcastIntent.putExtra(KEY_COUNTER, i);
        sendStickyBroadcast(broadcastIntent);
    }
}}

清单文件条目:

应用前部分:

uses-permission android:name="com.mindspiker.Tester.MyService.TEST"
uses-permission android:name="android.permission.BROADCAST_STICKY"

应用程序内部部分

service android:name=".MyService"

我也遇到了同样的问题,我想出了一个不使用ProgressDialog的解决方案,我得到了更快的结果。

我所做的是创建一个布局,其中有一个ProgressBar。

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent">
<ProgressBar
    android:id="@+id/progressImage"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_centerInParent="true"
    />
</RelativeLayout>

然后在onCreate方法中执行以下操作

public void onCreate(Bundle icicle) {
    super.onCreate(icicle);
    setContentView(R.layout.progress);
}

然后在线程中执行长任务,完成后使用Runnable将内容视图设置为您想要用于此活动的实际布局。

例如:

mHandler.post(new Runnable(){

public void run() {
        setContentView(R.layout.my_layout);
    } 
});

这就是我所做的,我发现它比显示ProgressDialog运行得更快,在我看来,它的侵入性更小,外观更好。

然而,如果你想要使用ProgressDialog,那么这个答案不适合你。

诀窍是在onPreExecute/onPostExecute期间像往常一样在AsyncTask中显示/解散对话框,尽管在方向改变的情况下,在活动中创建/显示一个对话框的新实例,并将其引用传递给任务。

public class MainActivity extends Activity {
    private Button mButton;
    private MyTask mTask = null;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        MyTask task = (MyTask) getLastNonConfigurationInstance();
        if(task != null){
            mTask = task;
            mTask.mContext = this;
            mTask.mDialog = ProgressDialog.show(this, "", "", true);        
        }

        mButton = (Button) findViewById(R.id.button1);
        mButton.setOnClickListener(new View.OnClickListener(){
            public void onClick(View v){
                mTask = new MyTask(MainActivity.this);
                mTask.execute();
            }
        });
    }


    @Override
    public Object onRetainNonConfigurationInstance() {
        String str = "null";
        if(mTask != null){
            str = mTask.toString();
            mTask.mDialog.dismiss();
        }
        Toast.makeText(this, str, Toast.LENGTH_SHORT).show();
        return mTask;
    }



    private class MyTask extends AsyncTask<Void, Void, Void>{
        private ProgressDialog mDialog;
        private MainActivity mContext;


        public MyTask(MainActivity context){
            super();
            mContext = context;
        }


        protected void onPreExecute() {
            mDialog = ProgressDialog.show(MainActivity.this, "", "", true);
        }

        protected void onPostExecute(Void result) {
            mContext.mTask = null;
            mDialog.dismiss();
        }


        @Override
        protected Void doInBackground(Void... params) {
            SystemClock.sleep(5000);
            return null;
        }       
    }
}

看起来太“快速和肮脏”了,所以请指出缺点,但我发现有用的是……

在我的AsyncTask的onPostExecute方法中,我简单地包装了`。try/catch块中的进度对话框(带有空捕获)的Dismiss ',然后简单地忽略所引发的异常。似乎是错误的,但似乎没有不良影响(至少对于我随后所做的事情,这是启动另一个活动,将我的长时间运行查询的结果传递为一个额外)